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ಸಮಾಂತರ ಶ್ರೇಢಿಯ nನೇ ಪದ ----
an=a+(n+1)
an=a+(n-1)
an=a+(n-1)d
an+(n-1)=d
an=3n+5 ಆದರೆ a5=-----
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ಸಮಾಂತರ ಶ್ರೇಢಿಯ n ಪದಗಳ ಮೊತ್ತ ಕಂಡು ಹಿಡಿಯುವ ಸೂತ್ರ
sn= n2\frac{n}{2}2n (2a+(n-1)d)
sn= n2\frac{n}{2}2n (2a+(n-1)
sn= n2\frac{n}{2}2n (2a+(n+1)d)
sn=(2a+(n-1)d)
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