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Logarithms and Exponential Functions

Logarithms and Exponential Functions

Assessment

Presentation

Mathematics

12th Grade

Practice Problem

Medium

CCSS
HSF.BF.B.5

Standards-aligned

Created by

Maman Firmansyah

Used 133+ times

FREE Resource

9 Slides • 10 Questions

1

Logarithms and Exponential Functions

Logarithms

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2

Learning Objective

  • understand the relationship between logarithms and indices.

  • able to use the laws of logarithms to any base (excluding change of base)

3

Logarithms to base 10

  • also called as common logarithms

  •  y=10x      x=log10yy=10^x\ \ \ \leftrightarrow\ \ \ x=\log_{10}y  

  •  y=10x    x=logyy=10^x\ \ \ \leftrightarrow\ x=\log y  

4

Rules

  •  logx+logy=logxy\log x+\log y=\log xy  

  •  logxlogy=log xy\log x-\log y=\log\ \frac{x}{y}  

  •  logym=mlogy\log y^m=m\log y  

  •  logxy=logylogx\log_xy=\frac{\log y}{\log x}  

5

Examples

  •  log100=log102=2log10=2\log100=\log10^2=2\log10=2  

  •  log0.01=log102=2.log10=2\log0.01=\log10^{-2}=-2.\log10=-2  

  •  log2+log3log6=log(2.36)=log1=0\log2+\log3-\log6=\log\left(\frac{2.3}{6}\right)=\log1=0  

6

Multiple Choice

log 10(1/2) =

1

1/2

2

1/3

3

1

4

2

7

Multiple Choice

log √1000 =

1

1/2

2

3/2

3

5/2

4

2

8

Multiple Choice

log 100√10

1

1/2

2

3/2

3

5/2

4

2

9

Multiple Choice

log 1000 + log 0.1 - log 0.01 =

1

0

2

2

3

3

4

4

10

Multiple Choice

log 100 + log 0.1 =

1

100.1

2

3

3

2

4

1

11

Logarithms to base a

  • For  a1, a>0, y>0,a\ne1,\ a>0,\ y>0,   ax=y  x =logaya^x=y\ \leftrightarrow\ x\ =\log_ay  

  • All rules in common logarithms also applied in this logarithms

12

Additional rules

  •  loganbm =mnlogab\log_{a^n}b^m\ =\frac{m}{n}\log_ab  

  •  logab =logcblogca\log_ab\ =\frac{\log_cb}{\log_ca}  

  •  logab = 1logba\log_ab\ =\ \frac{1}{\log_ba}  

  •  alogab = ba^{\log_ab}\ =\ b  

13

Examples

  •  log39=log332=2\log_39=\log_33^2=2  

  •  log93=log3231 =12log33 = 12\log_93=\log_{3^2}3^1\ =\frac{1}{2}\log_33\ =\ \frac{1}{2}  

  •  log168 =log2423 =34log22 =34\log_{16}8\ =\log_{2^4}2^3\ =\frac{3}{4}\log_22\ =\frac{3}{4}  

  •  2log25 =52^{\log_25}\ =5  

  •  2log83 =2log233 =213log23 =2log2313 =132^{\log_83}\ =2^{\log_{2^3}3}\ =2^{\frac{1}{3}\log_23}\ =2^{\log_23^{\frac{1}{3}}}\ =\frac{1}{3}  

14

Multiple Choice

Question image

Solve the equation for x.

1

x = 27

2

x = 9

3

x = 3

4

x = 1

15

Multiple Choice

Evaluate: log93 = x

1

½ = x

2

-½ = x

3

2 = x

4

-2 = x

16

Multiple Choice

Evaluate log525 = x

1

x = 2

2

x = 5

3

x = 125

17

Multiple Choice

Write the following equation in logarithmic form:

35 = 243

1

log35 = 243

2

log2433 = 5

3

log5243 = 3

4

log3243 = 5

18

Multiple Choice

Rewrite the equation in exponential form:

log5125 = 3

1

1253 = 5

2

5125 = 3

3

53 = 125

4

35 = 125

19

The End

Thank you

Logarithms and Exponential Functions

Logarithms

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