WorksheetsTrigonometric Challenge
Total questions: 10
Worksheet time: 5mins
Graph the function y = sin(x) for x in the interval [-2π, 2π].
The graph of y = sin(x) for x in the interval [-2π, 2π] is a sine curve that starts at (−2π, 0), reaches its peak at (0, 1), crosses the x-axis at (π, 0), reaches its lowest point at (2π, −1), and returns to the x-axis at (3π, 0).
The graph of y = sin(x) is a straight line
The graph of y = sin(x) is a parabola
The graph of y = sin(x) is a hyperbola
Solve for x in the equation sin(x) = 0.5.
x = 2π/3 or x = 120 degrees
x = π/3 or x = 60 degrees
x = π/4 or x = 45 degrees
x = π/6 or x = 30 degrees
Graph the function y = cos(x) for x in the interval [-π, π].
Graph plotted with two complete cycles of cosine function from -π to π.
Graph plotted with sine function instead of cosine function.
Graph plotted with exponential function.
Graph plotted with one complete cycle of cosine function from -π to π.
Find the exact value of sin^(-1)(1).
π/2
2π
π
0
Graph the function y = tan(x) for x in the interval [-π/2, π/2].
Graphing the function y = tan(x) for x in the interval [-π/2, π/2] results in a curve with vertical asymptotes at x = -π/2 and x = π/2.
The function y = tan(x) has no asymptotes in the given interval
Graphing the function y = tan(x) for x in the interval [-π/2, π/2] results in a straight line
The graph of y = tan(x) is a perfect circle
Determine the value of cos^(-1)(0).
3pi/2
pi/2
pi
pi/4
Graph the function y = csc(x) for x in the interval [0, 2π].
The graph of y = csc(x) has a horizontal asymptote at x = π
The graph of y = csc(x) is symmetric about the y-axis
The graph of y = csc(x) for x in the interval [0, 2π] will have vertical asymptotes at x = 0, x = π, and x = 2π. It will have peaks at x = π/2 and x = 3π/2. The graph will repeat every π units.
The graph of y = csc(x) has a peak at x = 2π
Calculate the value of tan^(-1)(√3).
π/3
2π/3
π/4
π/6
Graph the function y = sec(x) for x in the interval [0, 2π].
The graph of y = sec(x) has no asymptotes.
The graph of y = sec(x) has a peak at x = π/2.
The graph of y = sec(x) has a valley at x = 3π/2.
The graph of y = sec(x) for x in the interval [0, 2π] will have vertical asymptotes at x = π/2 and x = 3π/2, and peaks at x = 0 and x = 2π, with valleys at x = π.
Solve for x in the equation cos(x) = -0.5.
x = 3π/4 or x = 7π/4
x = 2π/5 or x = 3π/5
x = π/3 or x = 2π/3
x = 4π/3 or x = 5π/3
