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x3+3x2+3x+1=(x+a)2x^3+3x^2+3x+1=\left(x+a\right)^2x3+3x2+3x+1=(x+a)2 a에 들어갈 숫자는? (a)
x3+4x2−2x+5x^3+4x^2-2x+5x3+4x2−2x+5 를 x+1x+1x+1 로 나눈 나머지는? (a)
x3−5x2+8x−4=(x−a)(x−2)2x^3-5x^2+8x-4=\left(x-a\right)\left(x-2\right)^2x3−5x2+8x−4=(x−a)(x−2)2 에서 a의 값은? (a)
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