Application Law of Sines and Cosines

Application Law of Sines and Cosines

Assessment

Flashcard

Mathematics

11th Grade

Hard

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the Law of Sines?

Back

The Law of Sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. It can be expressed as: a/sin(A) = b/sin(B) = c/sin(C).

2.

FLASHCARD QUESTION

Front

What is the Law of Cosines?

Back

The Law of Cosines relates the lengths of the sides of a triangle to the cosine of one of its angles. It is expressed as: c² = a² + b² - 2ab*cos(C).

3.

FLASHCARD QUESTION

Front

How do you find the area of a triangle using the Law of Sines?

Back

The area (A) of a triangle can be calculated using the formula: A = (1/2) * a * b * sin(C), where a and b are two sides and C is the included angle.

4.

FLASHCARD QUESTION

Front

Given a = 4, b = 5, and c = 8, find angle B using the Law of Sines.

Back

Angle B is approximately 30.8 degrees.

5.

FLASHCARD QUESTION

Front

How do you calculate the area of a triangle with sides a = 4, b = 5, and c = 8?

Back

The area is approximately 28.6 square units.

6.

FLASHCARD QUESTION

Front

What is the formula to find the length of a side using the Law of Cosines?

Back

The formula is: c = √(a² + b² - 2ab*cos(C)).

7.

FLASHCARD QUESTION

Front

If a surveyor walks 425 meters from point A to point B and then turns 65º to walk 300 meters to point C, how do you find the length AC?

Back

Use the Law of Cosines: AC = √(425² + 300² - 2*425*300*cos(65º)) which approximates to 615 meters.

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