Free Printable Unit 9: Worksheet: Boyle's, Charles' Combined

1.

Match the following values with what they represent:

What is the new volume of a gas at 25 degrees Celsius if it occupies 50.2 cm³ at 53 degrees Celsius?

Categorize the following

V1 = ?

T1 = 25 degrees Celsius = 298K

T2 = 53 degrees C = 326 K

Amount is held constant

Pressure is held constant.

V2 = 50.2 cm3

Volume

Temperature

Pressure

Amount

2.

Which equation will we use to solve this problem?

What is the new volume of a gas at 25 degrees Celsius if it occupies 50.2 cm³ at 53 degrees Celsius?

a)

Boyle's Law

P1V1= P2V2

b)

Charles Law:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

c)

Combined Gas Law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

3.

Match the following values:

The volume of Carbon Dioxide gas at 99.3 kPa was measured at 455 cm³.

What will be its volume if the pressure is adjusted to 202.6 kPa?

Categorize the following

P1 = 99.3 kPa

P2 = 202.6 kPa

V1 = 455 cm3

V2 = ?

Temperature is constant.

Amount of gas is constant

Pressure

Volume

Temperature

Amount

4.

Which equation will we use to solve this problem?

The volume of Carbon Dioxide gas at 99.3 kPa was measured at 455 cm³.

What will be its volume if the pressure is adjusted to 202.6 kPa?

a)

Boyle's Law

P1V1= P2V2

b)

Charles Law:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

c)

Combined Gas Law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

5.

At what temperature would a gas at 90.9 kPa of pressure occupy 25.0 cm3 if it occupies 15.0 cm3 at 45 degrees Celsius and 112 kPa?

Categorize the following

T2= 45 celsius = 318K

T1 = ?

P1= 90.9 kPa

V1 = 25.0 cm3

V2 = 15.0 cm3

P2 = 112 kPa

Temperature

Pressure

Volume

What are we solving for?

6.

Which equation will we use to solve this problem?

At what temperature would a gas at 90.9 kPa of pressure occupy 25.0 cm3 if it occupies 15.0 cm3 at 45 degrees Celsius and 112 kPa?

a)

Boyle's Law

P1V1= P2V2

b)

Charles Law:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

c)

Combined Gas Law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

7.

At 1750 cm³ container of ammonia gas is exerting a pressure of 275 kPa while at a temperature of 130 degrees Celsius. Calculate the pressure of this same amount of gas in a 2500 cm³container at a temperature of 27 degrees Celsius.

Categorize the following

T2= 27 C = 300K

T1 = 130 C = 403K

P1= 275 kPa

V1 = 1750 cm3

V2 = 2500 cm3

P2 = ?

Temperature

Pressure

Volume

What are we solving for?

8.

Which equation should we use to solve this problem?

At 1750 cm³ container of ammonia gas is exerting a pressure of 275 kPa while at a temperature of 130 degrees Celsius. Calculate the pressure of this same amount of gas in a 2500 cm³container at a temperature of 27 degrees Celsius.

a)

Boyle's Law

P1V1= P2V2

b)

Charles Law:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

c)

Combined Gas Law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Unit 9: Worksheet: Boyle's, Charles' Combined

Total questions: 8

Worksheet time: 14mins

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