WorksheetsRadical Functions
Total questions: 88
Worksheet time: 5hrs 37mins
What would be the radicand, if the following expression were rewritten in radical form?
5(xy)5/6
5
x
5/6
xy
What would be the root index, if the following expression were rewritten in radical form?
12x5/8
12
8
5
x
What is the root index for the square root of 9?
1
2
3
4
Rewrite the expression using a rational exponent.
4xy11
xy44
(xy)11/4
(xy)4/11
simplify the following..
361/2
36
6
9
18
If the rational exponent of an expression is 5/2, what is the exponent when written in radical form?
5/2
5
2
10
Which of the following does not simplify to an integer?
272/3
161/2
If rewritten with a radical exponent, which of the following would be the base of the expression provided?
6xy
6x
xy
8/3
Simplify the following
4
9
2
3
13
169
21
21972/3
What would be the root index if the following expression were written in radical form?
12x2/3
The implied root index
2
There is no root index..
3
Simplify the given expression.
49-1/2
7
1/72
1/492
1/7
√20a²b⁴
√98b
√45n3
The expression x33 is equivalent to
x16x
x4x
x8x
x2x
A
B
C
D
A
B
C
D
Solve the equation. Remember to check for extraneous solutions.
−7+8p=−3
p=−5
p=2
p=9
p=−10, 9
Solve the equation. Remember to check for extraneous solutions.
−5=7x+2−9
x=−10, 8
no solution
x=2
x=8
Solve the equation. Remember to check for extraneous solutions.
−48=−610x
x=640, 9
no solution
x=−2
x=640
Solve the equation. Remember to check for extraneous solutions.
−1−x=−8−2x
x=7
x=−7
x=−7, 7
no solution
Solve the equation. Remember to check for extraneous solutions.
2x+11=x+10
x=−1
x=1
x=−2
no solution
Solve the equation. Remember to check for extraneous solutions.
10m=2m−171
m=9
m=2
m=90
no solution
Solve the equation. Remember to check for extraneous solutions.
−1−2n=3−n
n=−1
n=−4
n=−5
n=4
Solve the equation. Remember to check for extraneous solutions.
x=−1−2x
x=−1, 1
x=1
x=−1
no solution
Solve the equation. Remember to check for extraneous solutions.
40−3k=k
k=−8
k=−8, 3
k=5
k=−8, 5
Solve the equation. Remember to check for extraneous solutions.
n=−21+10n
n=3
n=7
n=3, 7
no solution
Solve the equation. Remember to check for extraneous solutions.
6−b=b
b=2
b=−3
b=2, −3
no solution
Which function represents the given graph?
Adding or subtracting outside of the square root moves the function up and down. Ex. x+3
True
False
Adding or subtracting inside of the square root moves the function left and right. Ex. x−2
True
False
What is the equation for this graph?
x−4
x+4
x−4
x+4
What is the range of this graph? (output values)
(4, infinity)
(infinity, 4)
(-4, 4)
(-infinity, infinity)
What is the equation for this graph?
x−2
x+2
x−2
x+2
What is the equation for this graph?
x+3−2
x+3+2
x−3−2
x−3+2
What is the equation for this graph?
x+4−1
x+4+1
x−4−1
x−4+1
What is the domain for this graph? (input values)
(2, infinity)
(infinity, 2)
(-2, 2)
(-infinity, infinity)
Which of these equations shifts a radical equation right 5 times and down once?
y = √(x - 5) - 1
y = √(x + 5) - 1
y = √(x - 5) + 1
y = √(x + 5) + 1
What type of function is shown?
cube root
square root
logarithm
exponential
What are the transformations of this functions compared to the parent function?
Shifted down 2
Shifted up 2
Shifted left 2
Shifted right 2
Which of these equations shifts a radical equation left 3 times?
y = √(x) + 3
y = √(x) - 3
y = √(x + 3)
y = √(x - 3)
Which equation is shown graphed?
y = 2√(x)
y = −2√(x)
y = −½√(x)
y = ½√(x)
Describe the transformation.
Down 1
Reflect over y-axis
Up 1
Reflect over x-axis
What are the transformations for the graph of
the parent function f(x) = √x to the function above
Vertical Stretch by a factor of 2; translated down 5 units
Shifted right 2 units and down 5 units
Vertical stretch by a factor of 2; translated left 5 units
Vertical stretch by a factor of 2; translated right one unit
Describe the transformation.
Vertical Stretch by 2
Vertical Shrink by ⅓
Horizontal Shrink by ⅓
Horizontal Stretch by 3
Pick the equation that shows a stretch of 2 and a shift up of 3
y=2√(x+3)
y=2√(x)-3
y=3√(x)2
y=2√(x)+3
Pick the equation that shows a reflection over the x-axis, a stretch of 4, a shift left 5, and a shift up 1
y = 4√(x+5)+1
y = - 4√(x+5)+1
y = - 5√(x+4)+1
y = - 4√(x-5)+1
Describe the transformation.
right 5
left 5
up 5
down 5
What is the domain of this graph?¿Cuál es el dominio de esta gráfica?
x ≥ -1
x ≤ -1
x ≥ 0
x ≤ 0
State the domain and range of h(x)=x−0.5−6.3 .
D: [0.5,∞)
R: [−6.3,∞)
D: [−0.5,∞)
R: [−6.3,∞)
D: [−6.3,∞)
R: [0.5,∞)
D: (0.5,∞)
R: (−6.3,∞)
Describe the translation of the function y=2+3 x+1 .
left 1 unit, down 2 units, vertical stretch by 3
left 1 unit, up 2 units, vertical stretch by 3
left 1 unit, up 2 units, vertical stretch by 1/3
right 1 unit, up 2 units
What is the domain for:
g(x) = √(x + 5) - 3
A
-3 ≤ x < ∞
B
− ∞ < x ≤ -3
C
-5 ≤ x < ∞
D
− ∞ < x ≤ -5
Which function matches the graph?
A
f(x) = ∛(x + 3) + 2
B
f(x) = − ∛(x - 3) + 2
C
f(x) = ∛(x - 3) + 2
D
f(x) = ∛(x - 2) + 3
What is the Range for the graph?
A
2 ≤ y < ∞
B
− ∞ < y ≤ 3
C
3 ≤ y < ∞
D
− ∞ < y < ∞
Which function matches the graph?
A
f(x) = − ∛(x + 3) − 1
B
f(x) = − ∛(x - 3) − 1
C
f(x) = ∛(x + 3) − 1
D
f(x) = ∛(x - 1) + 3
The range is y ≥ 1
It has been reflected over the y-axis
The function has been shifted up 1 unit
The function has been shifted up 2 units
Shifted to the left 6
Identify the function that corresponds with the graph.
f(x)=3x+2−5
f(x)=3x−5+2
f(x) = 3x+5+2
Solve the cube root equation
900
990
0
90
None
Solve the cube root equation
78
-228
228
-78
None
Solve the cube root equation
-984
984
26
-26
None
Solve for x. Identify extraneous solutions, if any.
x = 4; x = - 8 is extraneous
x = - 8; x = 4 is extraneous
x = - 8; x = 4
no solution; x = - 8 and x = 4 are extraneous
Solve for x. Identify extraneous solutions, if any.
x = 4; x = - 8 is extraneous
x = - 8; x = 4 is extraneous
x = - 8; x = 4
no solution; x = - 8 and x = 4 are extraneous
Which function matches the graph?
A
f(x) = ∛(x + 3) + 2
B
f(x) = − ∛(x - 3) + 2
C
f(x) = ∛(x - 3) + 2
D
f(x) = ∛(x - 2) + 3
Which function matches the graph?
A
f(x) = − ∛(x + 3) − 1
B
f(x) = − ∛(x - 3) − 1
C
f(x) = ∛(x + 3) − 1
D
f(x) = ∛(x - 1) + 3
