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WorksheetsQuiz on P. D. E 6th semester
Total questions: 153
Worksheet time: 3hrs 29mins
A partial differential equation requires
exactly one independent variable
two or more independent variables
more than one dependent variable
equal number of dependent and independent variables
Using substitution, which of the following equations are solutions to the partial differential equation?
The partial differential equation
is classified as
elliptic
parabolic
hyperbolic
none of the above
The partial differential equation
is classified as
elliptic
parabolic
hyperbolic
none of the above
The complete integral of z=px+qy+f(p,q)
z=px+qy
z=ax+by+f(a,b)
z=f(a,b)
none of the above
What is the order & degree of the p.d.e x2(∂x∂z)2=z(x−y∂y∂z)
1 & 2
2 & 1
2 & 2
none of the above
Singular solution of Partial differential equation can be obtained by
General solution
Complete solution
both a & b
none of the above
The condition of compatibility of partial differential equations f(x,y,z,p,q)=0 , g(x,y,z,p,q)=0 is
∂(p,q)∂(f,g)=0
∂(p,q)∂(f,g)=0
∂(g,q)∂(f,p)=0
∂(g,p)∂(f,q)=0
If u is homogeneous function of order n then ∂x∂u , ∂y∂u both are homogeneous function of order
n
n-1
n+1
n-2
If f(x,y)=0 then what is the value of dxdy is
fyfx
−fyfx
fxfy
−fxfy
1. Find the nature of the one-dimensional wave equation.
Hyperbolic
Parabolic
Elliptic
None of These
The nature of the one-dimensional heat equation is
Circular
Elliptic
Parabolic
Hyperbolic
The nature of PDE 4uxx +3 uxy +3 uyy=0
Parabolic
Hyperbolic
Elliptic
Laplace
The PDE uxx + uyy = 0, is known as
1-D heat equation
1-D wave equation
Laplace equation
None of these
Let PDE uxx + uyy = ut, By method separation, we consider the solution
u(x,y)=X(x)Y(y)
u(x,y,t)=X(x)Y(y)T(t)
u(x,t)=X(x)T(t)
None of these
Let PDE c2(uxx + uyy )= ut, By is known as
2-D heat equation
2-D wave equation
Laplace equation
None of these
Let PDE c2(uxx + uyy )= utt, By is known as
2-D heat equation
2-D wave equation
Laplace equation
None of these
The nature of PDE 4uxx +3 uxy =0
Circular
Elliptic
Hyperbolic
Parabolic
The nature of PDE uxx +4 uxy +3 uyy,=0
Circular
Elliptic
Hyperbolic
Parabolic
A rod of length 10 m has temperature 300 C and 400 C at end points. What is the temperature gradient
10C per cm
30C per cm
20C per cm
None of these
In the steady state, 2-D heat equation reduces to
1-D heat equation
1-D wave equation
Laplace equation
None of these
In the steady state, the change in temperature at any point with respect to time is
00C
>00C
<00C
None of these
The ends A and B of a rod of length10cm are at 300C and 800C at end points until steady state prevails. Then Initial temperature distribution in the rod
10+(5x)/2
30+(5x)/2
30+5x
None of these
The ends A and B of a rod of length20cm are at 300C and 800C at end points until steady state prevails. Then the temperature of the rod at ends are changed to 400C and 600C respectively. Final temperature distribution (i.e. in Steady state) is
40+x
50+x
60+x
70+x
dy/dx = 4x/y. Suppose y(0)=1
The particular solution is
B
C
D
E
The following Differential Equation is
dxdy=xy
Separable.
Non Separable
Is this a Linear Differential equation
Yes
No
Maybe
red
Solve the following differential equations:
dxdy=ex
1=ex+C
y=2ex+C
y=ex+C
0=ex+C
Which functions below will have the same slope field? (choose all that apply)
y = x2 - 3
y = x2 + 4
y = 2x - 5
y = 2x2
In drawing the slope field for the differential equation , I would place short slope lines of _________ at the points (0,1), (1,-1), and (2,-2)
dxdy=2x−3y
Select all that apply
-3
-1
2
5
10
y is proportional to the product of z and the square root of x
y=zx2
y=kzx2
y=kzx
y=zkx
The degree of a differential equation is define by a
Positive real number
Positive rational number
Positive integer
All the above
Solution of a linear differential equation of first order can be obtain by
multiplying on both the sides by its integrating factor.
adding on both the sides by integrating factor.
subtracting integrating factor from both sides
None of the above
The complete solution of Linear Differential equations involves
complete function + particular integral
complementary function + particular integral
complementary function + definite integral
complete function + indefinite integral
The particular integral of the equation (D−1)y=e3x is
2e3x
2e−3x
4e3x
2ex
The C.F. of the equation (D2−9)y=e−3x+1+e3x is
c1e−3x+c2e−x
c1e3x+c2e3x
c1e3x+c2e−x
c1e3x+c2e−3x
Choose the right description for the given differential equation
Ordinary, 2nd order, degree 2, non linear
Partial, 1st order, degree 2, linear.
Ordinary, 1st order, degree 2, linear
Partial, 2nd order, degree 1, non linear
Number of arbitrary constant in the general solution of a differential equation of degree 3 and order 4 is
3
4
0
43
dy2d2x+6dydx−5y=0
The general solution to the DE is,
y=Aex+Be5x
y=Ae−x+Be−5x
y=Ae(−3+14)x+Be(−3−14)x
y=Acos(−3+14)x+Bsin(−3−14)x
Find a solution for y if dy/dx = 2x√y and y = 4 when x = 3.
2√y = x2 + C
y = (x2 + 25)2/4
y = x4/4
y = ¼(x2 - 5)2
Which of the following equations solves dy/dt = ky?
y = y0ekt
y = mx + b
y = a(x - h)2 + k
y = Asin[B(x - C)] + D
2. Solve the differential equation
𝑑𝑦/𝑑𝑡 =3𝑡2/𝑦 with initial condition
𝑦(2) = 0.
y=ln∣15t∣
y=16t3
y = 2t3−16
y=2t3−16
A PDE consists of
only one independent variable
more than one independent variable
more than one dependent varible
The highest derivative in the given pde is called
order
degree
The degree of the following pde (∂x∂z )2+2(∂x∂y∂2z)+(∂y∂z)2=0 is
2
0
1
The order of the following pde (zxx)2+(zxyy)+(zyy)=sinz is
1
2
3
The expansion for s
∂y2∂2z
∂x2∂2z
∂x∂y∂2z
If the number of arbitrary constants is less than or equal to number of independent variables then the pde obtained is of order
>1
=1
<1
If the number of arbitrary function is n then the pde obtained is of order
<n
>n
=n
1
The complete integral is defined as
The number of arbitrary constants < The number of independent variables
The number of arbitrary constants = The number of independent variables
The number of arbitrary constants > The number of independent variables
Giving particular values for arbitrary constants in the complete integral is called
Particular solution
General solution
Singular solution
which of the following has the trial solution z=ax+by+c
z=px+qy+p2
p+q=pq
p(1+q)=qz
Which of the following is clairaut's form
z=px+qy+pq
p+q=1
p+q=x+y
The complete integral of F1(x,p)=F2(y,q) is
z=∫qdx+∫pdy
z=∫pdx−∫qdy
z=∫pdx+∫qdy
The subsidiary equation for Lagrange's linear equation
xdx=ydy=zdz
pdx=qdy=rdz
Pdx=Qdy=Rdz
The multipliers for x(y−z)p+y(z−x)q=z(x−y) is
1,1,1 and x1,y1,z1
1,1,1 and x,y,z
0,0,0 and 1,1,1
The CF of (D2−DD′−2D′2)z=0
f1(y−2x)+f2(y−x)
f1(y+2x)+f2(y+x)
f1(y+2x)+f2(y−x)
If we eliminate a and b from z = (x+a)(y+b)
z = p/q
z = p - q
z = p + q
z = pq
If the number of constants to be eliminated is equal to number of independent variables, then the result is_____
First order PDE
Second order PDE
third order PDE
Second order linear PDE
If the number of constants to be eliminated is greater than the number of independent variables, then the result is_____
First order PDE
Second and higher order PDE
Second and higher order PDE
only Second order linear PDE
The Clairaut’s equation is of the form____
y=px+f(p)
y=px+f(q)
x=qy+f(p)
x=py+f(q)
If the equation is in the form f(x, p, q)=0, then we assume
p=a
z=pq
q=a
p=aq
The solution of the equation z = px + qy + pq is____
z = ax + by + pq
z = ax + by + ab
z = bx + ay + ab
z = px + qy + ab
Eliminate the arbitrary function from z = f(x2+y2)
px = qy
py+qx=0
px+qy=0
py = qx
Eliminate the arbitrary constants c and r from x2+y2+(z-c)2=r2
px = qy
px+qy=0
py = qx
py+qx=0
A solution containing as many arbitrary constants as there are independent variables is called____
complete integral
particular integral
singular integral
general integral
A solution obtained by giving particular values to the arbitrary constants in a complete integral is called____
complete integral
particular integral
singular integral
general integral
A partial differential equation which is not linear then it is called_____
semi linear
collinear
Quasi linear
non-linear
A partial differential equation requires
exactly one independent variable
two or more independent variables
more than one dependent variable
equal number of dependent and independent variables
Form a PDE by eliminating arbitrary constants from z= ax + by
z = px + qy
z = px - qy
z = qx + py
z = qx - py
Form a PDE by eliminating arbitrary constants from z= a(x+y) + b
p+q=0
px = qy
qx = py
p-q=0
The solution of ∂y2∂2z=0
z = yf(x)+g(x)
z = yf(y)+g(x)
z = xf(x)+g(x)
z = xf(y)+g(x)
The solution z = ax + g(a)y +c is getting from
f(x,p,q)=0
f(p,q)=0
f(x,p)=g(y,q)
f(z,p,q)=0
If the PDE is of the type f(p,q)=0, then we will take____
f(y,q)=a
f(x,p)=a
p=q
p=a
If the PDE is of the type f(z,p,q)=0, then we will take____
f(x,p)=a
p=aq
p=a
p=q
If the PDE is of the type f(x,p)=g(y,q), then we will take____
f(x,p)=a=g(y,q)
p=q
p=aq
p=a
The solution of simultaneous linear differential equations is of the form___
Φ(u,v)=0
Φ(u)=0
Φ(v)=0
Φ(x,y)=0
Find the complementary function of (D3−3D2D′+2DD′2)Z=0
Z=f1(y)+f2(y+x)+f3(y+2x)
Z=f1(y−x)+f2(y+x)+f3(y+2x)
Z=f1(y)+xf2(y+x)+f3(y+2x)
Z=f1(y)+f2(y−x)+f3(y−2x)
Find the roots of m3−m2+m−1=0
1,i,-i
1,-1,i
i,-i,0
1,-1,0
Find the complementary function of ∂x2∂2z+∂x∂y∂2z−2∂y2∂2z=0
Z=f1(y+x)+f2(y−2x)
Z=f1(y−x)+f2(y+2x)
Z=f1(y)+f2(y+2x)
Z=f1(y+x)+xf2(y−2x)
Find the complementary function of (D3−7DD′2−6D′3)z=0
Z=f1(y−x)+f2(y−2x)+f3(y+3x)
Z=f1(y+x)+f2(y+2x)+f3(y−3x)
Z=f1(y+x)+f2(y−2x)+xf3(y+3x)
Z=f1(y−x)+f2(y)+f3(y+3x)
Find the complementary function of ∂x3∂3z−3∂x2∂y∂3z+4∂y3∂3z=0
Z=f1(y−x)+f2(y+2x)+xf3(y+2x)
Z=f1(y−x)+f2(y+2x)+f3(y−2x)
Z=f1(y−x)+f2(y+2x)+f3(y+2x)
Z=f1(y+x)+f2(y+2x)+xf3(y+2x)
Solve (D3−DD′2−D′3)z=0
Z=f1(y+x)+f2(y−x)+xf3(y−x)
Z=f1(y−2x)+xf2(y−2x)+f3(y+x)
Z=f1(y)+xf2(y)+f3(y−x)
Z=f1(y+x)+f2(y−x)+f3(y−x)
Solve ∂x3∂3z−2∂x2∂y∂3z=0
Z=f1(y)+xf2(y)+f3(y+2x)
Z=f1(y)+f2(y+x)+f3(y+2x)
Z=f1(y)+f2(y−x)+f3(y+2x)
Z=f1(x)+yf2(x)+f3(y+2x)
Solve m2−4m+4=0
2,2
-2,-2
2,-2
0,2
Solve (D2+2DD′+D′2)z=0
Z=f1(y−x)+xf2(y−x)
Z=f1(y+x)+xf2(y−x)
Z=f1(y+x)+xf2(y+x)
Z=f1(y−x)+f2(y−x)
Solve (D2−3DD′+2D′2)z=0
Z=f1(y+x)+f2(y+2x)
Z=f1(y)+f2(y+x)
Z=f2(y−x)+f3(y−2x)
Z=xf1(y)+xf2(y+x)
The subsidiary equation for Lagrange's linear equation
xdx=ydy=zdz
pdx=qdy=rdz
Pdx=Qdy=Rdz
The multipliers for x(y−z)p+y(z−x)q=z(x−y) is
1,1,1 and x1,y1,z1
1,1,1 and x,y,z
0,0,0 and 1,1,1
Which of the following is clairaut's form
z=px+qy+pq
p+q=1
p+q=x+y
The degree of the following pde (∂x∂z )2+2(∂x∂y∂2z)+(∂y∂z)2=0 is
2
0
1
The solution of simultaneous linear differential equations is of the form___
Φ(u,v)=0
Φ(u)=0
Φ(v)=0
Φ(x,y)=0
Find the general solution of the linear partial differential equation, yzp+zxq=xy.
ϕ(x2−y2,y2−z2)=0
ϕ(x2−z2, y2−z2)=0
ϕ(x2−y2,−z2)=0
ϕ(x2−y2,y2−x2)=0
The solution of Lagrange's partial differential equation xp+yq=z is
f(yx,zy)=0
f(yx,zx)=0
f(xy,zy)=0
f(xy,zx)=0
The solution of non-linear partial differential equation
p+q=1 isz=ax+(1−a)2 y+c
z=ax+ay+b
z=ax+2ay+c
z=ax+ay+c
The particular integral of the equation (D−1)y=e3x is (K1, CO1)
2e3x
2e−3x
4e3x
2ex
The solution of non-linear partial differential equation
p+q=1 isz=ax+(1−a)2 y+c
z=ax+ay+b
z=ax+2ay+c
z=ax+ay+c
What are the multiples while solving (3z−4y)p+(4x−2z)q=2y−3x
2,3,4
3,4,2
4,2,3
1,1,1
What are the Lagrange’s multipliers while solving the PDE
p(y−z)−q(2x+y)=2x+zx,y,z
2x,y,z
x,−2y,z
2x,−z,−y
. Find the P.I of (D3+D2D′+DD′2+D′3)Z=0
1
0
ex
none
. Find the P.I of (D2−5DD′+6D′2)z=e(x+y)
e(x+y)
21e(x+y)
31e(x+y)
41e(x+y)
. Find the P.I of (D3−3D2D′+4D′2)Z=e(x+2y)
271e(x+2y)
61e(x+2y)
271e(2x+y)
61e(2x+y)
−161sin(x−3y)
−161cos(x−3y)
161cos(x−3y)
161sin(x−3y)
2y2e(2x+y)
2xye(2x+y)
2x2e(2x+y)
2x2e(2y+x)
41cosy
41cosx
41sinx
41siny
1
2
3
4
The highest derivative in the given pde is called
order
degree
The degree of the following pde (∂x∂z )2+2(∂x∂y∂2z)+(∂y∂z)2=0 is
2
0
1
Which of the following is clairaut's form
z=px+qy+pq
p+q=1
p+q=x+y
The complete integral of F1(x,p)=F2(y,q) is
z=∫qdx+∫pdy
z=∫pdx−∫qdy
z=∫pdx+∫qdy
The subsidiary equation for Lagrange's linear equation
xdx=ydy=zdz
pdx=qdy=rdz
Pdx=Qdy=Rdz
The multipliers for x(y−z)p+y(z−x)q=z(x−y) is
1,1,1 and x1,y1,z1
1,1,1 and x,y,z
0,0,0 and 1,1,1
The CF of (D2−DD′−2D′2)z=0
f1(y−2x)+f2(y−x)
f1(y+2x)+f2(y+x)
f1(y+2x)+f2(y−x)
The partial differential equation
is classified as
elliptic
parabolic
hyperbolic
none of the above
Solve (D3−3D2D′+2DD′2)Z=0
Z=f1(y)+f2(y+x)+f3(y+2x)
Z=f1(y−x)+f2(y+x)+f3(y+2x)
Z=f1(y)+xf2(y+x)+f3(y+2x)
Z=f1(y)+f2(y−x)+f3(y−2x)
∂x2∂2z+∂x∂y∂2z−2∂y2∂2z=0
Z=f1(y+x)+f2(y−2x)
Z=f1(y−x)+f2(y+2x)
Z=f1(y)+f2(y+2x)
Z=f1(y+x)+xf2(y−2x)
∂x3∂3z−3∂x2∂y∂3z+4∂y3∂3z=0
Z=f1(y−x)+f2(y+2x)+xf3(y+2x)
Z=f1(y−x)+f2(y+2x)+f3(y−2x)
Z=f1(y−x)+f2(y+2x)+f3(y+2x)
Z=f1(y+x)+f2(y+2x)+xf3(y+2x)
Solve (D3−DD′2−D′3)z=0
Z=f1(y+x)+f2(y−x)+xf3(y−x)
Z=f1(y−2x)+xf2(y−2x)+f3(y+x)
Z=f1(y)+xf2(y)+f3(y−x)
Z=f1(y+x)+f2(y−x)+f3(y−x)
Solve ∂x3∂3z−2∂x2∂y∂3z=0
Z=f1(y)+xf2(y)+f3(y+2x)
Z=f1(y)+f2(y+x)+f3(y+2x)
Z=f1(y)+f2(y−x)+f3(y+2x)
Z=f1(x)+yf2(x)+f3(y+2x)
Solve (D2−3DD′+2D′2)z=0
Z=f1(y+x)+f2(y+2x)
Z=f1(y)+f2(y+x)
Z=f2(y−x)+f3(y−2x)
Z=xf1(y)+xf2(y+x)
The solution of Lagrange's partial differential equation xp+yq=z is
f(yx,zy)=0
f(yx,zx)=0
f(xy,zy)=0
f(xy,zx)=0
Which of the following equations represents Clairaut’s partial differential equation?
z=px+f(p,q)
z=f(p,q)
z=p+q+f(p,q)
z=px+qy+f(p,q)
The solution of non-linear partial differential equation
p+q=1 isz=ax+(1−a)2 y+c
z=ax+ay+b
z=ax+2ay+c
z=ax+ay+c
The solution of non-linear partial differential equation
p+q=x isz=(x−a)3+a2y+b
z=3(x−a)3+a2y+b
z=(x−a)3+b
z=a2x+(y−a)3+c
The solution of non-linear partial differential equation
q−p+x−y=0 isz=2(x+a)2+2(y+a)2+c
z=(x+a)2+(y+a)2+c
z=2(x+a)2+2(y−a)2+c
z=2(x−a)2+2(y+a)2+c
By usual notations what is the general form of Lagrange’s linear PDE.
pdx+qdy=0
Pp+Qq=R
Pdx+Qdy=Rdz
non of the above
Find the complete integral of pq=1 .
i) z=(1/b)x+by+c
ii) z=ax+(1/a)y+c
iii) z=ax+by+c
(i)&(ii)
The complete solution of partial differential equation involves
complete function + indefinite integral
Complete function + Particular Integral
Complementary function + Particular Integral
complementary function + definite integral
Find the particular integral of (D2 -2DD' +D2)z=ex+2y
2ex
ex+2y
ex-y
3ex+2y
The particular integral of the equation (D2+DD'-6D'2)z = e3x+y
6e3x−y
5e3x+y
6e3x
6e3x+y
Find the Particular Integral of (D +4DD'-4D' )z = cos(x+y)
−cos(x+y)
2cos(x+y)
cos(x−y)
−2cos(x+y)
Which of the following is an example for first order linear partial differential equation?
Lagrange’s Partial Differential Equation
Clairaut’s Partial Differential Equation
What is the nature of Lagrange’s linear partial differential equation?
First-order, Second-degree
Second-order, First-degree
First-order, Third-degree
First-order, First-degree
Find the general solution of the linear partial differential equation, yzp+zxq=xy.
ϕ(x2−y2,y2−z2)=0
ϕ(x2−z2, y2−z2)=0
ϕ(x2−y2,−z2)=0
ϕ(x2−y2,y2−x2)=0
Which of the following equations represents Clairaut’s partial differential equation?
z=px+f(p,q)
z=f(p,q)
z=p+q+f(p,q)
z=px+qy+f(p,q)
The solution of Lagrange's partial differential equation xp+yq=z is
f(yx,zy)=0
f(yx,zx)=0
f(xy,zy)=0
f(xy,zx)=0
The solution of non-linear partial differential equation
p+q=1 isz=ax+(1−a)2 y+c
z=ax+ay+b
z=ax+2ay+c
z=ax+ay+c
The solution of non-linear partial differential equation
p+q=x isz=(x−a)3+a2y+b
z=3(x−a)3+a2y+b
z=(x−a)3+b
z=a2x+(y−a)3+c
The solution of non-linear partial differential equation
p(1+q)=qz islog(az−1)=x+a y+c
logz=x+a y+c
az−1=ex+a y+c
The solution of non-linear partial differential equation
q−p+x−y=0 isz=2(x+a)2+2(y+a)2+c
z=(x+a)2+(y+a)2+c
z=2(x+a)2+2(y−a)2+c
z=2(x−a)2+2(y+a)2+c
(undefined = 0, undefined = 4)
(undefined = 0, undefined = 4)
