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7.5A Exponential Equations

7.5A Exponential Equations

Assessment

Flashcard

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Hard

Created by

Wayground Content

FREE Resource

Student preview

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15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is an exponential equation?

Back

An exponential equation is an equation in which a variable appears in the exponent. For example, 2x=82^x = 8 .

2.

FLASHCARD QUESTION

Front

How do you solve the equation 34x=9x−73^{4x}=9^{x-7} ?

Back

Convert to the same base: 34x=(32)x−73^{4x} = (3^2)^{x-7} , which simplifies to 34x=32(x−7)3^{4x} = 3^{2(x-7)} . Set the exponents equal: 4x=2(x−7)4x = 2(x-7) . Solve for x to get x=−7x = -7 .

3.

FLASHCARD QUESTION

Front

What is the first step in solving −6e8x+8−3=−23-6e^{8x+8}-3=-23 ?

Back

Add 3 to both sides to isolate the exponential term: −6e8x+8=−20-6e^{8x+8} = -20 .

4.

FLASHCARD QUESTION

Front

How do you isolate e8x+8e^{8x+8} in the equation −6e8x+8=−20-6e^{8x+8} = -20 ?

Back

Divide both sides by -6: e8x+8=206=103e^{8x+8} = \frac{20}{6} = \frac{10}{3} .

5.

FLASHCARD QUESTION

Front

What is the natural logarithm property used to solve e8x+8=103e^{8x+8} = \frac{10}{3} ?

Back

Use the property if ey=a, then y=ln(a)\text{if } e^y = a, \text{ then } y = \text{ln}(a) . Thus, 8x+8=ln1038x + 8 = \text{ln}\frac{10}{3} .

6.

FLASHCARD QUESTION

Front

How do you solve for x in the equation 8x+8=ln1038x + 8 = \text{ln}\frac{10}{3} ?

Back

Subtract 8 from both sides: 8x=ln103−88x = \text{ln}\frac{10}{3} - 8 , then divide by 8: x=ln103−88x = \frac{\text{ln}\frac{10}{3} - 8}{8} .

7.

FLASHCARD QUESTION

Front

What is the solution to the equation −10e2−2x−6=−66-10e^{2-2x}-6=-66 ?

Back

Add 6 to both sides: −10e2−2x=−60-10e^{2-2x} = -60 , then divide by -10: e2−2x=6e^{2-2x} = 6 .

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