WorksheetsAP Calculus AB Quiz 1 (Part 2) Review
Total questions: 51
Worksheet time: 1hrs 29mins
Find the limit. Hint: Where is the horizontal asymptote?
3/7
0
∞
-∞
Find the limit. Hint: Where is the horizontal asymptote?
-2/9
0
∞
-∞
x→∞lim 4x +12x−3
0
DNE
1/2
2
x→∞lim(2x3+3x−1)=
Hint: Think of the end behavior of an odd and positive polynomial.
∞
−∞
2
2/3
The x→0limf(x) fails to exist because...
As the function approaches zero, left and right of zero do not match
As the function approaches zero, the graph oscillates.
As the function approaches zero, the graph increases without bound.
The x→2limf(x) fails to exist because...
As the function approaches two, left and right of two do not match
As the function approaches two, the graph oscillates.
As the function approaches two, the graph increases or decreases without bound.
The x→0limf(x) fails to exist because...
As the function approaches zero, left and right of zero do not match
As the function approaches zero, the graph oscillates.
As the function approaches zero, the graph increases without bound.
x→−∞lim xcos x
DNE
1
0
−∞
x→∞lim 2xx−cos x
1/2
-1/2
DNE
0
Find the value of x where the function is discontinuous.
(a)
x→∞lim 4x2+3xx+7=...
−∞
∞
21
0
−21
Determine whether f(x)=x−1x2+5x−6 is continuous or discontinuous at x=1.
continuous
discontinuous, removable
discontinuous, jump
discontinuous, essential
x→0lim 5xsin3x
0
5/3
3/5
DNE
x→−∞lim 2x
−∞
+∞
0
2
x→∞lim x5e5x
2/5
∞
0
e/x
What is the limit of h(x) as x approaches -4?
16
4
−4
DNE
Check all the boxes that contain true statements.
x→−2+ limg(x)=−3
x→−2lim g(x) =e−2
x→0−lim g(x)=1
x→0lim g(x)=1
x→−∞lim 3x34=
0
+∞
−∞
DNE
x→+∞lim4x4−2x2+x−15x4−3x3+9=
0
45
+∞
DNE
What is x→−∞lim5x5+7x4−3x2−2x−8?
5
0
−∞
+∞
Which of the following best describes the continuity at x = 5?
Continuous
Removable discontinuity
Non-removable discontinuity
Determine whether the graph of the function has a vertical asymptote or a removeable discontinuity at x = -1.
Vertical Asymptote
Removable Discontinuity
limx→0 sin(6x) ∕ sin(2x)
1/3
3
1
DNE
What value does m have to be in order for the limit as x approaches -4 to exist in the function g(x) = (x^2+8x+m)/(x+4)
18
16
24
-12
Let f be the function defined above where c is a constant. For what value of c, if any is f continuous at x=c ?
6
8
10
There is no such value c
I. f(x) has a least 2 zeros
II. For some c, 2 < c < 9, f(c) = 3
III. The graph of f(x) has a horizontal tangent
Which of the following best describes the continuity at x = -4?
Continuous
Removable Point Discontinuity
Infinite Discontinuity
Jump Discontinuity
Does the following function is continuous at x=0?
Continuous
Discontinuous
Determine whether the graph of the function has a vertical asymptote or a removeable discontinuity at x = -1.
Vertical Asymptote
Removable Discontinuity
TRUE OR FALSE? If f is continuous on [-1,1], f(-1)=4 and f(1)= -2, then there is a zero (a y-value of zero) between -1 and 1.
TRUE
FALSE
CANNOT BE DETERMINED
Which of the following best describes the continuity at x = 5?
Maximum
Minimum
Vertical Asymptote
Hole
Find the vertical asymptotes and holes of
y = (x+3) / ((x-1)(x+3))
Holes: None;
VA: x = 1, -3
Holes: x = -3;
VA: x = 1
Holes: x = -3, 1
VA: None
Holes: x = 1
VA: x = -3
Suppose t is a continuous function containing the ordered pairs shown in the table. On which interval(s) must t attain a value of -2.5? Select all that apply.
(1, 2)
(2, 3)
(3, 4)
(4, 5)
(5, 6)
Suppose h is a continuous function containing the ordered pairs shown in the table. On which interval must h have a zero?
(12.163, 12.164)
(12.164, 12.165)
(12.165, 12.166)
(12.166, 12.168)
True or false? There is a zero on the interval [1,3].
True because the function is continuous and there is a sign change on the interval [1,3]
We cannot be certain since the function is not continuous on the interval [1,3]
False because there is no sign change on the interval [1,3]
False because the graph is not continuous on the interval [1,3]
True or false: If f(x)=x+1∣x+1∣ , then there is a zero on the interval [-2,0].
TRUE because there is a sign change on the interval
FALSE because there is no sign change on the interval
TRUE because of the Intermediate Value Theorem
FALSE because the function is discontinuous on the interval
