Worksheetsunit 3-Strain Energy and Modulus of Resilience
Total questions: 20
Worksheet time: 20mins
What is strain energy?
Energy stored in a body due to deformation
Energy released during fracture
Kinetic energy of a moving body
Heat energy generated during loading
Strain energy is typically stored in a material when it is subjected to:
Compression only
Tension only
Any elastic deformation
Plastic deformation
The unit of strain energy is:
Newton (N)
Joule (J)
Pascal (Pa)
Watt (W)
Strain energy is a measure of:
Work done by external forces
Energy dissipated as heat
Energy stored due to elastic deformation
Permanent deformation energy
Proof resilience is defined as:
The maximum strain energy stored at failure
The maximum strain energy stored at the elastic limit
The total energy stored in a material
The energy required to break a material
Modulus of resilience is the proof resilience per unit:
Length
Area
Volume
Mass
The modulus of resilience is expressed in the unit:
J/m²
J/m³
N/m
N/m²
Which material property is directly related to the modulus of resilience?
Yield strength
Ultimate tensile strength
Hardness
Ductility
The strain energy stored in a bar under axial load is given by:
U = (P²L)/(2AE)
U = (PL)/(AE)
U = (P²L)/(AE)
U = (PL²)/(2AE)
For a bar under axial tension, strain energy depends on:
Load and material density
Load, length, area, and Young’s modulus
Length and temperature
Area and weight only
If the axial load on a bar is doubled, the strain energy stored will:
Remain the same
Double
Increase by four times
Decrease by half
The strain energy in a bar is zero when:
The load is applied gradually
The bar is not deformed
The bar is plastically deformed
The bar is under shear stress
When a load is applied suddenly to a bar, the instantaneous stress is:
Equal to gradually applied stress
Twice the stress due to gradual loading
Half the stress due to gradual loading
Zero
For a sudden load, the instantaneous stress is calculated as:
σ = P/A
σ = 2P/A
σ = P/(2A)
σ = P²/(AE)
In an impact load, the stress depends on:
Height of drop and material properties
Load weight only
Bar length only
Temperature of the bar
The instantaneous stress due to an impact load is generally:
Lower than sudden load stress
Higher than sudden load stress
Equal to sudden load stress
Zero
A bar with cross-sectional area 100 mm² is subjected to a sudden load of 10 kN. What is the instantaneous stress?
50 MPa
100 MPa
200 MPa
25 MPa
A bar of length 1 m, area 50 mm², and E = 200 GPa is subjected to a sudden load of 5 kN. What is the deformation?
0.5 mm
1 mm
2 mm
0.25 mm
A weight of 2 kN falls from a height of 0.1 m onto a bar with A = 100 mm² and E = 100 GPa. The instantaneous stress is approximately (assume basic impact formula):
20 MPa
200 MPa
400 MPa
100 MPa
A bar under an impact load of 10 kN with h = 0.05 m, A = 200 mm², L = 1 m, and E = 200 GPa has a deformation of approximately:
0.5 mm
1.25 mm
2.5 mm
0.1 mm
