Free Printable Day 46-Nov 6-worksheet-Btech-Superelevation & extrawidening

1.

Centrifugal ratio or impact factor on a horizontal curve is given by —

a)

$P \times W$

b)

$P/W$

c)

$gR/W$

d)

$W/gR$

2.

Overturning of a vehicle begins when —

a)

$P/W = f$

b)

$P/W \ge b/2h$

c)

$P\times W\le f$

d)

$P\div W<b/2h$

3.

The relation between super elevation (e), friction (f) and speed (V) is —

a)

$e - f = V^2/127R$

b)

$e + f = V^2/127R$

c)

$e/f = 127V^2R$

d)

$e \times f = 127R/V^2$

4.

At equilibrium, super elevation e is —

a)

$V^2/225R$

b)

$V^2/127R$

c)

$127R/V^2$

d)

None

5.

Maximum super elevation for plain terrain is —

(a)

6.

Mechanical widening for a two‑lane road with wheelbase 6 m and curve radius 120 m is —

(a)

7.

Super elevation is provided to counteract centrifugal force.

a)

True

b)

False

8.

Psychological widening depends only on wheelbase and number of lanes.

a)

True

b)

False

9.

Assertion (A): Rotation about inner edge is suited for flat terrain. Reason (R): It avoids drainage problems and needs less earthwork. Choose the correct statement.

a)

A and R are true, and R explains A

b)

A and R are true, but R does not explain A

c)

A is true, R is false

d)

Both are false

10.

At equilibrium super elevation, the pressure on the inner and outer wheels are —

(a)

11.

Which expression correctly gives the total extra widening $W_e$ ?

a)

$W_e = \frac{n \times l^2}{2R} + \frac{V}{9.5 \times \sqrt{R}}$

b)

$W_e = \frac{l^2}{2R} + \frac{nV}{9.5 \times R}$

c)

$W_e = \frac{n \times l}{2R} + \frac{V^2}{9.5 \times \sqrt{R}}$

d)

$W_e = \frac{n \times l^2}{R} + \frac{V}{127 \times R}$

12.

In the off‑tracking formula $O = \frac{l^2}{2R}$ , the parameter l denotes —

a)

Wheelbase of the vehicle

b)

Lane width

c)

Radius of the curve

d)

Vehicle speed

13.

If the curve radius is greater than 300 m, the extra widening provided is —

(a)

14.

For $V = 100$ km/h, $e = 0.08$ , and $f = 0.12$ , the absolute minimum radius is —

(a)

15.

Calculate the total extra widening for a three‑lane road with $R = 100$ m, wheelbase $l = 6$ m, and $V = 95$ km/h .The result is —

(a)

Day 46-Nov 6-worksheet-Btech-Superelevation & extrawidening

Total questions: 15

Worksheet time: 11mins

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