WorksheetsPka and Pkb
Total questions: 11
Worksheet time: 8mins
calculate the Ka of a solution with a pKb of 3.38
3.38x10-11
6.76x10-11
2.40x10-11
2.39x10-11
calculate the pKb of solution with a pKa of 6.9
7.1
6.5
14
9.6
Calculate the Kb of a solution that has a pKb of 4.2
0.62
6.3x10-5
9.8
4.2
The magnitude of Kw indicates that ______________.
water autoionizes very slowly
water autoionizes very quickly
water autoionizes only to a very small extent
the autoionization of water is exothermic
How would you calculate Kb for the formate ion (HCOO–), given that the Ka for formic acid (HCOOH) is 1.8 × 10–4? (Kw=1.0 × 10–14)
Kb = Ka × Kw
Kb = Kw / Ka
Kb = Ka / Kw
Kb = Kw + Ka
In which of the following aqueous solutions does the weak acid exhibit the highest percentge of ionization?
.01 M HC2H3O2 . (Ka 1.8 x 10 -5)
.01 M HNO2 . ( Ka =4.5 x 10 -4)
.01 M HClO . (Ka= 3.0 x 10 -8)
.01 M HF (Ka= 6.8 x 10 -4)
HA is a weak acid. Which equilibrium corresponds to the equilibrium constant Kb for A-?
HA (aq) + H2O (l) <---> H2A+ (aq) + OH-(aq)
A- (aq) + H3O+ (aq) <---> HA (aq) + H2O (l)
HA (aq) + OH- (aq) <---> H2O (l) + H+ (aq)
A- (aq) + H2O (l) <---> HA (aq) + OH- (aq)
A- (aq) + OH- (aq) <---> HOA2- (aq)
A- is a weak base. Which equilibrium corresponds to the equilibrium constant Ka for HA?
HA (aq) + H2O (l) <---> H2A+ (aq) + OH- (aq)
A- (aq) + H3O+ (aq) <---> HA (aq) + H2O (l)
HA (aq) + H2O (l) <---> H3O+ (aq) + A- (aq)
A- (aq) + H2O (l) <---> HA (aq) + OH- (aq)
A- (aq) + OH- (aq) <---> HOA2- (aq)
Using the data in the table, which of the conjugate bases below is the weakest base?
OAc-
C7H5O2-
NO2-
F-
OAc- and C7H5O2-
Using the data in the table, which of the conjugate acids below is the weakest acid?
HClO
HCO3-
H2S
NH3CH3+
H2S and HClO
Z- is a weak base. An aqueous solution of NaZ is prepared by dissolving 0.350 mol of NaZ in sufficient water to yield 1.0 L of solution. The pH of the solution was 8.93 at 25.0 0C. What is the Kb of the solution?
1.2 x 10-5
6.9 x 10 -9
2.1 x 10 -10
2.8 x 10 -12
