Algebra 2 Final

The distance formula is given by: d = $$\text{sqrt}((x2 - x1)^2 + (y2 - y1)^2)$$ .

The exponential form is: $$2^5 = 32$$ .

The slope of a line perpendicular to this line is 5 (the negative reciprocal of -\frac{1}{5}).

Using the distance formula: d = $$\text{sqrt}((12 - 0)^2 + (1 - 10)^2) = 15$$ .

The point (2, 2) is a solution to the system.

A linear equation in slope-intercept form is expressed as: y = mx + b, where m is the slope and b is the y-intercept.

The slope (m) is calculated as: m = $$\frac{y2 - y1}{x2 - x1}$$ .

The midpoint M is given by: M = $$\left(\frac{x1 + x2}{2}, \frac{y1 + y2}{2}\right)$$ .

Two lines are parallel if they have the same slope and will never intersect.

The quadratic formula is: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ .