$$\frac{\text{d}y}{\text{d}x}=8x^{-5}+4x$$  

$$\frac{\text{d}y}{\text{d}x}=-8x^{-5}+4$$  

$$\frac{\text{d}y}{\text{d}x}=-8x^{-4}+4$$  

$$\frac{\text{d}y}{\text{d}x}=8x^{-4}+4x$$  

$$\frac{\text{d}y}{\text{d}x}=2x^5+6x^2$$  

$$\frac{\text{d}y}{\text{d}x}=10x^6+6x$$  

$$\frac{\text{d}y}{\text{d}x}=10x^4-12$$  

$$\frac{\text{d}y}{\text{d}x}=10x^4+12x$$  

$$-1$$  

$$\frac{\left(-x^2+2x\right)}{x^2}$$  

$$\frac{1}{x^2}$$  

$$-\frac{1}{x^2}$$  

Ninguna de las opciones es correcta

$$y'=\frac{3}{7\sqrt[2]{x^4}}$$

$$y'=\frac{7}{3\sqrt[2]{x^4}}$$

$$y'=\frac{3}{7\sqrt[7]{x^4}}$$

$$y'=\frac{7}{7\sqrt[3]{x^2}}$$

$$y´=x^{3\ }\arccos\ x-\frac{x^3}{\sqrt{1-x^2}}$$  

$$y´=3x^{3\ }\arccos\ x+\frac{x^3}{\sqrt{1-x^2}}$$  

$$y´=3x^{3\ }\arccos\ x-\frac{x^3}{\sqrt{1-x^2}}$$  

$$f'\left(x\right)=\frac{\left(3x^2+1\right)}{\left(x^2+1\right)}$$  

$$f'\left(x\right)=\frac{\left(2x^2-1\right)}{\left(x^2+1\right)^2}$$  

$$f'\left(x\right)=\frac{\left(1-x^2\right)}{\left(x^2+1\right)^2}$$  

$$f'\left(x\right)=\frac{\left(x^2-1\right)}{\left(x^2+1\right)^2}$$  

$$f'\left(x\right)=\sqrt{x}$$  

$$f'\left(x\right)=2$$  

$$f'\left(x\right)=\frac{1}{2\sqrt{x}}+2$$  

$$f'\left(x\right)=\sqrt{x}+2$$  

$$f\left(x\right)'=\frac{7}{3}\sqrt[3]{x^4}+9x^2+\frac{3}{x^4}$$  

$$f\left(x\right)'=\frac{7}{3}\sqrt[3]{x^4}+18x+\frac{3}{x^4}$$  

$$f\left(x\right)'=\frac{7}{3}\sqrt[3]{x^4}+18x+\frac{9}{x^4}$$  

Isaac Newton

Gottfried Wilhelm von Leibniz

James Clerk Maxwell

Matemático y científico

Augustin Louis Cauchy