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G-6.6 FLASHCARD Area of Similar Figures

G-6.6 FLASHCARD Area of Similar Figures

Assessment

Flashcard

Mathematics

8th Grade

Practice Problem

Hard

CCSS
3.MD.C.7B, 8.G.A.2, HSG.CO.B.6

+1

Standards-aligned

Created by

Wayground Content

FREE Resource

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the ratio of the areas of two similar figures if the ratio of their corresponding sides is 4:7?

Back

The ratio of the areas is the square of the ratio of the sides. Therefore, (4/7)² = 16/49.

2.

FLASHCARD QUESTION

Front

If the area of a smaller rectangle is 54 ft² and the ratio of the areas of two similar rectangles is 1:4, what is the area of the larger rectangle?

Back

The area of the larger rectangle is 4 * 54 ft² = 216 ft².

3.

FLASHCARD QUESTION

Front

Define similar figures in geometry.

Back

Similar figures are shapes that have the same shape but may differ in size. Their corresponding angles are equal, and the ratios of their corresponding sides are proportional.

Tags

CCSS.8.G.A.2

CCSS.HSG.CO.B.6

4.

FLASHCARD QUESTION

Front

What is the formula to find the area of a rectangle?

Back

Area = length × width.

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

5.

FLASHCARD QUESTION

Front

If two similar pentagons have a side length ratio of 5:9, what is the ratio of their areas?

Back

The ratio of their areas is (5/9)² = 25/81.

6.

FLASHCARD QUESTION

Front

How do you find the ratio of the areas of two similar triangles?

Back

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

7.

FLASHCARD QUESTION

Front

What is the area of a rectangle with a length of 12 ft and a width of 9 ft?

Back

Area = 12 ft × 9 ft = 108 ft².

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

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