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WorksheetsUnderstanding Capacitors and Capacitance
Total questions: 30
Worksheet time: 22mins
What is the formula for capacitance?
C = Q/V
C = V/Q
C = V^2/Q
C = Q*V
If a capacitor has a capacitance of 10 µF and a voltage of 5 V, what is the charge stored?
5 µC
100 µC
50 µC
20 µC
How do you calculate the total capacitance of capacitors in series?
C_total = 1 / (1/C1 + 1/C2 + ... + 1/Cn)
C_total = max(C1, C2, ..., Cn)
C_total = C1 * C2 / (C1 + C2)
C_total = C1 + C2 + ... + Cn
If two capacitors of 4 µF and 6 µF are in series, what is the total capacitance?
3.6 µF
2.4 µF
5 µF
1.2 µF
What is the formula for total capacitance of capacitors in parallel?
C_total = C1 + C2 - C3 + ... + Cn
C_total = C1 * C2 * C3 * ... * Cn
C_total = 1/(1/C1 + 1/C2 + 1/C3 + ... + 1/Cn
C_total = C1 + C2 + C3 + ... + Cn
If three capacitors of 2 µF, 3 µF, and 5 µF are in parallel, what is the total capacitance?
8 µF
7 µF
10 µF
6 µF
What happens to the total capacitance when capacitors are added in series?
The total capacitance decreases.
The total capacitance fluctuates.
The total capacitance remains the same.
The total capacitance increases.
What happens to the total capacitance when capacitors are added in parallel?
The total capacitance increases.
The total capacitance decreases.
The total capacitance becomes zero.
The total capacitance remains the same.
Can a capacitor store energy? If so, how is it calculated?
Energy in a capacitor is calculated using E = C * V.
Capacitors only store energy when connected to a resistor.
No, capacitors cannot store energy.
Yes, a capacitor can store energy, calculated using E = 1/2 * C * V^2.
What is the unit of capacitance?
watt
farad
ohm
volt
With respect to the capacitor, which relationship is true? •
C = Q×V
V = C×Q
V = Q/C
Q = C/V
How is the capacitance (C) of a parallel-plate capacitor affected by the charge on the plates ?
C depend on the charge on the plates
C is vanished when there are plates
C does not depend on the charge on the plates
C is accumulated on one side only
How is the capacitance of a parallel-plate capacitor affected by the potential difference across the capacitor ?
C depend on the potential difference across the capacitor
C does not depend on the potential difference across the capacitor
C partially depend on the potential difference across the capacitor
C sometime depend on the potential difference across the capacitor
How is the capacitance of a parallel-plate capacitor affected by the area of each plate?
C is directly proportional to the area A of each plate
C is inversely proportional to the area A of each plate
C is partially proportional to the area A of each plate
C is fully proportional to the area A of each plate
How is the capacitance of a parallel-plate capacitor affected by the distance between the plates ?
C is directly proportional to the area A of each plate
C is inversely proportional to the distance d between the plates
C is partially proportional to the area A of each plate
C is not affected by the area A of each plate
How is the capacitance of a parallel-plate capacitor affected by filling the space between the plates with an insulator ?
C stable when the space between the plates is filled with an insulator, εr >1
C reduces when the space between the plates is filled with an insulator, εr >1
C increases when the space between the plates is filled with an insulator, εr >1
C fluctuate when the space between the plates is filled with an insulator, εr >1
The plates of a parallel-plate capacitor are 2.50mm apart, and each carries a charge of magnitude 80.0nC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00x106V/m. What is the potential difference between the plates?
2.00x104V
1.75x104 P.D.
1.00x10-4P
1.00x104V
not solvable! because capacitor has no potential difference because it should have an insulator in between.
from question 16:
The plates of a parallel-plate capacitor are 2.50mm apart, and each carries a charge of magnitude 80.0nC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00x106V/m.
What is the area of each plates?
2.26x10-3cm2
2.26x10-3m2
22.6m2
2.26cm2
none of the above
The plates of a parallel-plate capacitor are 2.50mm apart, and each carries a charge of magnitude 80.0nC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00x106V/m.
what is the capacitance?
zero
same as potential difference 4.00pF
8.99pF
8pF
8.00x10-9F
Is it correct to say that the capacitance is inversely proportional to the area of the parallel plates?
True
False
Capacitor is a device use to store energy. Therefore a solar cell is a type of capacitor.
True
False
