
Distance on Coordinate Plane: Pythagorean Theorem
Flashcard
•
Mathematics
•
8th - 10th Grade
•
Practice Problem
•
Hard
Standards-aligned
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the Pythagorean Theorem?
Back
The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). It can be expressed as: c² = a² + b².
Tags
CCSS.8.G.B.8
2.
FLASHCARD QUESTION
Front
How do you find the distance between two points (x1, y1) and (x2, y2) on a coordinate plane?
Back
The distance d can be found using the formula: d = √((x2 - x1)² + (y2 - y1)²).
Tags
CCSS.HSG.GPE.B.7
3.
FLASHCARD QUESTION
Front
Calculate the distance between the points (3, 4) and (0, 0).
Back
Using the distance formula: d = √((3 - 0)² + (4 - 0)²) = √(9 + 16) = √25 = 5.
Tags
CCSS.HSG.GPE.B.7
4.
FLASHCARD QUESTION
Front
What is the distance between the points (-5, 5) and (1, -2)?
Back
Using the distance formula: d = √((1 - (-5))² + (-2 - 5)²) = √((1 + 5)² + (-7)²) = √(6² + 7²) = √(36 + 49) = √85 ≈ 9.2.
Tags
CCSS.HSG.GPE.B.7
5.
FLASHCARD QUESTION
Front
If point A is at (2, 3) and point B is at (2, 7), what is the distance between them?
Back
The distance is |7 - 3| = 4.
Tags
CCSS.HSG.GPE.B.7
6.
FLASHCARD QUESTION
Front
What is the distance between the points (1, 1) and (4, 5)?
Back
Using the distance formula: d = √((4 - 1)² + (5 - 1)²) = √(3² + 4²) = √(9 + 16) = √25 = 5.
Tags
CCSS.HSG.GPE.B.7
7.
FLASHCARD QUESTION
Front
Find the distance between points (0, 0) and (6, 8).
Back
Using the distance formula: d = √((6 - 0)² + (8 - 0)²) = √(6² + 8²) = √(36 + 64) = √100 = 10.
Tags
CCSS.HSG.GPE.B.7
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