Free Printable Phy 2D vector -L1

1.

A 2-dimensional vector has _____________ and ___________ components.

a)

horizontal; vertical

b)

positive; negative

c)

superficial; deep

d)

long; short

2.

$\cos\alpha\ =$

a)

adjacent leg / hypotenuse

b)

opposite leg / hypotenuse

c)

adjacent leg / opposite leg

3.

$\sin\alpha\ =$

a)

opposite leg / adjacent leg

b)

opposite leg / hypotenuse

c)

adjacent leg / hypotenuse

4.

$\tan\alpha$ =

a)

a/b

b)

a/c

c)

b/c

5.

Which side is adjacent to the 40⁰ angle?

a)

AB

b)

AC

c)

BC

6.

See Sample Problem B on page 91. Which of the following equations is equal to

$\sin\theta\ =\ \frac{y}{v}$ ?

a)

$y\ =\ v\sin\theta$

b)

$v\ =\ y\sin\theta$

c)

$\sin v\ =\ y$

7.

See Sample Problem B on page 91. Which of the following equations is equal to

$\cos\theta\ =\ \frac{x}{v}$ ?

a)

$x\ =\ v\ \cos\theta$

b)

$v\ =\ x\ \cos\theta$

c)

$\sin\theta\ =\ xv$

d)

$\frac{\cos\theta}{x}=v$

8.

A vector has a magnitude of 22 and is directed at an angle of 60 degrees. What are its components in the x and y direction?

a)

x component = 22 * tan(60°), y component = 22 * cos(60°)

b)

x component = 22 * cos(60°), y component = 22 * sin(60°)

c)

x component = 22 * cos(60°), y component = 22 * tan(60°)

d)

x component = 22 * sin(60°), y component = 22 * cos(60°)

9.

What is the y component of the vector in the diagram?

a)

104N

b)

60N

c)

-104N

d)

95N

10.

Calculate the x and y components of the given vector.

(a)

11.

What is the y component of the vector in the diagram?

a)

104N

b)

-60N

c)

60N

d)

95N

12.

What is the x component of the vector in the diagram?

a)

104N

b)

-60N

c)

60N

d)

95N

13.

What is the x component of the vector in the diagram?

a)

104N

b)

60N

c)

-104N

d)

95N

14.

For a ball launched to the right at a velocity of 20 m/s at an angle of 30 degrees above the horizontal, choose the correct velocity components for the ball:

a)

v_x = 20 m/s

b)

v_x = 10 m/s

c)

v_y = 17.3 m/s

d)

v_y = 10 m/s

e)

v_x = 17.3 m/s

15.

Pythagorean theorem states that...

a)

C² = √(A + B)

b)

C² = √(A² + B²)

c)

C² = √(A² - B²)

d)

C² = (A + B)²

16.

If we know A and B. We can calculate the angle α by using this trig. function

a)

tan^-1(B/A)

b)

cos^-1(B/A)

c)

sin^-1(B/A)

d)

cos(A/B)

17.

If two vectors to be added are at right angles, you will need to....

a)

Multiply

b)

Divide

c)

Pythagorean Theorem

d)

Use trigonometry

18.

Solve for the missing angle

a)

50.5 degrees

b)

12.7 degrees

c)

36.9 degrees

d)

72.2 degrees

19.

Find the direction and magnitude of the resultant vector for the drawing of two forces.

a)

Direction 90°
Magnitude 139.0N

b)

Direction 52.3°
Magnitude 195N

c)

Direction 52.3°
Magnitude 139.0N

d)

Direction 37.7°
Magnitude 139.0N

20.

Given the x and y components, find the magnitude and direction of the vectors below.【合成，找到大小及角度】

(a)

21.

Check out this super cool vector (☞ﾟヮﾟ)☞

Calculate the horizontal component of the velocity

a)

69 m/s

b)

20 m/s

c)

35 m/s

d)

23 m/s

22.

Aww snap, it's another vector (☞ﾟヮﾟ)☞

Find the vertical component of its velocity

a)

52 m/s

b)

30 m/s

c)

35 m/s

d)

9 m/s

23.

Determine the components of the following vectors.

a)

Cx = 10.4 m

Cy = 6 m

b)

Cx = 6 m

Cy = 10.4 m

c)

Cx = 6.2 m

Cy = 29.3 m

d)

Cx = 29.3 m

Cy = 29.3 m

24.

Determine the components of the following vectors.

a)

Cx = 10.9 m

Cy = 43.7 m

b)

Cx = 43.7 m

Cy = 10.9 m

c)

Cx = 9.9 m

Cy = 9.9 m

d)

Cx = 29.3 m

Cy = 29.3 m

25.

Dana throws a baseball with an initial velocity of 20.2 feet per second at an angle of 69° with the horizontal. Find the initial vertical and horizontal velocity of the ball.

a)

Horizontal 18.9

Vertical 7.2

b)

Horizontal 7.2

Vertical 18.9

c)

Horizontal 15.2

Vertical 9.6

d)

Horizontal 9.6

Vertical 15.2

26.

Page 92, #3. A truck drives up a hill with a 15 degree incline. if the truck has a constant speed of 22 m/s, what are the horizontal and vertical components of the truck's velocity?

a)

21 m/s, 5.7 m/s

b)

21 m/s, 15 m/s

c)

7.5 m/s, 5.7 m/s

d)

19.2 m/s, 10 m/s

27.

Page 92, #4. What are the horizontal and vertical components of a cat's displacement when the cat has climbed 5 meters directly up a tree?

a)

horizontal: 5 m

vertical: 0 m

b)

horizontal: 0 m

vertical: 5 m

c)

horizontal: 5 m

vertical: 5 m

d)

horizontal: -5 m

vertical: 5 m

Phy 2D vector -L1

Total questions: 27

Worksheet time: 45mins

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