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En un triángulo ABC recto en B es:
2
3
4
5
1
25°
10°
20°
40°
32\frac{\sqrt[]{3}}{2}23
12\frac{1}{2}21
33\frac{\sqrt[]{3}}{3}33
3\sqrt[]{3}3
34\frac{3}{4}43
35\frac{3}{5}53
43\frac{4}{3}34
45\frac{4}{5}54
si secx=5/4,entonces el cosx es
3/5
4/5
3/4
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