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WorksheetsFinal HUGE AP Review
Total questions: 178
Worksheet time: 1hrs 29mins
sec(θ)=
cos(θ)1=x1
sin(θ)1=y1
cos(θ)sin(θ)=xy
sin(θ)cos(θ)=yx
csc(θ)=
cos(θ)1=x1
sin(θ)1=y1
cos(θ)sin(θ)=xy
sin(θ)cos(θ)=yx
tan(θ)=
cos(θ)1=x1
sin(θ)1=y1
cos(θ)sin(θ)=xy
sin(θ)cos(θ)=yx
cot(θ)=
cos(θ)1=x1
sin(θ)1=y1
cos(θ)sin(θ)=xy
sin(θ)cos(θ)=yx
1
3
DNE
5
1
3
DNE
0
3
1
DNE
5
4
1
DNE
2
4
2
1
3
4
2
1
DNE
True
False
True
False
3
1
DNE
Undefined
1
3
DNE
Undefined
DNE
Undefined
1
3
2
1
DNE
Undefined
2
1
Undefined
DNE
Big infinity over little infinity equals infinity
Little infinity over big infinity equals zero
Same infinity over same infinity equals ratio
Factor and cancel
Big infinity over little infinity equals infinity
Little infinity over big infinity equals zero
Same infinity over same infinity equals ratio of 1/1=1
Factor and cancel
Big infinity over little infinity equals infinity
Little infinity over big infinity equals zero
Same infinity over same infinity equals ratio equals 1/e
Factor and cancel
Big infinity over little infinity equals infinity
Little infinity over big infinity equals zero
Same infinity over same infinity equals ratio equals 2/3
Factor and cancel
Big infinity over little infinity equals infinity
Little infinity over big infinity equals zero
Same infinity over same infinity equals ratio equals 3/1
Same infinity over same infinity equals ration 9/1
0
1
cos(x)
sin(x)
0
1
cos(x)
sin(x)
Little infinity over big infinity equals zero
Big infinity over little infinity equals infinity
Same infinity over same infinity equals 1 over 1
Little infinity over big infinity equals zero
Big infinity over little infinity equals infinity
Same infinity over same infinity equals 1 over 1
Little infinity over big infinity equals zero
Big infinity over little infinity equals infinity
Same infinity over same infinity equals 1 over 1
1
5
0
1/5
Check Left, Check Right, See if Equal
Multiply by conjugate
Graph
Set equal, solve for constant
Check Left, Check Right, See if Equal
Multiply by conjugate
Graph
Set equal, solve for constant
When using the Intermediate Value Theorem on f(x) , you must first write
Since f(x) is increasing
Since f(x) is continous
Since f(x)>L
Since f(x) is a function
To find the horizontal asymptotes of f(x) , you consider
The limit of f(x) as x approaches positive and negative infinity
Set the denominator of f(x) equal to zero, ignoring holes
Find the holes by cancelling common factors
To find the vertical asymptotes of f(x) , you consider
The limit of f(x) as x approaches positive and negative infinity
Set the denominator of f(x) equal to zero, ignoring holes
Find the holes by cancelling common factors
If f(x)=x+35x−2 , the vertical asymptote is
x=−3
x=3
y=5
y=−5
If f(x)=x+35x−2 , the horizontal asymptote is
x=−3
x=3
y=5
y=−5
Find cosine of x=pi/3
Limits to infinity - big infinity over little infinity
Limit definition of the derivative question, find the derivative of cosine
Graph and find the limit
Limit definition of the derivative - find the derivative of x3 at x=2
Limits to infinity
Graph, then find limit
Factor and cancel
If
f(x)=log3(x) , then ...f′(x)=xln(3)1
f′(x)=ln(3)⋅3x
f′(x)=3x1
f′(x)=x3
If f(x)=cos(x3) , then f′(x)=
f′(x)=−3x2sin(x3)
f′(x)=−sin(x3)
3x2cos(x3)
f(x)=−3sin(x3)
If m(x)=(f(x))5 , then m′(x)=
5(f(x))4f′(x)
5(f′(x))4
5f(x)f′(x)
(f′(x))5
If h(x)=f(g(x)) , then h′(x)=
f′(g(x))g′(x)
f(g′(x))
f′(x)g(x)+f(x)g′(x)
f′(g′(x))
dxd(uv)
u′v+uv′
u′v′
u′v−uv′
uv
dxd(vu)=
v2u′v−uv′
u′v+uv′
v′u′
u′v−uv′
If h(x)=x2f(x) , then h′(x)=
h′(x)=2xf(x)+x2f′(x)
h′(x)=2xf′(x)
h′(x)=x2f(x)⋅f′(x)
f′(x)=2(f(x))f′(x)
If
f(x)=sin(x)x3 , then find f′(x)cos(x)3x2
(sin(x))2(3x2)(sin(x))−(x3)(cos(x))
(3x2)sin(x)+(x3)cos(x)
(sin(x))2x3sin(x)−cos(x)x3
If
f(x)=2x , then ...f′(x)=2x
f′(x)=ln(2)⋅2x
f′(x)=e2x
f′(x)=ln(2)ex
If
f(x)=4x , then ...f′(x)=4x
f′(x)=ln(4)⋅4x
f′(x)=e4x
f′(x)=ln(4)ex
If
f(x)=log2(x) , then ...f′(x)=xln(2)1
f′(x)=ln(2)⋅2x
f′(x)=2x1
f′(x)=x2
∫4 x7
32x8+C
23x6+C
28x6+C
32x8+C
3-x2
Limit to infinity
Substitute upper bound into x, multiply by derivative of the upper bound
Take antiderivative, evaluate integral
Substitute in upper bound, multiply by derivative of the upper bound
Take the anti-derivative, evaluate
x2-a
Limit to infinity
Take the derivative
graph the function
Set up to coordinate points, f and f-1. Set point equal to a, solve for x. Find f'(x). Take reciprical - 1/m
Integrate
Separate the variables
Separate the variables
Separate the variables
Separate the variables
Separate the variables
Separate the variables
Separate the variables
Separate the variables
Separate the variables
If you're supposed to find the Average Value of f(x) , then the units of the average value will be...
the same as the unit for f(x)
the units of the ∫f(x)
the units of the derivative of f(x)
Average value is...
b−a1∫abf(x)dx
b−af(b)−f(a)
∫abf(x)dx
y−y1=m(x−x1)
Average rate of change is...
b−a1∫abf(x)dx
b−af(b)−f(a)
∫abf(x)dx
y−y1=m(x−x1)
∫f′(2x)dx
21f(2x)
2f′′(2x)
2f(2x)
21f′′(2x)
∫f′(21x)dx
21f(21x)
2f′′(21x)
2f(21x)
21f′′(21x)
If R(x) is an increasing function, then a Left Hand Riemann sum will be an...
Underapproximation
Overapproximation
If R(x) is a decreasing function, then a Left Hand Riemann sum will be an...
Underapproximation
Overapproximation
If R(x) is an increasing function, then a Right Hand Riemann sum will be an...
Underapproximation
Overapproximation
If R(x) is a decreasing function, then a Right Hand Riemann sum will be an...
Underapproximation
Overapproximation
If R(x) is an increasing concave up function, then a Trapezoidal Riemann sum will be an...
Underapproximation
Overapproximation
If R(x) is an increasing concave down function, then a Trapezoidal Riemann sum will be an...
Underapproximation
Overapproximation
Find the area of the region
Find the area of the region
Find the between the two curves
Find the volume of the solid formed when the region R is rotated about the line y=k
Find the volume of the solid formed when the region R is rotated about the line x=k
Find the volume of the solid formed when cross sections perpendicular to the x axis are squares
Find the volume of the solid formed when cross sections perpendicular to the x axis are isosceles triangles
Find the volume of the solid formed when cross sections perpendicular to the x axis are semi-circles
Find the volume of the solid formed when cross sections perpendicular to the y axis are semi-circles
Find the volume of the solid formed by cross sections perpendicular to the x axis that are rectangles with a height three times the base.
Find the volume of the solid formed when the region is rotated about the line y=8
π∫08((8−f(x))2−(8−g(x))2)dx
π∫08((8−g(x))2−(8−f(x))2)dx
π∫06((8−g(y))2−(8−f(y))2)dy
π∫06((8−f(y))2−(8−g(y))2)dy
Find the volume of the solid formed when the region is rotated about the line x=8
π∫08((8−f(x))2−(8−g(x))2)dx
π∫08((8−g(x))2−(8−f(x))2)dx
π∫06((8−g(y))2−(8−f(y))2)dy
π∫06((8−f(y))2−(8−g(y))2)dy
Find the volume of the solid formed when the region is rotated about the line y=−1
π∫08((f(x)−(−1))2−(g(x)−(−1))2)dx
π∫08((g(x)−(−1))2−(f(x)−(−1))2)dx
π∫06((−1−g(y))2−(−1−f(y))2)dy
π∫06((−1−f(y))2−(−1−g(y))2)dy
Find the volume of the solid formed when the region is rotated about the line x=−1
π∫08((f(x)−(−1))2−(g(x)−(−1))2)dx
π∫08((g(x)−(−1))2−(f(x)−(−1))2)dx
π∫06((g(y)−(−1))2−(f(y)−(−1))2)dy
π∫06((f(y)−(−1))2−(g(y)−(−1))2)dy
Find the volume of the solid formed when the region is rotated about the x−axis
π∫08((f(x))2−(g(x))2)dx
π∫06((g(y))2−(f(y))2)dy
π∫06((f(y))2−(g(y))2)dy
π∫08((g(x))2−(f(x))2)dx
Find the volume of the solid formed when the region is rotated about the y−axis
π∫08((f(x))2−(g(x))2)dx
π∫06((g(y))2−(f(y))2)dy
π∫06((f(y))2−(g(y))2)dy
π∫08((g(x))2−(f(x))2)dx
Find the volume of the solid formed when cross sections perpendicular to the x axis are rectangles with height 5 times its base
Why do we need implicit differentation?
Because the x and y's are on the same side of the equation
Because it's fun
Because we're supposed to learn it
Find the derivative of 2y
y′
1
2yy′
2y′
Find the derivative of xy
(1)(y′)+(x)(y)
(1)(y)+(x)(y′)
(1)(y′)
(x)(y′)+(x)(y)
Find the derivative of x2−xy
2x−[(1)(y)+(x)(y′)]
2x−(1)(y)+(x)(y′)
2x−[(x)(y)+(1)(y′)]
2x−(1)(y′)
When you see an xy or 2x2y or 3xy2 you need to remember
The product rule!
The quotient rule!
Write a lot!
The derivative of x3+y3 is
3x2+3y2y′
(3x2)(y3)+(x3)(3y2y′)
3x2+3y2
x3+3y2y′
If x2+2xy=4 , then the first step to finding dxdy is
2x+(2)(y)+(2x)(dxdy)=0
2x+(2)(y)+(2x)(1)=0
2x+2y dxdy=0
2x dxdy+(2)(y)+(2x)(dxdy)=0
What is the first step of the derivative
sin(xy)=y2
cos(xy)((1)(y)+(x)(y′))=2y⋅y′
cos(xy)=2y⋅y′
sin(xy)((1)(y)+(x)(y′))=2y⋅y′
cos((1)((y)+(x)(y′)))=2y⋅y′
What is the first step of the derivative of
ey+y31=2x
ey⋅y′+31y−32⋅y′=2x⋅ln(2)
ey+31y−32=2x⋅ln(2)
ey⋅y′+y31=2x
Find the distance the particle travels on [a,b]
Find the particle's position at
t=5 given that x(1)=2Find the particle's displacement on [a,b]
Distance
Displacement
Position
Acceleration
Distance
Displacement
Position
Acceleration
Distance
Displacement
Position
Acceleration
Find the average velocity on [a,b]
Average rate of change
Average Value
Average rate of change
Average value
Average rate of change
Average value
If the velocity and acceleration of a particle have the SAME SIGN, then the particle is...
Speeding Up
Slowing Down
Neither
If the velocity and acceleration of a particle have OPPOSITE SIGNS, then the particle is...
Speeding Up
Slowing Down
Neither
To determine if a particle is speeding up or slowing down at time r , the first thing you need to do is
Find
v(r) and a(r)Compare the signs to determine if they are the same or opposite
Make a sign chart for v(t)
Make a sign chart for a(t)
If
v(r)=+ and a(r)=+ , then the particle isSpeeding Up
Slowing Down
Neither
If
v(r)=+ and a(r)=− , then the particle isSpeeding Up
Slowing Down
Neither
