Given: True HDG: 035°; TAS: 245 kts; Track: 046° (T); GS: 220 kts. Calculate the W/V.

The true course in the flight log is 270°, the forecast wind is 045° (T)/15 kts and the TAS is 120 kts. After 15 minutes of flying with the planned TAS and TH the aircraft is 3 NM south of the intended track and 2.5 NM ahead of the dead reckoning position. The track angle error (TKE) is:

An aircraft is flying from A to B. The true course according to the flight log is 090°, the estimated wind is 225° (T)/15 kts and the TAS is 120 kts. After 15 minutes of flying with the planned TAS and TH the aircraft is 3 NM south of the intended track and 2.5 NM ahead of the dead reckoning position. The track angle error (TKE) is:

After 15 minutes of flying with the planned TAS and TH the aircraft is 3 NM south of the intended track and 2.5 NM ahead of the dead reckoning position. To reach destination B from this position, the TH should be:

What is the average TAS climbing from 2,000 ft up to FL120 at standard temperatures, given a CAS 185 kts and QNH 1013?

What is the average TAS climbing from 1,500 ft up to FL180, given a temperature ISA +15 °C, a CAS 230 kts and QNH 1032?

An aircraft is following a true track of 048° at a constant TAS of 210 kt. The wind velocity is 350° / 30 kt. The GS and drift angle are:

Given: An aircraft is on final approach to runway 32R (322°). The wind velocity reported by the tower is 350°/20 kt; TAS on approach is 95 kt. In order to maintain the centre line, the aircraft's heading (°M) should be:

Given: TAS = 197 kt, True course = 240°, W/V = 180/30 kt. Descent is initiated at FL220 and completed at FL40. Distance to be covered during descent is 39 NM. What is the approximate rate of descent?

You are departing from an airport which has an elevation of 2000 ft. The QNH is 1013 hPa. 10 NM away there is a waypoint you are required to pass at an altitude of 7500 ft. Given a groundspeed of 100 kt, what is the minimum rate of climb?

An aircraft is departing from an airport which has an elevation of 2,000 ft and the QNH is 1003 hPa. The TAS is 100 kts, the head wind component is 20 kts and the rate of climb is 500 ft/min. Top of climb is FL050. At what distance from the airport will this be achieved?

During approach the following data are obtained: DME: 12.0 NM, altitude 3,000 ft; DME: 9.8 NM, altitude 2,400 ft; TAS: 160 kts; GS: 125 kts. The rate of descent is:

Given: ILS GP angle: 3.5°; GS: 150 kts. What is the approximate rate of descent?

You are required to descend from FL230 to FL50 over a distance of 32 NM in 7 minutes. What will the glideslope be when you expect a Wind Component (WC) of −25 kts during the descent?

A ground feature appears 30° to the left of the centre line of the CRT of an airborne weather radar. If the heading of the aircraft is 355° (M) and the magnetic variation is 15° East, the true bearing of the aircraft from the feature is:

Consider the following statements on sunset:

A map is conformal when:

Parallels of latitude, except the equator, are:

Consider the following statements on rhumb lines:

The shortest distance between two points on the surface of the Earth is:

The convergence of meridians:

You are flying from A (50°N 10°W) to B (58°N 02°E). What is the convergence between A and B?

The convergence factor of a Lambert conformal conic chart is quoted as 0,78535. At what latitude on the chart is Earth convergence correctly represented?

What is the value of the convergence factor on a Polar Stereographic chart?

What is the convergence at 50°00'N between the meridians 105°00'W and 145°00'W on the Earth?

Radio bearings:

Which one of the following, concerning great circles on a Direct Mercator chart, is correct?

Conversions angle is:

The great circle bearing of position B from position A in the Northern Hemisphere is 040°. If the conversion angle is 4°, what is the great circle bearing of A from B?

On a Lambert conformal chart the distance between two parallels of latitude (difference of latitude = 2°), is measured to be 112 mm. The distance between two meridians, spaced 2° longitude, according to the chart is 70 NM. The parallel of origin (selected parallel) runs through the middle of the described square. What is the convergence for a d-long of 15° on this map?

On a Lambert conformal chart the distance between two parallels of latitude (difference of latitude = 2°), is measured to be 112 mm. The distance between two meridians, spaced 2° longitude, according to the chart is 70 NM. The parallel of origin (selected parallel) runs through the middle of the described square. What is the convergence for a d-long of 15° on this map?

On a Mercator's projection the distance between (17°N, 035°E) and (17°N, 040°E) is 5 cm. The scale at 57°N is approximately:

On a direct Mercator projection, the distance measured between two meridians spaced 5° apart at latitude 60°N is 8 cm. The scale of this chart at latitude 60°N is approximately:

The polar Stereographic projection is:

Which map projection is described as follows: - Meridians are straight lines. - The scale vary with latitude. - Most rhumb lines are curved lines.

The chart that is generally used for navigation in polar areas is based on a:

The Polar Stereographic projection is:

On a polar stereographic map, a straight line is drawn from position A (70°N 102°W) to position B (80°N 006°E). The point of highest latitude along this line occurs at longitude 035°W. What is the initial straight-line track angle from A to B, measured at A?

A straight line from A (75°S, 120°E) to B (75°S, 160°E) is drawn on a Polar Stereographic chart. When passing the meridian 155°E, the True Track is:

Given: Direct Mercator chart with a scale of 1: 200 000 at the equator; chart length from A to B, in the vicinity of the equator, 11 cm. What is the approximate distance from A to B?

What is the chart distance between longitudes 179°E and 175°W on a direct Mercator chart with a scale of 1: 5 000 000 at the equator?

On a Lambert chart (standard parallels 37°N and 65°N), with respect to the straight line drawn on the map between A (49°N 030°W) and B (48°N 040°W), the:

The standard parallels of a Lambert's conical orthomorphic projection are 07°40'N and 38°20'N. The constant of the cone for this chart is:

The constant of the cone in a Lambert chart is 0,8666500. The angle between the north directions of the meridian in position A (65°00'N, 018°00'W) and the meridian of position B (75°00'N, 023°00'W) on the chart is:

A straight line from A (53°N, 155°W) to B (53°N, 170°E) is drawn on a Lambert Conformal conical chart with standard parallels at 50°N and 56°N. When passing the meridian 175°E, the True Track is:

A Lambert's conical conformal chart has standard parallels at 63°N and 41°N. What is the constant of the cone?

On a Lambert conformal chart, the distance between two parallels of latitude (difference of latitude = 2°) is measured to be 112 mm. The distance between two meridians, spaced 2° longitude, according to the chart is 70 NM. What is the latitude in the centre of the described square?

Which of the following lists all the aeronautical chart symbols shown at position N5150.4 W00829.7?

Which of the following lists all the aeronautical chart symbols shown at position N5318.1 W00856.5?