$$\frac{\text{sin }x}{\text{cos x}}$$

$$\frac{\text{cos }x}{\text{sin x}}$$

$$\sin^2x\ +\cos^2x$$

$$\tan x\ .\cot x$$

$$\tan^2x\ +\cos^2x$$

$$\tan x\ +\cot x$$

$$\frac{1}{\cos^2x}$$

$$\frac{1}{\sin^2x}$$

$$\frac{1}{\cos^2x}$$

$$\frac{1}{\sin^2x}$$

sina.cosb + cosa.sinb

sina.cosb - cosa.sinb

cosa.cosb - sina.sinb

cosa.cosb + sina.sinb

sina.cosb + cosa.sinb

sina.cosb - cosa.sinb

cosa.cosb - sina.sinb

cosa.cosb + sina.sinb

sina.cosb + cosa.sinb

sina.cosb - cosa.sinb

cosa.cosb - sina.sinb

cosa.cosb + sina.sinb

sina.cosb + cosa.sinb

sina.cosb - cosa.sinb

cosa.cosb - sina.sinb

cosa.cosb + sina.sinb

$$\frac{\tan a+\tan b}{1-\tan a.\tan b}$$

$$\frac{\tan a-\tan b}{1+\tan a.\tan b}$$

$$\frac{\tan a.\tan b}{1-\tan a+\tan b}$$

$$\frac{\tan a.\tan b}{1+\tan a+\tan b}$$

$$\frac{\tan a+\tan b}{1-\tan a.\tan b}$$

$$\frac{\tan a-\tan b}{1+\tan a.\tan b}$$

$$\frac{\tan a.\tan b}{1-\tan a+\tan b}$$

$$\frac{\tan a.\tan b}{1+\tan a+\tan b}$$

$$\frac{2\tan x}{1-\tan^2x}$$

$$\frac{1-\cos2a}{2}$$

$$\frac{1+\cos2a}{2}$$

$$\frac{1-\cos2a}{1+\cos2a}$$

$$\frac{2\tan x}{1-\tan^2x}$$

$$\frac{1-\cos2a}{2}$$

$$\frac{1+\cos2a}{2}$$

$$\frac{1-\cos2a}{1+\cos2a}$$

$$\frac{2\tan x}{1-\tan^2x}$$

$$\frac{1-\cos2a}{2}$$

$$\frac{1+\cos2a}{2}$$

$$\frac{1-\cos2a}{1+\cos2a}$$

$$\frac{1-\cos2a}{2}$$

$$\frac{2\tan x}{1-\tan^2x}$$

$$\frac{1+\cos2a}{2}$$

$$\frac{1-\cos2a}{1+\cos2a}$$

$$2\sin\left(\frac{a+b}{2}\right).\cos\left(\frac{a-b}{2}\right)$$

$$2\cos\left(\frac{a+b}{2}\right).\sin\left(\frac{a-b}{2}\right)$$

$$2\cos\left(\frac{a+b}{2}\right).\cos\left(\frac{a-b}{2}\right)$$

$$-2\sin\left(\frac{a+b}{2}\right).\sin\left(\frac{a-b}{2}\right)$$

$$2\sin\left(\frac{a+b}{2}\right).\cos\left(\frac{a-b}{2}\right)$$

$$2\cos\left(\frac{a+b}{2}\right).\sin\left(\frac{a-b}{2}\right)$$

$$2\cos\left(\frac{a+b}{2}\right).\cos\left(\frac{a-b}{2}\right)$$

$$-2\sin\left(\frac{a+b}{2}\right).\sin\left(\frac{a-b}{2}\right)$$

$$2\sin\left(\frac{a+b}{2}\right).\cos\left(\frac{a-b}{2}\right)$$

$$2\cos\left(\frac{a+b}{2}\right).\sin\left(\frac{a-b}{2}\right)$$

$$2\cos\left(\frac{a+b}{2}\right).\cos\left(\frac{a-b}{2}\right)$$

$$-2\sin\left(\frac{a+b}{2}\right).\sin\left(\frac{a-b}{2}\right)$$

$$2\sin\left(\frac{a+b}{2}\right).\cos\left(\frac{a-b}{2}\right)$$

$$2\cos\left(\frac{a+b}{2}\right).\sin\left(\frac{a-b}{2}\right)$$

$$2\cos\left(\frac{a+b}{2}\right).\cos\left(\frac{a-b}{2}\right)$$

$$-2\sin\left(\frac{a+b}{2}\right).\sin\left(\frac{a-b}{2}\right)$$

$$\frac{1}{2}\left(\cos\left(a+b\right)+\cos\left(a-b\right)\right)$$

$$\frac{1}{2}\left(\sin\left(a+b\right)+\sin\left(a-b\right)\right)$$

$$\frac{-1}{2}\left(\cos\left(a+b\right)-\cos\left(a-b\right)\right)$$

$$\frac{1}{2}\left(\cos\left(a+b\right)+\cos\left(a-b\right)\right)$$

$$\frac{1}{2}\left(\sin\left(a+b\right)+\sin\left(a-b\right)\right)$$

$$\frac{-1}{2}\left(\cos\left(a+b\right)-\cos\left(a-b\right)\right)$$

$$\frac{1}{2}\left(\cos\left(a+b\right)+\cos\left(a-b\right)\right)$$

$$\frac{1}{2}\left(\sin\left(a+b\right)+\sin\left(a-b\right)\right)$$

$$\frac{-1}{2}\left(\cos\left(a+b\right)-\cos\left(a-b\right)\right)$$

u=v +k2π

u=π-v +k2π

u= -v +k2π

u=v +k2π

u=π-v +k2π

u= -v +k2π

u=v +kπ

u=π-v +k2π

u= -v +k2π

u=v +kπ

u=π-v +k2π

u= -v +k2π

$$0\le\sin x,\cos x\le1$$

$$-1\le\sin x,\cos x\le1$$

$$-1\le\sin x,\cos x\le0$$

$$-1\le\sin^2x,\cos^2x\le0$$

$$-1\le\sin^2x,\cos^2x\le1$$

$$0\le\sin^2x,\cos^2x\le1$$

$$-1\le\left|\sin x\right|,\left|\cos x\right|\le0$$

$$-1\le\left|\sin x\right|,\left|\cos x\right|\le1$$

$$0\le\left|\sin x\right|,\left|\cos x\right|\le1$$

+) asinu +/- bcosu =c

+) asinu +/- bcosu =c.sinu+/- d.cosu

+) a.sinu +/- b.cosu =c.sinu

+) a.sinu +/- b.cosu =c.sinv +/- d.cosv

+) asinu +/- bcosu =c

asinu +/- bcosu =c.sinu+/- d.cosu

a.sinu +/- b.cosu =c.sinu

a.sinu +/- b.cosu =c.sinv +/- d.cosv

y=sin (ax+b)

y=cos (ax+b)

y=tan (ax+b)

y=cot (ax+b)

y=cot (ax+b)

y=tan (ax+b)

y=cos (ax+b)

y=sin (ax+b)

+) Chia 2 vế $$\sqrt[]{a^{ }\ +b^{ }}$$ và đặt ẩn cos,sin

(bắt buộc)

+) Chia 2 vế $$\sqrt[]{a^2\ +b^2}$$ và đặt ẩn cos,sin (bắt buộc)

Chia 2 vế $$\sqrt[]{a^{ }\ +b^{ }}$$

+) Chia 2 vế $$\sqrt[]{a^2\ +b^2}$$

+) Chia $$\sqrt[]{a^{ }\ +b^{ }}$$ và đặt ẩn cos,sin

+) Chia $$\sqrt[]{a^2\ +b^2}$$ và đặt ẩn cos,sin

Chia $$\sqrt[]{a^{ }\ +b^{ }}$$

+) Chia $$\sqrt[]{a^2\ +b^2}$$

+) ĐK: $$a^2+b^2\ =c^2+d^2$$

+) ĐK: $$a^2+b^2\ =c^2+d^2$$

$$a^2+b^2\le c^2$$

$$a^2+b^2\ge c^2$$

$$a^2+b^2\ge c^2$$

$$a^2+b^2\le c^2$$

+) ĐK: $$a^2+b^2\ =c^2+d^2$$

+) ĐK: $$a^2+b^2\ =c^2-d^2$$

$$\left(a.b\ \right)^m$$

$$\left(\frac{a}{b}\ \right)^m$$

$$\left(a-b\ \right)^m$$

$$\left(a+b\ \right)^m$$

u_n+1 = u _n +d

u_n= u ₁ +(n-1)d n€N*

S_n=[ ( 2u ₁ +(n-1)d ) ÷2]*n

Sn=[ ( 2u 1 +(n-1)d ) ÷2]*n

u _n+1 =u _n +d

U _n= u ₁ +(n-1)d n€N*

U _n= u ₁ +(n-1)d n€N*

S _n=[ ( 2u ₁+(n-1)d ) ÷2]*n

u _n+1=u _n +d

$$\frac{1}{a^n}$$

aⁿ

$$\frac{1}{a^{-n}}$$

$$a^{m.n}$$

$$a^{m+n}$$

$$a^{\frac{m}{n}}$$

$$a^{m-n}$$

u _n+1=u _n +d

U _n= u ₁ +(n-1)d n€N*

S _n=[ ( 2u ₁+(n-1)d ) ÷2]*n

U_n+1 =U_{1 *}q

U_{n =} U_{1 *q^n-1}

S_n ={ (1 - qⁿ ) *U₁ } ÷ (1-q)

U_n = U₁ *q^n-1

S_n ={ (1 - q_n ) *U₁} ÷ (1-q)

U_n+1=U₁ *q

U_n+2=U₁ *q

S_n ={ (1 - q_n ) *U₁ } ÷ (1-q)

U_n = U₁ *q_n-1

$$a^{m+n}$$

$$a^{m.n}$$

$$a^{\frac{m}{n}}$$

$$a^{m-n}$$

$$a^{m+n}$$

$$a^{m.n}$$

$$a^{\frac{m}{n}}$$

$$a^{m-n}$$