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WorksheetsChange of Base, Graphs of Exponentials/Logs, Properties of Logs
Total questions: 122
Worksheet time: 10hrs 31mins
Condense the Logarithm 5loga − 25logb
log (a5+b25)
log (a5−b25)
log (ab)25
log (b25a5)
Condense 3logx+4logy +logz
log x3y4z
12log xyz
log 3x4yz
Condense: log4(x+4)−log4(x−5)
log49
log4(2x−1)
log4(x+4)(x−5)
log4(x−5x+4)
Condense: 2log3(11x)
log3(22x)
log3(121x)
log3(11x)2
log3(11x2)
Expand using the properties of Logaritms log y4zx3
logx+4logy +logz
3logx−4logy −logz
3logx+4logy +logz
3logx−4logy +logz
Expand the logarithm.
logy6x
logx+6logy
logx−6logy
logx+log6y
logx−log6y
Expand . log6(y5x3)
log65x3−log6y
log65+log6x3−log6y
log65+3log6x−log6y
log65+3log6x+log6y
What is the correct transformed equation for the graph?
y = log(x - 4)
y = log(x) - 4
y = log(x + 4)
y = log(x) + 4
What is the equation of the asymptote on the graph of y=log5(x+3)+5 ?
x = -3
x=5
y= -3
y=5
Which of the following has a vertical asymptote at x=4
y=2x−4
y=log2(x−4)
y=2x+4
y=log2(x+4)
What is the transformation of the logarithmic function
f(x)=log (x+3)−1
left 3, right 1
right 3, down 1
right 3, up 1
left 3, down 1
Which graph matches the function?
Which is the product property of logarithms?
logb(x⋅y) =logbx +logby
logb(yx) = logbx − logby
logbxn=nlogbx
What is the quotient property of logarithms?
logbxn=nlogbx
logb(yx)=logbx −logby
logb (x⋅y)=logbx + logby
Which is the power property of logarithms?
logb(x⋅y)=logbx +logby
logb(yx) = logbx −logby
logb xn =nlogbx
Expand: logb nm
logbm −logbn
logbm + logb n
mlogbn
nlogbn
Expand: log 2k3
3log2 − logk
3logk−log2
3logk+log2
logk−3log2
Expand: ln x5y2
5lnx + ln2y
lnx5y2
5lnx + 2lny
5lnx - 2lny
Condense: log25+log2x
log2x5
log2 x5
log2 5x
log25x
Condense: log65−log62
log610
log6 25
log6 52
log6 52
Condense: 3log4x
log4 3x
log4x3
log4 3x
log4 3x
Condense: 4log5k−log5d
log5k4d
log5 4kd
log5 dk4
log5 d4k
Condense: 4logp+2logq−3logr
log p4q2r3
log q2r3p4
log 3r8pq
log r3p4q2
Condense: 3lnx + 8lny
ln(y8x3)
ln(x3y8)
24ln(xy)
11ln(xy)
Condense the logarithmic expression.
A
B
C
D
21log4 9
Condense into a single logarithm. Simplify if possible.
log18
log4 29
log44.5
log43
Condense this expression to a single logarithm.
log312
Which of the following is a possible expansion for this logarithm? Check all that apply.
log34+log33
log310+log32
log32+log36
log336−log33
log315−log33
Use the properties of logarithms to rewrite as the difference of two logs:
log545log590 −log52
log515−log53
log 5log45
log550−log55
Rewrite as a single logarithm:
log 10
log 21
log 3/7
log 3/log 7
Rewrite as a single logarithm: log65−log62
log610
log6 25
log6 52
log6 52
Rewrite as a single logarithm:
log260 − log210 log26
log250
log210log260
log270
Condense: 3log4x
log4 3x
log4x3
log4 3x
log4 3x
Expand: log(23)
log3+log2
3log2
log(3−2)
log3−log2
Use the properties of logarithms to rewrite as the sum of two logarithms:
log55log 40 + log 15
log 50 + log 5
log 11 + log 5
Which of the logarithms below is equivalent to the following:
2log12
log 10
log 6
log 24
log 144
Simplify: log432+log42
(a)
Simplify:
log354 - log32
(a)
Simplify: log13136
(a)
Simplify 10log47
(a)
Use these and other properties of logarithms to evaluate the expression.
log232 − 6log63
(a)
log(4x)
log4-logx
log4+logx
4logx
xlog4
log(xy2)
logx+2logy
logx+logy2
logx-2logy
logx+logy+log2
log(yz8x)
log8+logx-logy-logz
log8+logx-logy+logz
log(8x)-log(yz)
8logx-ylogz
Which equation is the inverse of the equation above?
Logarithmic functions have...
Vertical asymptote at x=0
Vertical asymptote at x=1
Horizontal asymptote at y=1
Horizontal asymptote at y=0
Find the corresponding graph of
log3(x−1)+4
Which graph matches the equation
Change log122 into the form of logbloga , where a and b are integers
log2log12
log12log2
Use the Change of Base Formula to evaluate the expression.
log92723
32
31
3
Solve the log by using change of base
log432
8
5/2
2/5
3/2
Simplify 2⋅lne5
(a)
Use the change of base rule to expand this problem:
log(35)
ln(35)log(10)
ln(10)log(35)
log3(10)log3(35)
log9(35)log9(10)
Evaluate log55
(a)
Evaluate log7491
(a)
Evaluate the following logarithm:
log8127
2/3
3/2
3/4
4/3
Evaluate the following logarithm:
log66
(a)
Evaluate the following logarithm:
log25125
2/3
3/2
3/4
1/2
Evaluate the following logarithm:
log84
2/3
3/2
3/4
1/2
Determine the range for the function.
f(x)=2x−4+5
y > 4
y > 2
y > 3
y > 5
Write the equation of the function f(x)=log3x after the following transformations:
Translate 6 units left and 4 units up.
g(x)=log3(x+6)+4
g(x)=log3(x+4)-6
g(x)=log3(x-6)+4
g(x)=3log(x+6)+4
Solve log2(x+8)=log264
x=16
x=24
x=56
x=40
Solve log8(3x+7)=log8(7x+4)
x=43
x=3
x=6
x=34
Solve log2(2x - 3) = log2(4x + 5)
4
-4
-.33
.33
Condense into a single log:
log67
log64
log6310
log9(r−8) = 2
55
611
89
6
-10log2 x + 8 = -12
8
12
1296
4
6 + log2 x = 6
9
101
1
121
log2(x2 - 6) = log2(2x+2)
4, -2
No Solution
4
-2
logx1000=3
1
10
30
3
log8(4x+4)=2
15
12
10
3
x is undefined
x = 2
x= 0.4
x = 33
LNe
ln(2x) + ln(y) - ln(z)
5 ln(x) = 7
4 - 3 ln(2x + 10) = 12
5 ln (3x - 2) = 15
ln3x + ln2x = 3
ln2x - ln41 = 2
e^(x + 6) = 12
7e^(3x - 5) = 49
Solve log9 (x - 4) + log9 (x + 1) = log9 (x + 5) + log9 (x - 6)
17/2
-9/16
13
-8
Change to Exponential Form:
log636 = 2
26=36
62=36
362=6
366=2
ln (5x + 6) = 5
154.413
30.883
147.213
28.483
Solve the following equation for x. Round your solution to two decimal places.
ln3+ ln2 = x
x = 12.91
x = 4.02
x = 3.35
x = 1.79
ln e
1
0
e
ee
ln3x + ln2x = 3
Solve for x
x = 1/4
x = 4
x = 3
x = 1/3
Solve:
log2(x + 3)=5
x=2
x=29
x=7
x=32
Solve the equation for x.
7.389
0.693
0.0183
6.581
Solve for x:
log(x+6) = 1
4
4.222
-5
-9.550
Solve for x: 32x – 6 = 81
Solve for n: 7n+10- 8 = 6
-8.644
Determine the equation of the asymptote?
x=3
x=4
y=-4
y=4
Determine the equation of the asymptote?
x=5
y=-5
y=2
x=-5
Solve:
5(6)3x=202.3
.26
.04
4
Solve for x
log4(x+5)+log4(7)=2log4(6)
(a)
Solve for x
5(x−7)−9=23
Give answer as a decimal approximation (3 decimal places)
(Do not put spaces in your answer)
Remember to put the log argument in parenthesis
(a)
Solve for x
2(x+7)+2=16
Give answer as a decimal approximation (3 decimal places)
(Do not put spaces in your answer)
Remember to put the log argument in parenthesis
(a)
