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Worksheets

Special Right Triangles and Trigonometry

Total questions: 15

Worksheet time: 15mins

Name
Class
Date
1.

A 25ft ladder is leaning up against a wall. If the ladder makes a 63o with the ground, how far is the base of the ladder from the wall?

a)

12.4 ft

b)

11.3 ft

c)

22.3 ft

d)

49.1 ft

2.

Which Trig function would you use to solve for x ?

a)

Cosine

b)

Sine

c)

Pythagorean Theorem

d)

Tangent

3.

The ratio in a right triangle of opposite to adjacent side is _____

a)

sine

b)

cosine

c)

tangent

d)

inverse cosine

4.

Which ratio would you use to solve for x?

a)

sine

b)

cosine

c)

hypotenuse

d)

tangent

5.

Which equation would you use to solve for x?

a)

sin 62 = 10/x

b)

tan 62 = 10/x

c)

tan 62 = x/10

d)

cos 10 = x/62

6.

Which equation would you use to solve for x?

a)

sin 58 = x/19

b)

cos 58 = x/19

c)

sin 58 = 19/x

d)

cos 58 = 19/x

7.

Which represents the value of x?

a)

19*cos 55

b)

19/sin 55

c)

19*sin 55

d)

19/cos 55

8.

Find the value of sin Z.

a)

17/8

b)

8/15

c)

17/15

d)

15/17

9.

What would be the next step to solve for x?

a)

Multiply both sides by cos 75

b)

Divide both sides by cos 75

c)

Divide both sides by 75

d)

Multiply both sides by 11

10.

Which trig ratio would you use to solve for x?

a)

sine

b)

tangent

c)

cosine

d)

hypotenuse

11.

Which equation would be used to solve for x?

a)

tan 44 = x/15

b)

cos 44 = x/15

c)

cos 44 = 15/x

d)

tan 44 = 15/x

12.

I have been given the short leg in this 30-60-90 triangle.  How do I find the length of the hypotenuse?

a)

Multiply 4 by 2

b)

Multiply 4 by √3

c)

Multiply 4 by √2

d)

Divide 4 by √3

13.

I have been given the hypotenuse in this 30-60-90 triangle.  How do I find the short leg?

a)

Multiply 6 by 2

b)

Multiply 6 by √3

c)

Divide 6 by 2

d)

Divide 6 by √3

14.

The ratio in a right triangle of adjacent to hypotenuse is _____

a)

sine

b)

cosine

c)

tangent

d)

inverse cosine

15.

What is the measure of a?

a)

3

b)

333\sqrt{3}

c)

6

d)

323\sqrt{2}