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Basic conversions of Moles

Total questions: 13

Worksheet time: 59mins

Name
Class
Date
1.

How many oranges are in 1 mole of oranges?

(a)  

2.

How many atoms are in 2 moles of water?

HINT: Remember mole is just a unit of measurement

a)

1.204x1024

b)

6.02x1023

c)

12.04x1023

d)

12.04x1024

3.

How many moles are in 450g Potassium chloride (KCl)?

a)

6.0 g

b)

74.6 g/mol

c)

6.0 mol

d)

33.570 mol

4.

How many grams are in 4 moles of Calcium?

a)

0.10 grams

b)

44 grams

c)

10 grams

d)

160 grams

5.

C3H5(NO3)3 Identify the correct number of atoms

a)

C = 3, H = 5, N = 3, O = 9

b)


C = 9, H = 15, N = 3, O = 9

c)

C = 3, H = 5, N = 1, O = 9

d)

C = 9, H = 15, N = 1, O = 3

6.
How many grams are in 2.3x10-4 mol of calcium phosphate?
a)
0.031 g
b)
0.071 g
c)
0.084 g
d)
5.9x105 g
7.
How many grams are in 3.3 moles of potassium sulfide?
a)
21.6 g
b)
33 g
c)
235 g
d)
3.6x102 g
8.
What is the identity of an unknown polyatomic element, which has 0.0404 mol of molecules in 5.00 g?
a)
Sulfur
b)
Phosphorous
c)
Chlorine
d)
Antimony
9.

what equation relates mass, moles, and Mr

a)

mass = moles x mr

b)

Mr = moles / mass

c)

mass = moles / Mr

d)

moles = mass / Mr

10.
How many moles are in 4.5x1024 particles?
a)

7.47 particles

b)

7.47mol

c)
2.71x1047 mol
d)
2.71x1047 particles
11.

85.0 g of NaOH is equal to how many moles?

a)

3400 moles

b)

45 moles

c)

0.47 moles

d)

2.1 moles

12.

How many moles of oxygen atoms are in 3.011 x 10^23 atoms of oxygen?

To solve this problem you should...

a)

multiply by 1 mole6.022x1023\frac{1\ mole}{6.022x10^{23}}  

b)

multiply by  1 mole15.999 g\ \frac{1\ mole}{15.999\ g}  

c)

multiply by 6.022x10231 mole\frac{6.022x10^{23}}{1\ mole}  

d)

multiply by 15.999 g1 mole\frac{15.999\ g}{1\ mole}  

13.

How many moles of oxygen atoms are in 31.998 grams of oxygen?

To solve this problem you should...

a)

multiply by 1 mole6.022x1023\frac{1\ mole}{6.022x10^{23}}  

b)

multiply by  1 mole15.999 g\ \frac{1\ mole}{15.999\ g}  

c)

multiply by 6.022x10231 mole\frac{6.022x10^{23}}{1\ mole}  

d)

multiply by 15.999 g1 mole\frac{15.999\ g}{1\ mole}