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Worksheets10054 Unit 3 Review (Topics 18-23): Trigonometry
Total questions: 136
Worksheet time: 2hrs 19mins
What is the order of the coordinate pairs for the points on the Unit Circle?
(tanθ,sinθ)
(cotθ,cosθ)
(sinθ,cosθ)
(cosθ,sinθ)
tan(θ) represents...
the x coordinate on the unit circle
the y coordinate on the unit circle
the ratio of coordinates: xy
sin(120°)=
22
23
−21
21
sin(4π)=
23
21
22
1
0
Give the exact value of the expression.
22
4π
−22
1
Evaluate sin(2π)
−21
21
23
−1
1
sin(−35π)
21
−23
−21
23
sin(−135°)=
−22
23
−21
21
Evaluate:
1
0
−1
Undefined
sin 415π
21
23
−22
22
cos(67π)=
22
23
−21
−23
cos(0)=
0
1
23
21
22
Exact value of sin(−35π)
23
2− 3
21
−21
Evaluate sin(623π)
−23
33
−21
3
sec 45π
−22
-2
−2
−323
csc 3π
323
2
23
21
Exact value of tan (65π)
− 3
3− 3
21
2− 3
33
tan 37π
33
3
-1
−3
sec 2π
0
1
undefined
-1
cot 34π
33
3
1
−33
Give the exact value of the expression.
−33
−3
21
−21
Evaluate:
1
0
−1
Undefined
tan(210°)=
22
33
−3
−21
tan(−π)=
Which of the following equal 0
sin(0)
sec(23π)
tan(π)
cot(2π)
Which of the following are undefined?
sec(2π)
tan(π)
csc(π)
cot(23π)
Find θ if sin(θ)=−23 , and θ is in Quadrant III.
34π
67π
43π
35π
Evaluate the given expression using only your unit circle. Give answers in degrees!
cos−1(2−1) =___ °30
60
120
150
Evaluate the given expression using only your unit circle. Give answers in degrees!
tan−1(−1) =___ °-45
45
315
90
Use the unit circle to match the angle measure: cos(310π)
22
23
−21
21
Evaluate the given expression using only your unit circle. Give answers in degrees!
arcsin(21) = (a) °
Evaluate the given expression using only your unit circle. Give answers in degrees!
sin−1(−1) =___ °45
90
0
-90
π/3; 5π/3
2π/3; 4π/3
7π/6; 11π/6
π/6; 5π/6
If the angle θ is in quadrant II and the sinθ=75 which of the following represents the cosθ ?
5−7
57
7−2 6
72 6
What quadrant is θ=−32π in?
I
II
III
IV
Give the exact value of the expression.
1
0
π
2π
Evaluate Sin−1(−23)=
−6π
−4π
−3π
35π
34π
Give the exact value of the expression.
4π
45π
2π
0
Evaluate Cos−1(−21)=
4π
3π
2π
32π
43π
Give the exact value of the expression.
−4π
43π
4π
6π
Give the exact value of the expression.
−2π
0
2π
π
What is the amplitude of the function y=3sin(2x−32π) ?
Amplitude =∣a∣
(a)
What is the period of the function y=3sin(2x−32π) ?
Period =b2π
2π
23π
π
3π
What is the maximum of the function y=3sin(2x−32π) ?
Max. =∣a∣
(a)
What is the minimum of the function y=3sin(2x−32π) ?
Min. =−∣a∣
(a)
Use the unit circle to match the angle measure: sinπ
undefined
−1
1
0
What is the phase shift (horizontal shift) of the function y=3sin(2x−32π) ?
Phase Shift =bc
3π units to the left
3π units to the right
Use a calculator to find to the degrees to the nearest hundredth of the expression Sin−1(0.87)= (a) . (Do not enter any words in your answer.)
Use a calculator to find the degrees to the nearest hundredth of the expression Cos−1(−53)= (a) . (Do not enter any words in your answer.)
Use the unit circle to match the angle measure: cos(47π)
22
23
−21
21
What is the phase shift (horizontal shift) of the function y=cos(2x−14π) ?
π units to the right
7π units to the right
14π units to the right
14π units to the left
Which graph represents the function f(x)=−2cosx+1 ?
Check all that apply to H(x)=Cos(x)
Cos(x) has a restricted domain: −2π≤x≤2π
Cos−1(x) exists
its range is [−1,1]
Cos(43π)=−22
The domain is restricted to QI and QII on the unit circle.
H−1(x)=Cos−1(x)
The domain is [−1,1]
The range is 0≤x≤π
Cos−1(0)=π
Cos−1(−23)=65π
Cos−1(23)=6π
Check all that apply to G(x)=Sin(x)
Sin(x) has a restricted domain: −2π≤x≤2π
Sin−1(x) exists
its range is [−1,1]
Sin(4π)=1
The domain is restricted to QI and QII on the unit circle.
G−1(x)=Sin−1(x)
The domain is (−∞,∝)
The range is −2π<x<2π
Sin−1(22)=4π
Sin−1(−23)=−3π
Sin−1(0)=0
Check all that apply to F(x)=Tan(x)
Tan(x) has a restricted domain: −2π<x<2π
Tan−1(x) exists
its range is [−1,1]
Tan(−4π)=−1
The domain is restricted to QI and QIV on the unit circle.
F−1(x)=Tan−1(x)
The domain is (−∞,∝)
The range is −2π<x<2π
Tan−1(1)=4π
Tan−1(3)=3π
Tan−1(−33)=−6π
What is csc(x) equivalent to?
sinx1
tanx1
sin(x)
cosx1
Simplify.
Simplify.
cos 2 x + sin 2 x=
Simplify
Simplify
secθ
cos²θ
sin²θ
cos2xsin2x
Simplify (cscx+1)(cscx−1)
csc2x+1
tan2x
cot2x
2cscx
sec(u)
cos(u)
csc(u)
sin(u)
cot(u)
csc(u)
cos(u)
tan(u)
sin(u)
cot(u)
sec(u)
cos(u)
tan(u)
sin(u)
csc(u)
Simplify: (cos θ)(sec θ−cosθ)
sin2θ
cos2θ
csc2θ
sec2θ
Simplify: secx−tanxsinx
sinx
cosx
cscx
secx
Simplify: secx1−sin2x
sin2x
cos2x
sin3x
cos3x
Simplify: cotxcos2(−x)cscx
−sinx
−cosx
sinx
cosx
cos(−θ)=
−cos(θ)
cos(θ)
−cos(−θ)
sin(−θ)=
−sin(θ)
sin(θ)
−sin(−θ)
tan(−θ)=
−tan(θ)
tan(θ)
−tan(−θ)
Evaluate:
1
0
−1
Undefined
Evaluate:
1
0
−1
Undefined
Evaluate:
22
−22
−21
21
Evaluate:
23
−23
−21
21
Evaluate:
23
−23
−22
22
Evaluate:
23
−23
−21
21
Evaluate:
1
0
−1
Undefined
Evaluate:
3
−3
−33
33
Evaluate:
1
0
−1
Undefined
Evaluate:
1
0
−1
Undefined
Evaluate:
23
−23
−22
22
Evaluate:
1
0
−1
Undefined
Evaluate:
1
0
−1
Undefined
Evaluate:
1
0
−1
Undefined
Evaluate:
1
0
−1
Undefined
Evaluate:
23
−23
−22
−21
Evaluate:
23
21
22
−21
Evaluate:
23
21
−23
−21
Evaluate:
23
21
−23
−21
Evaluate:
1
0
−1
Undefined
Evaluate:
1
0
−1
Undefined
Evaluate:
3
−3
−33
33
Evaluate:
1
0
−1
Undefined
Evaluate:
23
21
−23
−21
Evaluate:
23
−23
−22
22
Solve over the interval [−2π, 2π] : csc2 x+2cscx −8= 0
0.253, 2.889, 67π, 611π
−0.253, 6π
3.394, 6.031, 67π, 611π
3.394, 6.031, 6π, 65π
Solve over the interval [0, 2π) : 3 cos2 x + cos x−1 = 0
Check ALL correct answers.
1.12, 5.16
0.43, 5.85
0.77, 2.44
2.44, 3.84
2.02, 5.16
π/3; 2π/3
Solve the following equation over the interval [0, 2π):
tan2θ − 3tanθ + 2 = 0
Check ALL correct answers.
43π, 47π
4π, 45π
1.11,4.25
2.03,5.17
2π, 23π
5cos2 x + 3cos x =0
Find all solutions to over the interval [2π, 23π)
0.927
2.215
4.069
2π
23π
Solve sinθ = -1 on θ∈[0, 2π)
θ = π /2, 3π /2
θ = π /2
θ = 3π /2
θ = π
Solve tanθ+1=2 on θ∈[0, 2π)
0 and π
3π/4 and 7π/4
π/4 and 5π/4
3π/4 and 5π/4
Solve cosθ = -1 on [0, 2π)
θ = π /2, 3π /2
θ = π /2
θ = 3π /2
θ = π
x = 60°, 120°
x = 60°, 300°
x = 30°, 150°
x = 30°, 330°
Why doesn't 2cosx − 3 = 0 have solutions?
cos x is never bigger than one
cos x is never equal to a fraction
Actually, this equation does have a solution, x = π
This equation will have a solution tomorrow.
Solve equation for 0≤θ<2π .
3sin2θ=7sin2θ+4sinθ+1
θ=67π
θ=0,3π,35π
θ=43π,47π
θ=67π,611π
cos2 x + sin x + 1 = 0
Solve over the interval [0,2π)
3sinθ=3cosθ
6π,67π
6π,65π
65π,611π
6π,65π,67π,611π
Solve the equation over the interval [ 2π,π ]
3−tan2θ2tanθ=1
Type in your answer rounded to the nearest thousandths (3 decimals).
(a)
no solution
π/6; 5π/6
Solve the equation over the interval [ 2π,π ]
3−tan2θ2tanθ=1
Type in your answer rounded to the nearest tenth
(a)
Solve:
2cos2x+3=2x=32π+2nπ; x=34π+2nπ
x=3π; x=32π
x=3π+nπ; x=32π+nπ
x=−41
Solve in the interval [0, 2π):
2sin3x−1=0x=6π; x=65π
x=18π; x=185π
x=9π; x=92π
x=2π
Which trigonometric ratio should you use?
Tangent Ratio
Sine Ratio
Cosine Ratio
Any ratio
Which trigonometric ratio should you use?
Tangent Ratio
Sine Ratio
Cosine Ratio
Any ratio
