Free Printable Module 2 (3)

Worksheets

Module 2 (3)

Total questions: 10

Worksheet time: 20mins

Name

Class

Date

How many shear stress components can act on a 3-D object?

Which of the following statements best describes the condition of plane stress?

Three-dimensional stress state with uniform stress in all directions.

One-dimensional stress state with varying stress along the length.

Two-dimensional stress state with negligible stress in the thickness direction.

A stress state that only considers shear stress without normal stress.

What is the fundamental concept behind transforming plane stresses?

The main idea is to determine the temperature effects on stress distribution.

involves changing the orientation of the coordinate system to find the stresses on a different plane

It focuses on the deformation of materials under uniform pressure.

The concept involves calculating the total stress on a single plane.

What is the significance of the coordinate system in transforming plane stresses?

It helps in measuring the temperature of materials.

The coordinate system is irrelevant to stress analysis.

It only applies to three-dimensional stress states.

The coordinate system enables the transformation of plane stresses to analyze different orientations and understand material behavior.

What is the relationship between the stress components in the original and transformed coordinate systems?

The transformation equations show how original stresses change based on the angle of rotation.

The stress components remain unchanged regardless of the coordinate system.

Stress components can only be transformed using linear equations without angles.

The relationship between stress components is independent of the coordinate system.

Given 𝛔ₓ = 35 MPa, 𝛔_y= 25 MPa, and τ ₓ_y = 15 MPa, find the principal stresses in a coordinate system rotated 30° counterclockwise

σₓ' and σ_y'

σₓ' = 35 MPa,

σy' = 22 MPa

σₓ' = 45 MPa,

σy' = 14MPa

σₓ' = 30 MPa,

σy' = 10 MPa

σₓ' = 40 MPa,

σy' = 20 MPa

If the principal stresses are σ₁ = 35 MPa and σ₂ = 20 MPa, find the maximum shear stress?

10 MPa

7.5 MPa

25 MPa

5 MPa

. If the principal stresses are σ_x = 40 MPa and σ_y = 70 MPa and τ_xy =20MPa.find the orientation of the principal planes?

333°.

320°.

220°.

32°.

. Given σₓ= 40 MPa, σ_y = 30 MPa, and τ _{x y} = 20 MPa, find the principal stresses

σ₁ = 60 MPa, σ₂ = 10 MPa

σ₁ = 55.615 MPa, σ₂ = 14.385 MPa

σ₁ = 50 MPa, σ₂ = 20 MPa

σ₁ = 45 MPa, σ₂ = 25 MPa

10.

A body is subjected to a direct tensile stress (σ) in one plane. The shear stress is max at a section inclined at ____ to the normal of the section.

90 degrees

0°

45°

45° and 135°

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Module 2 (3)

Total questions: 10

Worksheet time: 20mins

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