
Application Law of Sines and Cosines
Flashcard
•
Mathematics
•
11th Grade
•
Practice Problem
•
Hard
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the Law of Sines?
Back
The Law of Sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. It can be expressed as: a/sin(A) = b/sin(B) = c/sin(C).
2.
FLASHCARD QUESTION
Front
What is the Law of Cosines?
Back
The Law of Cosines relates the lengths of the sides of a triangle to the cosine of one of its angles. It is expressed as: c² = a² + b² - 2ab*cos(C).
3.
FLASHCARD QUESTION
Front
How do you find the area of a triangle using the Law of Sines?
Back
The area (A) of a triangle can be calculated using the formula: A = (1/2) * a * b * sin(C), where a and b are two sides and C is the included angle.
4.
FLASHCARD QUESTION
Front
Given a = 4, b = 5, and c = 8, find angle B using the Law of Sines.
Back
Angle B is approximately 30.8 degrees.
5.
FLASHCARD QUESTION
Front
How do you calculate the area of a triangle with sides a = 4, b = 5, and c = 8?
Back
The area is approximately 28.6 square units.
6.
FLASHCARD QUESTION
Front
What is the formula to find the length of a side using the Law of Cosines?
Back
The formula is: c = √(a² + b² - 2ab*cos(C)).
7.
FLASHCARD QUESTION
Front
If a surveyor walks 425 meters from point A to point B and then turns 65º to walk 300 meters to point C, how do you find the length AC?
Back
Use the Law of Cosines: AC = √(425² + 300² - 2*425*300*cos(65º)) which approximates to 615 meters.
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