a=1

b=-6

c=7

a=0

b=-6

c=7

a=1

b=6

c=7

a=0

b=6

c=7

Substitute a, b, and c into the equation.

Simplify the radical.

Simplify the fracton.

There is not a next step. The answer is complete.

10, -10

10

10i, -10i

-10

$$\sqrt[]{38},\ -\sqrt[]{38}$$

38, -38

no solution

19

5

-5

5, -5

$$\sqrt[]{5}$$

-10, -4

10, 4

-10i, -4i

10i, 4i

$$-7+\frac{\sqrt[]{40}}{2}$$

$$-7-\frac{\sqrt[]{40}}{2}$$

$$-\frac{14}{2}+\frac{\sqrt[]{40}}{2}$$

$$-\frac{14}{2}-\frac{\sqrt[]{40}}{2}$$

$$-14+\sqrt[]{40}$$

$$-14-\sqrt[]{40}$$

$$-7+\frac{i\ \sqrt[]{40}}{2}$$

$$-7-\frac{i\ \sqrt[]{40}}{2}$$

$$\frac{5}{6}+\frac{\sqrt[]{157}}{6}$$

$$\frac{5}{6}+\frac{\sqrt[]{157}}{6}$$

$$5+\sqrt[]{157}$$

$$5-\sqrt[]{157}$$

$$\frac{5}{2}+\frac{\sqrt[]{157}}{2}$$

$$\frac{5}{2}+\frac{\sqrt[]{157}}{2}$$

$$\frac{5}{6}+\frac{i\ \sqrt[]{157}}{6}$$

$$\frac{5}{6}+\frac{i\ \sqrt[]{157}}{6}$$

$$\frac{b\pm\sqrt[]{b^2-4ac}}{2a}$$

$$\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$$

$$\frac{-b\pm\sqrt[]{b-4ac}}{2a}$$

$$\frac{-b\pm\sqrt[]{b^2-4ac}}{2}$$

-2

-2, 2

2i, -2i

2

$$\frac{7}{10}+\frac{\sqrt[]{89}}{10}$$

$$\frac{7}{10}-\frac{\sqrt[]{89}}{10}$$

$$-\frac{7}{10}+\frac{\sqrt[]{89}}{10}$$

$$-\frac{7}{10}-\frac{\sqrt[]{89}}{10}$$

$$7+\sqrt[]{89}$$

$$7-\sqrt[]{89}$$

$$\frac{7}{10}+\frac{i\ \sqrt[]{89}}{10}$$

$$\frac{7}{10}-\frac{i\ \sqrt[]{89}}{10}$$