Graphing in POINT-SLOPE Form ~ HONORS

Front

Equation in point-slope form for line through (4, -7) with slope -1/4

Back

y + 7 = -1/4(x - 4)

Front

Equation in point-slope form for line through (-2, -1) with slope m = -3

Back

y + 1 = -3(x + 2)

Front

Equation in point-slope form for line through (-2, -1) with slope m = -3

Back

y + 1 = -3(x + 2)

Front

Equation of the line in Point-Slope Form through point (10,5) with slope -3

Back

y - 5 = -3(x - 10)

Front

Which of these represents point-slope form of a linear equation?

y - y₁ = m(x - x₁)

,

Ax + By = C

,

y = mx + b

Back

y - y₁ = m(x - x₁)

Front

Given y + 6 = 10( x - 9), what is the point used to write this equation? Options:

(10, 9)

,

(6, -9)

,

(-6, 9)

,

(9, -6)

Back

(9, -6)

Front

Equation of the line in point slope form with slope ⅔ and point (-4, 7)

Back

y - 7 = ⅔(x + 4)

Front

Given the graph, what is the equation of the line in point slope form?

Options: y - 20 = ½(x - 4), y - 20 = 5(x - 4), y + 20= 5(x + 4), y - 20 = 1(x - 4)

Back

y - 20 = 5(x - 4)

Front

Equation of the line y + 5 = -3(x - 6) in slope intercept form?

Back

y = -3x+13

Front

Equation of the line in slope-intercept form passing through (4, -7) with slope m = -1/4.

Back

y = -1/4x - 6