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Balanced Modulator (DSBSC)

Total questions: 20

Worksheet time: 10mins

Name
Class
Date
1.

In a balanced modulator for DSB‑SC generation, what is the primary purpose of the tuned load circuit at the output?

a)

To select the sum and difference sidebands only

b)

To convert the signal from analog to digital form

c)

To amplify the carrier frequency component strongly

d)

To suppress the message and pass only the carrier

2.

Two identical nonlinear devices in a balanced modulator are driven by vc±vm. If i1=a+bv1+cv1^2 and i2=a+bv2+cv2^2, which operation produces suppression of the carrier term at the output?

a)

Taking the difference current io=i1−i2

b)

Adding currents so that io=i1+i2

c)

Differentiating current with respect to time

d)

Filtering with a low‑pass RC network

3.

Given vc=Vc sin ωc t and vm=Vm sin ωm t, the difference current contains terms k1 sin ωm t + k2 cos(ωc−ωm)t + k2 cos(ωc+ωm)t. After proper tuning, which expression represents the DSB‑SC output current?

a)

k2 cos(ωc−ωm)t + k2 cos(ωc+ωm)t

b)

k1 sin ωm t + k2 cos ωc t

c)

k2 cos ωc t + k2 sin ωm t

d)

k1 sin ωc t + k1 sin ωm t

4.

In the ring modulator shown, what is applied to the center taps of both transformers to drive the diode switching?

a)

A triangular ramp waveform

b)

A constant DC bias voltage

c)

A sinusoidal message signal

d)

A square wave carrier signal

5.

During a large positive value of the square-wave drive w(t), which diode pair conducts and how are nodes connected?

a)

D1 and D4 conduct; A to D and B to C

b)

D1 and D2 conduct; A to C and B to D

c)

D3 and D4 conduct; A to C and B to D

d)

All diodes conduct; A to B and C to D

6.

Which statement best explains how the ring modulator generates a DSB-SC signal at the output of T2?

a)

It multiplies the message by a ±1 square wave

b)

It adds the carrier to the message directly

c)

It filters the message with a low-pass only

d)

It rectifies the message to remove negatives

7.

Which statement best defines demodulation in amplitude modulation?

a)

Filtering noise from a baseband audio signal

b)

Amplifying a carrier to increase transmission distance

c)

Combining two baseband signals into a carrier wave

d)

Recovering the original message from a modulated wave

8.

In a square law detector for AM, what is the primary role of the low-pass filter after the nonlinear device?

a)

Shift the message spectrum to higher frequencies

b)

Remove the high-frequency carrier components

c)

Increase the envelope amplitude for transmission

d)

Linearize the diode for ideal detection

9.

For a square law detector using a diode with characteristic i(t)=av+bv2i(t) = a v + b v^2 , which term after low-pass filtering is primarily responsible for recovering the message m(t)m(t) when the AM input is v=(VDC+m(t))cos(ωct)v = (V_{DC} + m(t)) cos(\omega_c t) ?

a)

the squared term b m(t)^2 high-frequency component

b)

the linear term a V_DC cos(ω_c t) component

c)

the squared term b V_DC m(t) baseband component

d)

the linear term a m(t) cos(ω_c t) component

e)

the squared term b V_DC^2 cos(2ω_c t) component

10.

When expanding v^2 = [(VDC+m(t))cos(ωct)]2[(V_DC + m(t)) cos(ω_c t)]^2 in a square law detector, which trigonometric identity allows separation into baseband and high-frequency terms?

a)

cos2(x)=1+cos(2x)2cos^2(x) = \frac{1 + cos(2x)}{2}

b)

tan2(x)=sec2(x)−1tan^2(x) = sec^2(x) - 1

c)

cos(2x) = 2 sin(x) cos(x)

d)

sin(2x)=2sin2(x)sin(2x) = 2 sin^2(x)

e)

sin2(x)=1−cos(2x)sin^2(x) = 1 - cos(2x)

11.

In an AM envelope detector, what happens during the positive half-cycle of the input when the diode conducts?

a)

The capacitor charges toward the input peak

b)

The capacitor discharges through the load resistor

c)

The diode remains reverse-biased and open

d)

The RC network blocks all carrier components

12.

Which statement best describes the role of the RC time constant in an envelope detector?

a)

RC must be smaller than the carrier period only

b)

RC must be larger than the message period

c)

RC must equal the carrier period exactly

d)

RC must be between carrier and message periods

13.

If RC is chosen too large in a peak detector, which outcome is most likely?

a)

Carrier components are fully removed always

b)

Output fails to follow fast envelope drops

c)

Output exhibits excessive ripple between peaks

d)

Diode remains forward-biased continuously

14.

To prevent diagonal clipping while minimizing ripple, which qualitative choice is appropriate for RC?

a)

Slightly less than 1/fc but greater than 1/fm

b)

Equal to the geometric mean of fc and fm

c)

Independent of both carrier and message rates

d)

Much greater than 1/fc yet much less than 1/fm

15.

In coherent AM demodulation, what condition must the local oscillator satisfy relative to the incoming carrier for correct detection?

a)

Same frequency but arbitrary phase offset

b)

Random phase with automatic gain control

c)

Slight frequency offset for envelope tracking

d)

Same frequency and in phase alignment

e)

Twice the carrier frequency with phase lock

16.

A receiver lacks a strong carrier component in its AM signal but still needs a coherent LO. Which block is best suited to regenerate a phase-synchronized LO from the input?

a)

Band-pass filter centered at carrier

b)

Phase-locked loop locked to carrier

c)

Low-pass filter for baseband extraction

d)

Automatic gain control amplifier

e)

Quadrature mixer with fixed clock

17.

In a synchronous AM demodulator with zero path delay, the local oscillator (LO) is best modeled as which signal?

a)

cos(ωc t)

b)

sin(ωc t + π/2)

c)

m(t) cos(ωc t)

d)

cos(2ωc t)

18.

Given an AM input of (V_DC + m(t)) cos(ωc t) multiplied by a synchronous LO cos(ωc t), what is Vx before filtering?

a)

(V_DC/2) cos(ωc t) + (m(t)/2) sin(2ωc t)

b)

(V_DC + m(t)) cos(2ωc t)

c)

V_DC + m(t) + cos(2ωc t)

d)

V_DC/2 + (V_DC/2) cos(2ωc t) + m(t)/2 + (m(t)/2) cos(2ωc t)

19.

If the LPF cut-off is approximately fc and Vx contains baseband and 2ωc terms, which output is expected at Vout?

a)

m(t) only with zero DC component

b)

V_DC/2 + m(t)/2

c)

V_DC + m(t)

d)

(V_DC/2) cos(2ωc t) + m(t)

20.

If there is a path delay τ so the LO becomes cos(ωc(t−τ)), which practical effect is most critical for coherent demodulation?

a)

It doubles the baseband bandwidth

b)

It removes the DC component entirely

c)

It introduces a phase offset relative to carrier

d)

It slightly boosts carrier amplitude