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Diode and Semiconductor Fundamentals

Total questions: 30

Worksheet time: 15mins

Name
Class
Date
1.

For an ideal p–n junction germanium diode with reverse saturation current Is=10μAI_s = 10 \mu A at 300 K, what forward-bias voltage is needed to produce 100mA100 mA forward current? Use q=1.6×1019Cq = 1.6 \times 10^{-19} C and k=1.38×1023J/Kk = 1.38 \times 10^{-23} J/K .

a)

0.38 V

b)

0.26 V

c)

0.10 V

d)

0.98 V

2.

The diode equation for forward current in an ideal p–n junction is I=Is(eqV/(kT)1)I = I_s (e^{qV/(kT)} − 1) . When I ≫ I_s, which simplified expression most appropriately estimates V?

a)

V ≈ (kT/q) ln(I·I_s)

b)

V ≈ (kT/q) (I/I_s)

c)

V ≈ (q/kT) ln(I/I_s)

d)

V ≈ (kT/q) ln(I/I_s)

3.

At T = 300 K, the thermal voltage V_T = kT/q is approximately which value?

a)

0.062 V

b)

0.0062 V

c)

0.026 V

d)

0.16 V

4.

A PN-junction solar cell delivers photocurrent IL=1 mAI_L = 1 \text{ mA} . At its maximum power point, the terminal voltage is Vm=0.3 VV_m = 0.3 \text{ V} and the thermal voltage is VT=30 mVV_T = 30 \text{ mV} . Assuming the one-diode model with I=ILI0(eV/VT1)I = I_L - I_0 (e^{V/V_T} - 1) , what is the reverse saturation current I0I_0 ?

a)

41.3 nA

b)

1.00 nA

c)

0.41 nA

d)

4.13 nA

5.

In a solar cell modeled by the single diode equation I=ILI0(eV/VT1)I = I_L − I_0 (e^{V/V_T} − 1) , increasing V_T while keeping V_m fixed and I_L constant will have what qualitative effect on the required I_0 to satisfy I(V_m) = 0?

a)

I_0 increases because eVm/VTe^{V_m/V_T} decreases

b)

I_0 decreases because eVm/VTe^{V_m/V_T} decreases

c)

I_0 unchanged because V_m is fixed

d)

I_0 becomes zero at any V_T

6.

The intrinsic carrier concentration of a semiconductor is ni=2.5×1016m3n_i = 2.5 \times 10^{16} m^{−3} at 300 K. Electron and hole mobilities are μn=0.15m2/Vsμ_n = 0.15 m^{2}/V·s and μp=0.05m2/Vsμ_p = 0.05 m^{2}/V·s . Taking q=1.6×1019Cq = 1.6 \times 10^{−19} C , what is the intrinsic resistivity ρρ ?

a)

1.65 kΩ·m

b)

1.25 kΩ·m

c)

0.85 kΩ·m

d)

1.95 kΩ·m

7.

Using σ=qni(μn+μp)σ = q n_i (μ_n + μ_p) , what is the intrinsic conductivity for the semiconductor with ni=2.5×1016m3n_i = 2.5×10^{16} m^{−3} , μn=0.15m2/Vsμ_n = 0.15 m^{2}/V·s , μp=0.05m2/Vsμ_p = 0.05 m^{2}/V·s ?

a)

8.0 × 10410^{-4} S/m

b)

2.0×1042.0 \times 10^{-4} S/m

c)

8.0 × 10310^{-3} S/m

d)

2.0×1032.0 \times 10^{-3} S/m

8.

Which parameter primarily sets the exponential slope of the diode I–V characteristic in the ideal diode equation?

a)

Thermal voltage kT/q

b)

Series resistance of leads

c)

Junction capacitance value

d)

Reverse breakdown voltage

9.

A germanium diode and a silicon diode have the same reverse saturation current I_s at 300 K. For the same forward current I ≫ I_s, which statement about required forward voltage is most accurate?

a)

Both need zero V in practice

b)

Silicon needs lower V always

c)

Germanium needs higher V always

d)

Both need nearly same V if ideal

10.

If the intrinsic carrier concentration n_i doubles while mobilities remain constant, how does intrinsic resistivity ρ = 1/(q n_i (μ_n+μ_p)) change?

a)

It halves

b)

It doubles

c)

It remains same

d)

It increases fourfold

11.

For a diode with I_s = 10 μA at 300 K, what forward current corresponds to V = 0.238 V assuming I ≫ I_s? Use V_T = 25.9 mV.

a)

≈1 A

b)

≈100 mA

c)

≈10 mA

d)

≈1 mA

12.

Which element is a suitable n-type dopant when added to crystalline silicon?

a)

Boron from group III acceptors

b)

Gallium from group III acceptors

c)

Phosphorus from group V donors

d)

Indium from group III acceptors

13.

In an n-type semiconductor, the donor level ED is 0.25 eV below the conduction band edge EC. Which statement best describes the position of EF if ED − EF = 0.18 eV?

a)

EF lies 0.43 eV below EC

b)

EF lies 0.18 eV above EC

c)

EF lies 0.07 eV below EC

d)

EF coincides exactly with EC

14.

Five percent of donor atoms remain neutral in an n-type semiconductor. What fraction of donor atoms are ionized?

a)

Ninety-five percent of donors

b)

One hundred percent of donors

c)

Fifty percent of donors

d)

Five percent of donors

15.

For a donor level with degeneracy factor g = 2, which term appears in the expression for electrons occupying the donor level nd = 1 + g exp[(kT ED − EF)] Nd?

a)

A factor accounting for level degeneracy

b)

A term for lattice vibration energy

c)

A correction for bandgap narrowing

d)

A coefficient for recombination velocity

16.

Given EC − EF = 0.25 eV and ED − EF = 0.07275 eV from VT ln(38), what is the numerical value of EC − ED?

a)

0.17725 eV difference

b)

0.32275 eV difference

c)

0.07275 eV difference

d)

0.25000 eV difference

17.

In an extrinsic semiconductor, the hole concentration is p=1.5nip = 1.5 ni where nini is the intrinsic carrier concentration. Using mass action ( np=ni2np = ni^2 ), what is the electron concentration nn ?

a)

n equals (ni / 1.5)

b)

n equals (1.5×ni2)(1.5 × ni^2)

c)

n equals (1.5 × ni)

d)

n equals (ni2/1.5)(ni^2 / 1.5)

18.

If equal drift currents are carried by electrons and holes (Jn = Jp) under the same electric field, which relation between mobilities holds when p = 1.5 ni and n = (ni/1.5)?

a)

μn / μp = 1.00

b)

μn / μp = 2.25

c)

μn / μp = 0.67

d)

μn / μp = 1.50

19.

Thermal voltage VT is approximated as 20 mV at room temperature. Which expression correctly uses VT to relate ED − EF when the occupation ratio gives exp[(ED − EF)/kT] = 38?

a)

ED − EF = VT ln 38

b)

ED − EF = q VT 38

c)

ED − EF = 38 / VT

d)

ED − EF = VT / ln 38

20.

For an intrinsic semiconductor at absolute zero (T = 0 K), which statement is correct about band occupancy?

a)

All valence band states are empty, conduction band states are filled

b)

All valence band states are filled, conduction band states are empty

c)

Both valence and conduction band states are filled with electrons

d)

Both valence and conduction band states are filled with holes

21.

In a non-degenerate semiconductor at 300 K, the relation between electron concentration n, the conduction band edge Ec, and the electron quasi-Fermi level EFn is n=Ncexp[(EcEFn)/kT]n = N_c \exp[−(E_c − E_{Fn})/kT] . If Nc=1019 cm3N_c = 10^{19} \text{ cm}^{-3} and EcEFn=0.2 eVE_c − E_{Fn} = 0.2 \text{ eV} , what is n? Use kT0.026 eVkT \approx 0.026 \text{ eV} .

a)

1.9×10^16 cm−3

b)

1.0×10^15 cm−3

c)

3.7×1017cm33.7\times10^{17} cm^{-3}

d)

2.1×1015cm32.1\times10^{15} cm^{-3}

e)

9.6×10^18 cm−3

22.

For two non-degenerate samples at the same temperature with electron densities n1 and n2 and identical Nc, the difference (Ec − EF1) − (Ec − EF2) equals kT ln(n2/n1). If n2 = 0.5 n1 and kT = 26 meV, what is (Ec − EF1) − (Ec − EF2)?

a)

−26 meV

b)

−18 meV

c)

+18 meV

d)

+26 meV

e)

−45 meV

23.

The intrinsic Fermi level Ei in a semiconductor with effective density of states Nc and Nv is offset from midgap by Δ = (kT/2) ln(Nv/Nc). If Nv = 2Nc at 300 K and kT = 26 meV, what is |Δ|?

a)

32.00 meV

b)

26.90 meV

c)

18.02 meV

d)

13.45 meV

e)

9.01 meV

24.

Which statement best explains why Ei shifts toward the band with larger effective density of states?

a)

Larger DOS increases entropy near that band

b)

Larger DOS raises bandgap energy significantly

c)

Larger DOS reduces carrier lifetimes dramatically

d)

Larger DOS eliminates non-radiative recombination

e)

Larger DOS lowers temperature dependence entirely

25.

A silicon sample at 300 K has Nd = 5×1016cm35\times10^{16} cm^{-3} and is uniformly illuminated with optical generation rate Gopt = 1.5×1020cm3s11.5\times10^{20} cm^{-3} s^{-1} . Under low-level injection, what is the steady-state excess minority hole concentration Δp0 if τp0 = 0.1μs0.1 \mu s ?

a)

7.5×1014cm37.5\times10^{14} cm^{-3}

b)

1.5×10^12 cm−3

c)

1.5×10^13 cm−3

d)

7.5×1013cm37.5\times10^{13} cm^{-3}

e)

1.5×10^14 cm−3

26.

After the light is turned off at t = 0, the excess minority holes in the sample of the previous question decay as Δp(t) = Δp0et/τp0Δp0 e^{−t/τp0} . With Δp0Δp0 from steady state and τp0=0.1μsτp0 = 0.1 μs , what is Δpatt=0.3μsΔp at t = 0.3 μs ?

a)

7.46×1012cm37.46\times10^{12} cm^{-3}

b)

1.11×10^13 cm−3

c)

4.98×1012cm34.98\times10^{12} cm^{-3}

d)

1.50×10^13 cm−3

e)

3.33×1012cm33.33\times10^{12} cm^{-3}

27.

For n-type silicon with Nd ≫ ni and low-level injection, which approximation is most appropriate for the majority carrier concentration n0?

a)

n0 ≈ Δn = Δp

b)

n0 ≈ Nd (complete ionization)

c)

n0 ≈ ni (intrinsic level)

d)

n0 ≈ Ndni2NdΔpNd - \frac{ni^2}{Nd} - \Delta p

e)

n0 ≈ Nv (valence DOS)

28.

Given ni = 1010cm310^{10} cm^{-3} at 300 K, Nc = 1019cm310^{19} cm^{-3} , and n = 1016cm310^{16} cm^{-3} , compute Ec − EFn using Ec − EFn = kTln(Ncn)kT \ln(\frac{Nc}{n}) with kT=26meVkT = 26 meV .

a)

286 meV

b)

260 meV

c)

234 meV

d)

208 meV

e)

104 meV

29.

If Nv/Nc = 0.5 at 300 K, what is the direction of Ei shift relative to midgap and its magnitude? Use Δ = (kT/2) ln(Nv/Nc) with kT = 26 meV.

a)

No shift at any temperature

b)

Toward Ec by 13.45 meV

c)

Toward Ec by 9.01 meV

d)

Toward Ev by 9.01 meV

e)

Toward Ev by 13.45 meV

30.

A sample has τp0 = 0.1 μs and τn0 = 0.5 μs under low-level injection. Which plot of Δp(t) correctly represents the transient after the light is turned off at t = 0?

a)

Exponential decay with time constant 0.1 μs

b)

Exponential decay with time constant 0.5 μs

c)

Constant value equal to Δp0 forever

d)

Exponential rise with time constant 0.1 μs

e)

Linear decay to zero in 0.1 μs