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WorksheetsGnav (301-350)
Total questions: 50
Worksheet time: 25mins
The initial straight track from A (75°N 60°E) to B (75°N 60°W) on a polar stereographic chart is:
360°
030°
060°
330°
A polar stereographic chart is used for navigation. The straight line between A 75°S 166°E and B 78°S 154°E is drawn in this chart. The true track angle of the rhumb line is 223°.Calculate the direction (T) of the straight line in position B:
217°
235°
211°
229°
What is the value of the convergence factor on a Polar Stereographic chart?
0.866
0.5
0.0
1.0
An aeronautical chart is conformal when:
every great circle is represented by a straight line in the map.
the meridians and parallels are perpendicular to each other.
the map is an equidistant normal projection.
At any point the scale over a short distance in the direction of the parallel is equal to the scale in the direction of the meridian and the meridians are perpendicular to the parallels.
The Polar Stereographic projection is:
a plane projection.
a cylinder projection.
a variable cone projection.
a conical projection.
On a polar stereographic chart, the initial great circle course from A 70°N 060°W to B 70°N 060°E is approximately:
030° (T)
330° (T)
150° (T)
210° (T)
In a navigation chart a distance of 49 NM is equal to 7 cm. The scale of the chart is approximately:
1 : 7 000 000
1 : 700 000
1 : 1 300 000
1 : 130 000
The total length of the 53°N parallel of latitude on a direct Mercator chart is 133 cm. What is the approximate scale of the chart at latitude 30°S?
1 : 30 000 000
1 : 26 000 000
1 : 18 000 000
1 : 21 000 000
If the chart scale is 1 : 500 000, what Earth distance would be represented by 7 cm on the chart?
3.5 km
35 NM
35 000 m
0.35 km
In which of the following projections does a plane surface touch the reduced Earth at one of the Poles?
Stereographic.
Direct Mercator.
Lambert's.
none of the above.
Calculate the constant of the cone on a Lambert Chart given chart convergency between 010°E and 030°W as being 30°:
0.40
0.75
0.50
0.64
A straight line from A (53°5, 155°E) to B (53°5, 170°W) is drawn on a Lambert Conformal conical chart with standard parallels at 50°5 and 56°5. When passing 175°W, the True Track is:
078°
102°
282°
258°
On a direct Mercator chart at latitude 15°S, a certain length represents a distance of 120 NM on the Earth. The same length on the chart will represent on the Earth, at latitude 10°N, a distance of:
122.3 NM
117.7 NM
124.2 NM
118.2 NM
On a Lambert conformal conic chart the convergence of the meridians:
is zero throughout the chart.
is the same as Earth convergency at the parallel of origin.
varies as the secant of the latitude.
equals Earth convergency at the standard parallels.
In producing chart projections, the following projection surfaces may be used:
plane, sphere, cone.
plane, cylinder, cone.
cylinder, sphere, plane.
parabola, cone, plane, cylinder.
Using a Lambert conformal conic chart on which Chart Convergency = Earth Convergency at latitude 42°. A straight line is drawn from position A (48°_ 155°E) to position B (36° _ ° E). The true course of the straight line track at position A is 060°T and at position B is 46°T. The hemisphere in which the track is drawn and the final longitude at B are:
Southern Hemisphere, 166°E
Northern Hemisphere, 176°E
Southern Hemisphere, 176°E
Northern Hemisphere, 166°E
On a chart, the distance along a meridian between latitudes 45°N and 46°N is 6 cm. The scale of the chart is approximately:
1 : 1 850 000
1 : 1 000 000
1 : 185 000
1 : 18 500 000
On a polar stereographic map, a straight line is drawn from position A (70°N 1 02°W) to position B (80°N 006°E). The point of highest latitude along this line occurs at longitude 035°W. What is the initial straight-line track angle from A to B, measured at A?
077°
049°
229°
023°
From Rakovnik (50°05.9' N, 013°41.5' E) to Frankfurt FFM (50°05.9' N, 008°38.3' E) the True Track of departure along the straight line is 272.0°. The constant of the cone of this Lambert conformal projection is:
0.79
0.77
0.20
0.40
On a Lambert conformal chart, the distance between two parallels of latitude (difference of latitude = 2°), is measured to be 112 mm. The distance between two meridians, spaced 2° longitude, according to the chart is 70 NM. What is the latitude in the centre of the described square?
38°
49°
54°
42°
How is a non controlled route marked on a map/chart?
As a dashed line.
As solid line.
As an alternate dotted/dashed line.
As a dotted line.
Contour lines on aeronautical maps and charts connect points:
with the same variation.
of equal latitude.
having the same longitude.
having the same elevation above sea level.
On a Lambert conformal conic chart great circles that are not meridians are:
straight lines.
curves concave to the parallel of origin.
curves concave to the pole of projection.
straight lines within the standard parallels.
Given: Lambert conformal conical projection, scale 1:1234000. Standard parallels 36°N and 60°N. A (53°N, 010°W), B (53°N, 020°W). The distance on the map between position A and position B measured along the Rhumb line:
is more than 57.13 cm.
is 55.66 cm.
is between 54.19 cm and 57.13 cm.
is less than 54.19 cm.
The nominal scale of a Lambert conformal conic chart is the:
scale at the standard parallels.
scale at the Equator.
mean scale between the pole and the Equator.
mean scale between the parallels of the secant cone.
A Lambert conformal conic projection, with two standard parallels:
shows lines of longitude as parallel straight lines.
shows all great circles as straight lines.
the scale is only correct at parallel of origin.
the scale is only correct along the standard parallels.
On a Lambert conformal chart the distance between meridians 5° apart along latitude 37° North is 9 cm. The scale of the chart at that parallel approximates:
1 : 3 750 000
1 : 5 000 000
1 : 2 000 000
1 : 6 000 000
A straight line from A (75°5, 120°E) to B (75°5, 160°E) is drawn on a Polar Stereographic chart. When passing the meridian 155°E, the True Track is:
105°
095°
075°
255°
On a direct Mercator projection chart a straight line is drawn between A (40°N, 050°W) and B (50°N, 060°W). Calculate the angle between the straight line and the great circle in position A
3.2°
3.5°
1.8°
7.0°
Given: TAS: 140 kts FL80 OAT: +20°C What is the CAS?
129 kts
120 kts
151 kts
163 kts
Given: TAS: 225 kts HDG: 123° (T) W/V: 090° / 60 kts Calculate the track (°T) and GS.
134° - 188 kts.
134° - 178 kts.
120° - 190 kts.
128° - 180 kts.
Given: Heading: 305°(T) TAS: 135 kts W/V: 230°/40 kts What is the ground speed?
125 kts
130 kts
145 kts
97 kts
An aircraft has to fly over a mountain ridge. The highest obstacle, indicated in the navigation chart, has an elevation of 9 800 ft. The QNH, given by a meteorological station at an elevation of 6 200 ft, is 1022 hPa. The OAT ISA +5°C. Calculate the approximate indicated altitude to obtain a clearance of 2000 ft. Between:
11 800 ft and 12 000 ft
10 900 ft and 11 100 ft
11 900 ft and 11 200 ft
11 500 ft and 11 700 ft
The ICAO definition of ETA is the:
estimated time of arrival at destination.
actual time of arrival at a point or fix.
estimated time of arrival at an en-route point or fix.
estimated time en-route .
Given: TAS: 485 kts HDG: 168°(T) W/V: 130° / 75 kts Calculate the True track and GS.
173° - 424 kts.
175° - 432 kts.
175° - 420 kts.
174° - 428 kts.
Given: TAS: 190 kts True HDG: 085° WN: 110°(T) / 50 kts Calculate the drift angle and GS.
7°L - 156 kts.
8°L - 146 kts.
4°L - 168 kts.
4°R - 145 kts.
Given: TAS: 190 kts HDG: 355°(T) W/V: 165/25 kts Calculate the drift and GS.
1L - 225 kts.
1R - 165 kts.
1R - 175 kts.
1L - 215 kts.
Given: GS: 345 kts Distance from A to B: 3 560 NM What is the time from A to B?
10 hrs 05 min
10 hrs 19 min
11 hrs 00 min
11 hrs 02 min
Given: Mach number: 0.8 Flight level: 330 OAT: ISA +15°C TAS is approximately (compressibility factor 0.94):
450 kts
420 kts
480 kts
265 kts
What is the ratio between the litre and the US gallon?
1 litre equals 4.55 US-GAL
1 US-GAL equals 4.55 litres.
1 US-GAL equals 3. 78 litres.
1 litre equals 3.78 US-GAL
Given: Course: 040°(T) TAS: 120 kts Wind speed: 30 kts Maximum drift angle will be obtained for a wind direction of:
145°
120°
115°
130°
Given: TAS: 440 kts HDG: 349°(T) W/V: 040/40 kts Calculate the drift and GS.
2°L - 420 kts.
4°L - 415 kts.
6°L - 395 kts.
5°L - 385 kts.
Given: CAS: 324 kts FL290 OAT: -46°C What is the TAS?
473 kts
487 kts
458 kts
444 kts
An aircraft is flying at FL300. The OAT= ISA +15, the QNH given by a station at an elevation of 3000 ft is 1020 hPa. Use 1 hPa = 30 ft. Calculate the True Altitude (rounded to hundreds of feet):
31 800 ft
28 500 ft
22 500 ft
26 000 ft
What is the ISA temperature value at FL330?
-56°C
-66°C
-81°C
-51°C
Given: Pressure Altitude: 10000 ft OAT: +15°C What is true altitude:
9 260 ft
10 750 ft
8 480 ft
11 830 ft
Given: TAS: 270 kts True HDG: 270° Aaual wind: 205° (T) / 30 kts Calculate the drift angle and GS.
6°L - 256 kts.
6°R- 259 kts.
6°R - 251 kts.
8°R - 259 kts.
At 10:15 the reading from a VOR/DME station is 211°/90 NM, at 10:20 the reading from the same VOR/DME station is 211°/120 NM. compass Heading: 200° Variation in the area: 31°W Deviation: + 1° TAS: 390 kts The wind vector (T) is approximately:
110°/70 kts
100°/60 kts
110°/40 kts
120°/50 kts
For a given heading the: Wind component: +45 kts Drift angle: 15° left TAS: 240 kts What is the wind component on the reverse track?
-60 kts
-40 kts
-45 kts
-35 kts
If the headwind component is 50 kts, the FL is 330, temperature ISA -7°C and the ground speed is 495 kts, what is the Mach number?
0.78
0.98
0.95
0.75
