All the Relative Motion
Flashcard
•
Physics
•
11th Grade
•
Practice Problem
•
Hard
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15 questions
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1.
FLASHCARD QUESTION
Front
What is relative motion?
Back
Relative motion is the calculation of the motion of an object with respect to another object. It is essential in understanding how different observers can perceive the motion of the same object differently.
2.
FLASHCARD QUESTION
Front
Define frame of reference.
Back
A frame of reference is a set of coordinates or a viewpoint from which the position and motion of objects are measured. Different frames of reference can lead to different measurements of velocity.
3.
FLASHCARD QUESTION
Front
How do you calculate the resultant velocity of an object?
Back
To calculate the resultant velocity, use vector addition. Combine the velocities of the object and the medium (e.g., air or water) in which it is moving, taking into account their directions.
4.
FLASHCARD QUESTION
Front
What is the velocity of an object relative to the ground if it moves in the opposite direction of a moving train?
Back
If a passenger throws a ball in the opposite direction of a train moving at 15 m/s, the ball's velocity relative to the ground is the speed of the train minus the speed of the ball.
5.
FLASHCARD QUESTION
Front
Explain the concept of vector addition in relative motion.
Back
Vector addition involves combining two or more vectors to determine a resultant vector. In relative motion, this is used to find the overall velocity of an object when considering the motion of other objects.
6.
FLASHCARD QUESTION
Front
What is the significance of the observer's position in measuring velocity?
Back
The observer's position affects the measurement of velocity because different observers may be in different frames of reference, leading to different perceived speeds and directions.
7.
FLASHCARD QUESTION
Front
Calculate the speed of a boat crossing a river with a current.
Back
If a boat moves north at 10 km/h and the river flows east at 5 km/h, the boat's speed relative to the shore is calculated using the Pythagorean theorem: speed = √(10² + 5²) = 11.18 km/h.
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