Unit 5 Retest

Unit 5 Retest

Assessment

Flashcard

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Wayground Content

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the sine ratio in a right triangle?

Back

The sine ratio is defined as the ratio of the length of the opposite side to the length of the hypotenuse. It is represented as: $$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$$.

2.

FLASHCARD QUESTION

Front

What is the cosine ratio in a right triangle?

Back

The cosine ratio is defined as the ratio of the length of the adjacent side to the length of the hypotenuse. It is represented as: $$\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}$$.

3.

FLASHCARD QUESTION

Front

What is the tangent ratio in a right triangle?

Back

The tangent ratio is defined as the ratio of the length of the opposite side to the length of the adjacent side. It is represented as: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$.

4.

FLASHCARD QUESTION

Front

How do you solve for x using the sine ratio?

Back

To solve for x using the sine ratio, rearrange the equation: $$\sin(\theta) = \frac{x}{\text{hypotenuse}}$$ to find $$x = \text{hypotenuse} \cdot \sin(\theta)$$.

5.

FLASHCARD QUESTION

Front

How do you solve for x using the cosine ratio?

Back

To solve for x using the cosine ratio, rearrange the equation: $$\cos(\theta) = \frac{x}{\text{hypotenuse}}$$ to find $$x = \text{hypotenuse} \cdot \cos(\theta)$$.

6.

FLASHCARD QUESTION

Front

How do you solve for x using the tangent ratio?

Back

To solve for x using the tangent ratio, rearrange the equation: $$\tan(\theta) = \frac{x}{\text{adjacent}}$$ to find $$x = \text{adjacent} \cdot \tan(\theta)$$.

7.

FLASHCARD QUESTION

Front

What is the Pythagorean theorem?

Back

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b): $$a^2 + b^2 = c^2$$.

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