
G-6.6 FLASHCARD Area of Similar Figures
Flashcard
•
Mathematics
•
8th Grade
•
Practice Problem
•
Hard
+1
Standards-aligned
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the ratio of the areas of two similar figures if the ratio of their corresponding sides is 4:7?
Back
The ratio of the areas is the square of the ratio of the sides. Therefore, (4/7)² = 16/49.
2.
FLASHCARD QUESTION
Front
If the area of a smaller rectangle is 54 ft² and the ratio of the areas of two similar rectangles is 1:4, what is the area of the larger rectangle?
Back
The area of the larger rectangle is 4 * 54 ft² = 216 ft².
3.
FLASHCARD QUESTION
Front
Define similar figures in geometry.
Back
Similar figures are shapes that have the same shape but may differ in size. Their corresponding angles are equal, and the ratios of their corresponding sides are proportional.
Tags
CCSS.8.G.A.2
CCSS.HSG.CO.B.6
4.
FLASHCARD QUESTION
Front
What is the formula to find the area of a rectangle?
Back
Area = length × width.
Tags
CCSS.3.MD.C.7B
CCSS.4.MD.A.3
5.
FLASHCARD QUESTION
Front
If two similar pentagons have a side length ratio of 5:9, what is the ratio of their areas?
Back
The ratio of their areas is (5/9)² = 25/81.
6.
FLASHCARD QUESTION
Front
How do you find the ratio of the areas of two similar triangles?
Back
The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
7.
FLASHCARD QUESTION
Front
What is the area of a rectangle with a length of 12 ft and a width of 9 ft?
Back
Area = 12 ft × 9 ft = 108 ft².
Tags
CCSS.3.MD.C.7B
CCSS.4.MD.A.3
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