WorksheetsOptional - Cell Membrane, Cell Transport, and Water Potential
Total questions: 25
Worksheet time: 25mins
Which of the following processes includes all others?
osmosis
facilitated diffusion
passive transport
simple diffusion
Celery stalks that are immersed in fresh water for several hours become stiff and hard. Similar stalks left in a salt solution become limp and soft. From this we can deduce that the cells of the celery stalks are
hypertonic to both fresh water and the salt solution.
hypotonic to both fresh water and the salt solution.
hypertonic to fresh water but hypotonic to the salt solution.
hypotonic to fresh water but hypertonic to the salt solution.
What forms the channels and pumps in the phospholipid bilayer?
carbohydrates
proteins
hydrophilic heads
lipids
Phospholipids have a -
nonpolar head and a nonpolar tail.
polar head and a polar tail.
nonpolar head and a polar tail.
polar head and a nonpolar tail.
Fewer molecules move from a region of low concentration to high concentration because molecules in the lower concentration area _______________.
have fewer molecular collisions than molecules in the higher concentration area.
vibrate more than molecules in higher concentration areas.
vibrate less than molecules in the higher concentration area.
have more molecular collisions than molecules in the higher concentration area.
Five dialysis bags, constructed from a semi-permeable membrane that is impermeable to sucrose, were filled with various concentrations of sucrose and then placed in separate beakers containing an initial concentration of 0.6 M sucrose solution. At 10-minute intervals, the bags were massed (weighed) and the percent change in mass of each bag was graphed.
Which line represents the bag that contained a solution isotonic to the 0.6 molar solution at the beginning of the experiment?
A
B
C
D
E
A dialysis-tubing bag is filled with a mixture of 3% starch and 3% glucose and placed in a beaker of distilled water, as shown in the image. After 3 hours, glucose can be detected in the water outside the dialysis-tubing bag, but starch cannot.
From the initial conditions and results described which of the following is a logical conclusion?
The initial concentration of glucose in the bag is higher than the initial concentration of starch in the bag.
The pores of the bag are larger than the glucose molecules but smaller than the starch molecules.
The bag is not selectively permeable.
A net movement of water into the beaker has occurred.
The molarity of the solution in the bag and the molarity of the solution in the surrounding beaker are the same.
The Ψ of a root cell is -3 bars and the Ψ of the surrounding solution is -2 bars. Which direction will the net flow of water be?
Into the root cell
Into the surrounding solution
There will be no net flow of water in either direction.
There is no way to make this prediction.
What is NOT true about water potential?
Water flows from a more negative Ψ to a less negative Ψ.
Water flows from high water potential to low water potential.
Ψ = Ψs + Ψp
The pressure potential (Ψp) of an open beaker is equal to 0 bars.
If a plant cell has a water potential of -2 bars and a pressure potential of 2 bars, what is the cell's solute potential?
4 bars
0 bars
-4 bars
2 bars
The value for Ψ in root tissue was found to be -3.3 bars. If you take the root tissue and place it in a 0.1 M solution of sucrose at 20 ° C in an open beaker, what is the Ψ of the solution, and in which direction would the net flow of water be?
Ψs = -3.3, net flow into the root
Ψs = 3.3, net flow out of the root (into the solution)
Ψs = -2.43, net flow into the root
Ψs = 2.43, net flow out of the root (into the solution)
