Worksheetsunit 8 1 sample review
Total questions: 83
Worksheet time: 7hrs 1mins
Suppose the P-value for a hypothesis test is 0.0304. Using a = 0.05, what is the appropriate conclusion?
a) Reject the null hypothesis
b) Reject the alternative hypothesis
c) Fail to reject the null hypothesis
d) Fail to reject the alternative hypothesis
When p-value is greater than alpha we:
Reject Ho
Fail to reject Ha
Fail to reject Ho
Reject Ha
Ha = 18.4
Ha > 18.4
Ha < 18.4
Ha ≠ 18.4
Ha = 47
Ha < 47
Ha > 47
Ha ≠ 47
The null and alternative hypothesis can be the same.
Yes
No
Maybe
All the above
Identify the correct null hypothesis:
Is the proportion of babies born male different from 50%? In a sample of 200 babies, 96 were male. Test the claim using a level of significance of 1%.
H0: p = 0.50
H0: µ = 100
H0: p = 0.48
H0: µ = 96
H0: μ = k
H1: μ ≠ k
Left-tailed test
Two-tailed test
Right-tailed test
H0: μ = k
H1: μ > k
Left-tailed test
Right-tailed test
In a random sample of 1000 adult Americans, only 430 could name at least one justice who is currently serving on the US Supreme Court. A claim is that fewer than half of adult Americans can name at least one justice who is currently serving on the US Supreme Court. State the null hypothesis.
Ho: p <.5, where p is the true proportion of Americans who can name one justice currently serving.
Ho:p >.5 where p is the true proportion of Americans who can name one justice currently serving.
Ho:p =.5 where p is the true proportion of Americans who can name one justice currently serving.
In a random sample of 1000 adult Americans, only 430 could name at least one justice who is currently serving on the US Supreme Court. A claim is that fewer than half of adult Americans can name at least one justice who is currently serving on the US Supreme Court. State the alternative hypothesis.
Ha: p=.5, where p is the true proportion of Americans who can name one justice currently serving.
Ha: p>.5, where p is the true proportion of Americans who can name one justice currently serving.
Ha: p<.5, where p is the true proportion of Americans who can name one justice currently serving.
In a national survey of 2013 adults, 1283 indicated that they believe rudeness is a more serious problem than in years past. Does this indicate that more than 3/4 of American adults believe rudeness is a worsening problem? State the alternative hypothesis.
Ha: p > .75, where p is the true proportion of Americans who believe rudeness is worsening.
Ha: p = .75, where p is the true proportion of Americans who believe rudeness is worsening.
Ha: p <.75, where p is the true proportion of Americans who believe rudeness is worsening.
In a national survey of 2013 adults, 1283 indicated that they believe rudeness is a more serious problem than in years past. Does this indicate that more than 3/4 of American adults believe rudeness is a worsening problem? State the null hypothesis.
Ho: p > .75, where p is the true proportion of Americans who believe rudeness is worsening.
Ho: p = .75, where p is the true proportion of Americans who believe rudeness is worsening.
Ho: p < .75, where p is the true proportion of Americans who believe rudeness is worsening.
The Associated Press found that 730 of 1000 randomly selected adults preferred to watch movies at home rather than at a movie theater. Is there convincing evidence that the majority of adult Americans prefer watching movies at home? State the alternative hypothesis.
Ha: p = .50, where p is the true proportion of adult Americans who prefer watching movies at home.
Ha: p < .50, where p is the true proportion of adult Americans who prefer watching movies at home.
Ha: p > .50, where p is the true proportion of adult Americans who prefer watching movies at home.
In a survey of 526 US businesses, 400 indicated that they monitor employee's web site visits. Is there sufficient evidence that more than 70% of US businesses monitor employees' web site visits? State the null hypothesis.
Ho: p = .70, where p is the true proportion of US businesses that indicated they monitor employee web sites.
Ho: p < .70, where p is the true proportion of US businesses that indicated they monitor employee web sites.
Ho: p > .70, where p is the true proportion of US businesses that indicated they monitor employee web sites.
In a random sample of 1000 adult Americans, 700 indicated that they oppose the reinstatement of a military draft. Is there convincing evidence that the proportion of American adults who oppose the reinstatement of the draft is different from two-thirds? State the null hypothesis.
Ho: p < 2/3, where p is the true proportion of American adults who oppose the reinstatement of the draft.
Ho: p > 2/3, where p is the true proportion of American adults who oppose the reinstatement of the draft.
Ho: p = 2/3, where p is the true proportion of American adults who oppose the reinstatement of the draft.
Suppose the P-value for a hypothesis test is 0.0304. Using a = 0.05, what is the appropriate conclusion?
a) Reject the null hypothesis
b) Reject the alternative hypothesis
c) Fail to reject the null hypothesis
d) Fail to reject the alternative hypothesis
When p-value is greater than alpha we:
Reject Ho
Fail to reject Ha
Fail to reject Ho
Reject Ha
The null and alternative hypothesis can be the same.
Yes
No
Maybe
All the above
H0: μ = k
H1: μ ≠ k
Left-tailed test
Two-tailed test
Right-tailed test
H0: μ = k
H1: μ > k
Left-tailed test
Right-tailed test
A __________ occurs if you accept the null hypothesis when it is false.
Type I error
Type II error
A __________ occurs if you reject the null hypothesis when it is true.
Type I error
Type II error
What is the 5 steps procedure for hypothesis testing?
1) State the hypotheses and identify the claim
2) Find the critical value
3) Compute the test value
4) Summarize the results
5) Make the decision (reject or not reject)
1) State the hypotheses and identify the claim
2) Compute the test value
3) Find the critical value
4) Make the decision (reject or not reject)
5) Summarize the results
1) State the hypotheses and identify the claim
2) Find the critical value
3) Compute the test value
4) Make the decision (reject or not reject)
5) Summarize the results
A manufacturer claims that his tires last at least 40,000
miles. A test on 25 tires reveals that the mean life of a tire
is 39,750 miles, with a standard deviation of 387 miles.
Test the Manufacturer’s claim at α = .01.
Reject Ho
Reject Ha
Fail to reject Ho
Fail to reject Ha
In performing a hypothesis test where the null
hypothesis is that the μ = 6.9. A random sample of 16
items is selected. The sample mean is 7.1 and the sample
standard deviation is 2.4. It can be assumed that the
population is normally distributed at α = .05.
Reject Ho
Reject Ha
Fail to reject Ho
Fail to reject Ha
A fast food outlet claims that the mean waiting time in
line is less than 1.9 minutes. A random sample of 20
customers has a mean of 1.7 minutes with a standard
deviation of 0.8 minute. If α = 0.05, test the fast food
outlet's claim using P-values.
Reject Ho
Reject Ha
Fail to reject Ho
Fail to reject Ha
A fast food outlet claims that the mean waiting time in
line is less than 3.5 minutes. A random sample of 20
customers has a mean of 3.7 minutes with a standard
deviation of 0.8 minute. If α = 0.05, test the fast food
outlet's claim.
Reject Ho
Reject Ha
Fail to reject Ho
Fail to reject Ha
It is said that 60% of families own a pet. Of a sample of 95 families, 70 owned pets. Perform a hypothesis test to determine whether the percent of families who own pets is different than 60%. Use a α=0.01 level of significance.
H0: P=60
H1: P=60
H0: P=0.60
H1: P=0.60
H0: μ=60
H1: μ=60
H0: μ≥60
H1: μ≤60
It is said that 60% of families own a pet. Of a sample of 95 families, 70 owned pets. Perform a hypothesis test to determine whether the percent of families who own pets is different than 60%. Use a α=0.01 level of significance.
What type of test would you need to run for this?
Z Test
T Test
1-Prop Z Test
X2 Test
It is said that 60% of families own a pet. Of a sample of 95 families, 70 owned pets. Perform a hypothesis test to determine whether the percent of families who own pets is different than 60%. Use a α=0.01 level of significance.
What is the p-value? Round to 4 decimal places.
(a)
It is said that 60% of families own a pet. Of a sample of 95 families, 70 owned pets. Perform a hypothesis test to determine whether the percent of families who own pets is different than 60%. Use a α=0.01 level of significance.
Reject the Null
Fail to Reject the Null
Accept the Null
It is said that 60% of families own a pet. Of a sample of 95 families, 70 owned pets. Perform a hypothesis test to determine whether the percent of families who own pets is different than 60%. Use a α=0.01 level of significance.
What is the conclusion statement?
There is enough evidence to reject the claim that the percent of families who own pets is different than 60%
There is not enough evidence to support the claim that the percent of families who own pets is 60%
There is enough evidence to support the claim that the percent of families who own pets is different than 60%
There is not enough evidence to support the claim that the percent of families who own pets is different than 60%
A recruiter for the Super Teachers School Board advertised that the average teacher's salary in a certain competing district is less than what his district offers, $50,000. A random sample of 50 teachers from the competing district had a mean annual salary of $48,300. The population standard deviation is known to be $8,000. Use a 0.01 level of significance to test the recruiter's claim.
Choose the correct Null and Alternate Hypothesis Statements.
H0: μ=48,300 H1: μ>48,300
H0: μ=50,000 H1: μ>50,000
H0: μ=48,300 H1: μ<48,300
H0: μ=50,000 H1: μ<50,000
A recruiter for the Super Teachers School Board advertised that the average teacher's salary in a certain competing district is less than what his district offers, $50,000. A random sample of 50 teachers from the competing district had a mean annual salary of $48,300. The population standard deviation is known to be $8,000. Use a 0.01 level of significance to test the recruiter's claim.
What type of test should you run?
Z test
T test
1-Prop Z test
X2 test
A recruiter for the Super Teachers School Board advertised that the average teacher's salary in a certain competing district is less than what his district offers, $50,000. A random sample of 50 teachers from the competing district had a mean annual salary of $48,300. The population standard deviation is known to be $8,000. Use a 0.01 level of significance to test the recruiter's claim.
What is the p-value? Round to 4 decimal places!!
(a)
A recruiter for the Super Teachers School Board advertised that the average teacher's salary in a certain competing district is less than what his district offers, $50,000. A random sample of 50 teachers from the competing district had a mean annual salary of $48,300. The population standard deviation is known to be $8,000. Use a 0.01 level of significance to test the recruiter's claim.
What is your decision?
Reject the Null
Fail to Reject the Null
Accept the Null
A recruiter for the Super Teachers School Board advertised that the average teacher's salary in a certain competing district is less than what his district offers, $50,000. A random sample of 50 teachers from the competing district had a mean annual salary of $48,300. The population standard deviation is known to be $8,000. Use a 0.01 level of significance to test the recruiter's claim.
Choose the correct conclusion.
There is enough evidence to support the claim that the average teacher's salary in the competing district is less than $50,000.
There is not enough evidence to support the claim that the average teacher's salary in the competing district is less than $50,000.
There is enough evidence to support the claim that the average teacher's salary in the competing district is more than $50,000.
There is not enough evidence to support the claim that the average teacher's salary in the competing district is more than $50,000.
Environmental advocates believe that there is too much Mercury in a town's lake. To test their claim, they took 7 samples of water from the lake and measured the concentration of mercury, in milligrams per cubic meter, in each sample. Assume the population distribution is normal. The sample results were:
1.02, 1.23, 0.91, 1.29, 1.01, 1.35, 1.43
Perform a hypothesis test to determine if the mean concentration of mercury is greater than 1 milligram per cubic meter. Use a 0.05 level of significance.
Choose the correct null and alternate hypothesis statements.
H0: μ=1 H1: μ>1
H0: μ<1 H1: μ>1
H0: μ=1 H1: μ<1
H0: μ>1 H1: μ<1
Environmental advocates believe that there is too much Mercury in a town's lake. To test their claim, they took 7 samples of water from the lake and measured the concentration of mercury, in milligrams per cubic meter, in each sample. Assume the population distribution is normal. The sample results were:
1.02, 1.23, 0.91, 1.29, 1.01, 1.35, 1.43
Perform a hypothesis test to determine if the mean concentration of mercury is greater than 1 milligram per cubic meter. Use a 0.05 level of significance.
What type of test should you run?
Z test
T test
1-Prop Z test
X2 test
Environmental advocates believe that there is too much Mercury in a town's lake. To test their claim, they took 7 samples of water from the lake and measured the concentration of mercury, in milligrams per cubic meter, in each sample. Assume the population distribution is normal. The sample results were:
1.02, 1.23, 0.91, 1.29, 1.01, 1.35, 1.43
Perform a hypothesis test to determine if the mean concentration of mercury is greater than 1 milligram per cubic meter. Use a 0.05 level of significance.
What is the p-value. Round to 4 decimal places.
(a)
Environmental advocates believe that there is too much Mercury in a town's lake. To test their claim, they took 7 samples of water from the lake and measured the concentration of mercury, in milligrams per cubic meter, in each sample. Assume the population distribution is normal. The sample results were:
1.02, 1.23, 0.91, 1.29, 1.01, 1.35, 1.43
Perform a hypothesis test to determine if the mean concentration of mercury is greater than 1 milligram per cubic meter. Use a 0.05 level of significance.
What is your decision?
Reject the Null
Fail to Reject the Null
Accept the Null
Environmental advocates believe that there is too much Mercury in a town's lake. To test their claim, they took 7 samples of water from the lake and measured the concentration of mercury, in milligrams per cubic meter, in each sample. Assume the population distribution is normal. The sample results were:
1.02, 1.23, 0.91, 1.29, 1.01, 1.35, 1.43
Perform a hypothesis test to determine if the mean concentration of mercury is greater than 1 milligram per cubic meter. Use a 0.05 level of significance.
Choose the correct conclusion statement
There is not enough evidence to conclude that the mean concentration of mercury in the town lake is greater than 1 milligram.
There is not enough evidence to conclude that the mean concentration of mercury in the town lake is less than 1 milligram.
There is enough evidence to conclude that the mean concentration of mercury in the town lake is less than 1 milligram.
There is enough evidence to conclude that the mean concentration of mercury in the town lake is greater than 1 milligram.
Find the P-value and make a decision based on the given z-score and level of significance. Right tailed, z=1.98, α =0.05.
P=0.239; Reject Ho
P=0.239; Fail to reject Ho
P=0.123; Reject Ho
P=0.123; Fail to reject Ho
Find the critical value given the sample size and level of significance. Two-tailed, n=14, α =0.01
t*=-2.345 and t*=2.345
t*=-3.012 and t*=3.012
t*=3.012
t*=-1.645 and t*=1.645
A citrus grower's association believes that the mean consumption of fresh citrus fruits by families in the U.S. is at least 98 pounds per year. A random sample of 13 families in the US has a mean consumption of 89.5 pounds per year with a standard deviation of 11 pounds. Test the validity of this claim at α=0.01. Calculate t to the hundredths place. t= (a)
A citrus grower's association believes that the mean consumption of fresh citrus fruits by families in the U.S. is at least 98 pounds per year. A random sample of 13 families in the US has a mean consumption of 89.5 pounds per year with a standard deviation of 11 pounds. Test the validity of this claim at α =0.01. (Use your t from the last question.) What is the correct decision and conclusion?
Reject Ho . There is sufficient evidence to indicate that the average consumption of fresh citrus fruit by families in the US is at least 98 per year.
Reject Ho . There is not sufficient evidence to indicate that the average consumption of fresh citrus fruit by families in the US is at least 98 per year.
Fail to reject Ho . There is sufficient evidence to indicate that the average consumption of fresh citrus fruit by families in the US is at least 98 per year.
Fail to reject Ho . There is not sufficient evidence to indicate that the average consumption of fresh citrus fruit by families in the US is at least 98 per year.
Is this a z-test or t-test?
An auto maker estimates that the mean gas mileage of its luxury sedan is at least 25 miles per gallon. A random sample of eight such cars had a mean of 23 miles per gallon. The United Autoworkers have studied all cars of this type and found that the population standard deviation is 5 miles per gallon. Test the validity of this claim at α =0.05.
z-test
t-test
Calculate the P value.
An auto maker estimates that the mean gas mileage of its luxury sedan is at least 25 miles per gallon. A random sample of eight such cars had a mean of 23 miles per gallon. The United Autoworkers have studied all cars of this type and found that the population standard deviation is 5 miles per gallon. Test the validity of this claim at α =0.05.
P=.1786
P=.897
P=.5698
P=.1292
Make a decision if P=.1292.
An auto maker estimates that the mean gas mileage of its luxury sedan is at least 25 miles per gallon. A random sample of eight such cars had a mean of 23 miles per gallon. The United Autoworkers have studied all cars of this type and found that the population standard deviation is 5 miles per gallon. Test the validity of this claim at α =0.05.
Fail to reject Ho
Reject Ho
Write a conclusion.
An auto maker estimates that the mean gas mileage of its luxury sedan is at least 25 miles per gallon. A random sample of eight such cars had a mean of 23 miles per gallon. The United Autoworkers have studied all cars of this type and found that the population standard deviation is 5 miles per gallon. Test the validity of this claim at α =0.05.
Since P=.1292 is greater than α =0.05, we must reject Ho . There is sufficient evidence to indicate that the average gas mileage for this luxury sedan is at least 25 mpg.
Since P=.1292 is greater than α =0.05, we must reject Ho . There is not sufficient evidence to indicate that the average gas mileage for this luxury sedan is at least 25 mpg.
Since P=.1292 is greater than α =0.05, we must fail to reject Ho . There is sufficient evidence to indicate that the average gas mileage for this luxury sedan is at least 25 mpg.
Since P=.1292 is greater than α =0.05, we must fail to reject Ho . There is not sufficient evidence to indicate that the average gas mileage for this luxury sedan is at least 25 mpg.
What is the difference between the way the t-test and the z-test work in this chapter?
The difference is in the way you make a decision.
The difference is in the way you write the null and alternate hypothesis.
The difference is in the way you find the sample mean.
Contrast how you make a decision in the z-test versus making a decision in the t-test.
What is a one-sample t-test used for?
Comparing means from a sample and a population
Comparing means from two separate samples
Comparing means from two related samples
Comparing means from more than two samples
Claim: The average weight of males is greater than 53 kg. Ten male students were selected to test this claim.We also set our α=0.01, x=51, s=4.74, n=10, df=10−1=9
Step 1: What is the null hypothesis?
Ho: μ=53
Ho: μ>53
Ho: μ=53
Ho: μ≤53
Claim: The average weight of males is greater than 53 kg. Ten male students were selected to test this claim.We also set our α=0.01, x=51, s=4.74, n=10, df=10−1=9
Step 1: What is the alternative hypothesis?
Ha: μ=53
Ha: μ>53
Ha: μ=53
Ha: μ≤53
Claim: The average weight of males is greater than 53 kg. Ten male students were selected to test this claim.We also set our ⍺ = 0.01. α=0.01, x=51, s=4.74, n=10, df=10−1=9
Using the formula, compute for the test value.
Step 3: What is the test value or computed value?
t=−1.33
t=1.33
t=−1.27
t=1.27
Claim: The average weight of males is greater than 53 kg. Ten male students were selected to test this claim.We also set our ⍺ = 0.01. α=0.01, x=51, s=4.74, n=10, df=10−1=9
Step 5: Draw conclusion
There is no significant difference between the sample and population mean. Thus the claim that the average weight of males is greater than 53 kg is incorrect.
There is no significant difference between the sample and population mean. Thus the claim that the average weight of males is greater than 53 kg is correct.
There is a significant difference between the sample and population mean. Thus the claim that the average weight of males is greater than 53 kg is incorrect.
There is a significant difference between the sample and population mean. Thus the claim that the average weight of males is greater than 53 kg is correct.
When testing with α=0.01 you get p=0.12 . Your decision should be
Reject H0 , there is a significant difference
Acceptundefined, there is NOT a significant difference
Rejectundefined, there is NOT a significant difference
Acceptundefined, there is a significant difference
A manufacturer claims that his tires last at least 40,000
miles. A test on 25 tires reveals that the mean life of a tire
is 39,750 miles, with a standard deviation of 387 miles.
Test the Manufacturer’s claim at α = .01.
Reject Ho
Reject Ha
Fail to reject Ho
Fail to reject Ha
A one sample t-test is conducted on Ho : μ = 81.6. The
sample has a sample mean = 84.1 , s = 3.1, n = 25, and α =
.01.
There is enough evidence to reject the claim
There is not enough evidence to reject the claim
There is enough evidence to support the claim
There is not enough evidence to support the claim
This symbol denotes the null hypothesis
Null hypothesis
Alternative Hypothesis
H0
Ha
This symbol denotes the alternative hypothesis
H1
Both Ha and H1
H0
Ha
Which of the following is NOT an option for an alternate hypothesis?
Ha = k
Ha > k
Ha < k
Ha ≠ k
Find the null and alternative hypothesis.
The standard deviation of the sale price of a bike is no
more than $225.
H0: σ=225
H1: σ<225
H0: σ=225 H1: σ<225
H0: σ=225 H1: σ>225
H0: σ=225 H1: σ>225
Find the null and alternative hypothesis.
A microwave manufacturer claims that the mean life of the thermostat for a certain model of microwave is more than 4 years.
H0: μ=4
H1: μ>4
H0: μ=4 H1: μ<4
H0: μ=4 H1: μ>4
H0: μ=4 H1: μ<4
Which of the following symbols can be in the ALTERNATIVE hypothesis? (Check all that apply)
=
>
=
≥
<
Identify whether the following is a null hypothesis or an alternative hypothesis.
The average age of grade eleven students is 17 years old.
Null Hypothesis
Alternative Hypothesis
Identify whether the following is a null hypothesis or an alternative hypothesis.
The mean weight of newborn babies is 0.5 kg.
Null Hypothesis
Alternative Hypothesis
