Conics- Circles

Conics- Circles

Assessment

Flashcard

Mathematics

10th - 12th Grade

Hard

CCSS
HSG.GPE.A.1, 7.G.A.3

Standards-aligned

Created by

Wayground Content

FREE Resource

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14 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the standard equation of a circle?

Back

The standard equation of a circle with center (h, k) and radius r is (x - h)² + (y - k)² = r².

Tags

CCSS.HSG.GPE.A.1

2.

FLASHCARD QUESTION

Front

What does the center of a circle represent in its equation?

Back

The center of a circle in the equation (x - h)² + (y - k)² = r² is the point (h, k) where the circle is centered.

Tags

CCSS.HSG.GPE.A.1

3.

FLASHCARD QUESTION

Front

How do you find the radius of a circle from its equation?

Back

The radius can be found by taking the square root of the constant on the right side of the equation in the standard form (x - h)² + (y - k)² = r².

Tags

CCSS.HSG.GPE.A.1

4.

FLASHCARD QUESTION

Front

What is the radius of the circle (x + 3)² + y² = 9?

Back

The radius is 3, since r² = 9, thus r = √9 = 3.

Tags

CCSS.HSG.GPE.A.1

5.

FLASHCARD QUESTION

Front

What is the center of the circle (x - 1)² + (y + 2)² = 16?

Back

The center is (1, -2).

Tags

CCSS.HSG.GPE.A.1

6.

FLASHCARD QUESTION

Front

What is the equation of a circle with center (0, 0) and radius 5?

Back

The equation is x² + y² = 25.

Tags

CCSS.HSG.GPE.A.1

7.

FLASHCARD QUESTION

Front

What is the distance between the centers of two circles with equations (x - 2)² + (y - 3)² = 4 and (x + 2)² + (y + 3)² = 9?

Back

The distance is √((2 - (-2))² + ((-3) - 3)²) = √(16 + 36) = √52 = 2√13.

Tags

CCSS.HSG.GPE.A.1

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