What is the sine ratio in a right triangle?
Unit 5 Retest

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Mathematics
•
9th - 10th Grade
•
Hard
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1.
FLASHCARD QUESTION
Front
Back
The sine ratio is defined as the ratio of the length of the opposite side to the length of the hypotenuse. It is represented as: $$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$$.
2.
FLASHCARD QUESTION
Front
What is the cosine ratio in a right triangle?
Back
The cosine ratio is defined as the ratio of the length of the adjacent side to the length of the hypotenuse. It is represented as: $$\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}$$.
3.
FLASHCARD QUESTION
Front
What is the tangent ratio in a right triangle?
Back
The tangent ratio is defined as the ratio of the length of the opposite side to the length of the adjacent side. It is represented as: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$.
4.
FLASHCARD QUESTION
Front
How do you solve for x using the sine ratio?
Back
To solve for x using the sine ratio, rearrange the equation: $$\sin(\theta) = \frac{x}{\text{hypotenuse}}$$ to find $$x = \text{hypotenuse} \cdot \sin(\theta)$$.
5.
FLASHCARD QUESTION
Front
How do you solve for x using the cosine ratio?
Back
To solve for x using the cosine ratio, rearrange the equation: $$\cos(\theta) = \frac{x}{\text{hypotenuse}}$$ to find $$x = \text{hypotenuse} \cdot \cos(\theta)$$.
6.
FLASHCARD QUESTION
Front
How do you solve for x using the tangent ratio?
Back
To solve for x using the tangent ratio, rearrange the equation: $$\tan(\theta) = \frac{x}{\text{adjacent}}$$ to find $$x = \text{adjacent} \cdot \tan(\theta)$$.
7.
FLASHCARD QUESTION
Front
What is the Pythagorean theorem?
Back
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b): $$a^2 + b^2 = c^2$$.
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