Concave Mirrors Optics Flashcard
Flashcard
•
Physics
•
12th Grade
•
Practice Problem
•
Hard
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the mirror equation for a concave mirror?
Back
The mirror equation is \( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \), where \( f \) is the focal length, \( d_o \) is the object distance, and \( d_i \) is the image distance.
2.
FLASHCARD QUESTION
Front
If the object distance (d_o) is 30 cm and the image distance (d_i) is 10 cm in a concave mirror, what is the focal length?
Back
The focal length \( f \) can be calculated using the mirror equation: \( \frac{1}{f} = \frac{1}{30} + \frac{1}{10} \) which gives \( f = 7.5 \) cm.
3.
FLASHCARD QUESTION
Front
If an object is placed beyond the center of curvature of a concave mirror, where will the image be formed?
Back
The image will be formed between the focal point and the center of curvature.
4.
FLASHCARD QUESTION
Front
For a concave mirror, if an object is placed at the focal point, where is the image formed?
Back
The image is formed at infinity.
5.
FLASHCARD QUESTION
Front
What happens to the image distance (d_i) as the object distance (d_o) approaches the focal length from the outside in a concave mirror?
Back
As the object distance approaches the focal length, the image distance approaches infinity.
6.
FLASHCARD QUESTION
Front
Define focal length in the context of concave mirrors.
Back
Focal length is the distance from the mirror's surface to the focal point, where parallel rays of light converge.
7.
FLASHCARD QUESTION
Front
What is the significance of the center of curvature in concave mirrors?
Back
The center of curvature is the point where the radius of curvature intersects the mirror's surface; it is twice the focal length.
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