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Worksheets

Area and Equations

Total questions: 20

Worksheet time: 40mins

Name
Class
Date
1.

Which equation can be used to find A, the area of the parallelogram shown?

a)

A=½ (1.8)(2.5)

b)

A=(1.8)(2)

c)

A=½ (2)(2.5)

d)

A=(1.8)(2.5)

2.

Which equation could be used to find the area of the rectangle shown?

a)

A=½ (3.2)(7.5)

b)

A= (3.2)(7.5)

c)

A=(3.2)(7.5)÷2

d)

A=3.2+7.5

3.

A rectangular board has an area of A square inches. The width of the board is 12 inches. Which equation represents x, the length of the board in inches?

a)

x=A÷12

b)

x= 12 + A

c)

x=12÷A

d)

x =A- 2(12)

4.

Which equation could be used to find A, the area of the triangle shown?

a)

½(16+11)9.4

b)

½(16)(9.4)

c)

(16)(9.4)

d)

½(11)(9.4)

5.

The table shows the relationship between perimeter and area of four different squares. Which equation could be used to find A, the area of a square that has a perimeter of P units?

a)

A= (P÷4) x (P÷4)

b)

A=P- 4

c)

A= (P+4) x (P+4)

d)

A= P

6.

A triangular shaped candy has an area of A square inches. The base of the candy is 5 inches. Which equation represents x, the height of the candy in inches?

a)

x= 5÷A

b)

x= A-2.5

c)

x=½A+6

d)

x=A÷2.5

7.

Which equation could be used to find the area of the trapezoid shown?

a)

A= ½(7+4)2.8

b)

A=½(7+4)2

c)

A=½(7+4)2.2

d)

A=½(4)(2)

8.

Which equation could be used to find A, the area of the triangle shown.

a)

A=(11)(5.1)

b)

A=½ (11+8)5.1

c)

A= ½(11)(5.1)

d)

A=½(11)(8)+5.1

9.

The face of a lamp shade is shaped like a trapezoid. The dimensions of the face are shown in the diagram. Which equation could be used to find A, the area of the face of the lamp shade in square inches?

a)

A=½(6+10)y

b)

A=½(6+10)x

c)

A=½(6)+(10)x

d)

A=½(6)+(9)y

10.

Maggie wants to find the area of the parallelogram shown. Which method could she use to correctly find the area of the parallelogram?

a)

A=½(10)(6)

b)

A=(10)(6)

c)

A=(10)(7)

d)

A=½(10+6)7

11.

A triangle has a base length of 18cm, a height of 12cm, and a slant length of 15cm. Which of the following could be used to find A, the area of the triangle?

a)

½ (18+12)15

b)

½ (18)(12)

c)

½ (18)(12)(15)

d)

½ (15)(12)

12.

A rectangular computer screen has an area of A, square inches. The width of the computer screen is 7 inches. Which equation represents x, the length of the computer screen in inches?

a)

x= 7A

b)

A=x +7

c)

x= A/7

d)

x= 7/A

13.

A trapezoid has a top base of 20 inches and a bottom base of 25 inches. It has a height of 10 inches and 2 slants of 6 inches. Which equation could help you find the area of the trapezoid?

a)

A=½(20+25)10

b)

A= ½ (2)(6)

c)

A= ½ (2x6)10

d)

A= ½ (20+25)6

14.

The equation A= ½(10+20)12 could be used to find the area of which trapezoid below?

a)
b)
c)
15.

A square has an area of A square centimeters. If the base of the square is 12 centimeters, which of the following could be used to find h, the height of the square?

a)

h= (12+12)A

b)

h= A/12

c)

h= 12/A

d)

12=A-h

16.

Which equation below could be used to find A, the area of the parallelogram shown?

a)

A= ½ (5+5)4

b)

A= ½ (5)(4)

c)

A= (5)(4)

d)

A= (5)(5)

17.

The face of a gold bar is shaped like a trapezoid. The dimensions of the gold bar are shown in the diagram. Which equation could be used to find A, the area of the gold bar?

a)

A=½ (t+y)h

b)

A= xz

c)

A= ½ (x+z)h

d)

A= ½(x+z)y

18.

A triangle has a height of 5 inches, a base of 6 inches, and a lean height of 7 inches. Which of the following could be used to find the area of the triangle?

a)

A= ½ (6 x 7)

b)

A= ½ (6 x 5)

c)

A= ½ (5 x 7)

d)

A= ½ (6)(7)

19.

A parallelogram has a height of 22 inches and a base of 36 inches. Which equation could NOT be used to find A, the area of the parallelogram?

a)

A= (22)(36)

b)

A= (36)(22)

c)

A= 36 x 22

d)

A= ½ (36)(22)

20.

A triangle has an area of A square feet. Which of the following could be used to find A, the area of a triangle?

a)

A = ½ bh

b)

A= ½(b+b)h

c)

A= bh

d)

A=(b+b)h