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Standard form for conics

Standard form for conics

Assessment

Presentation

Mathematics

10th Grade - University

Practice Problem

Medium

CCSS
HSG.GPE.A.1

Standards-aligned

Created by

Amy Latsch

Used 37+ times

FREE Resource

7 Slides • 12 Questions

1

Standard form for conics

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2

Open Ended

Give me your best guess about how you can tell the difference between the equations of a circle and an ellipse.

3

Open Ended

Give me your best guess about how you can tell the difference between the equations of an ellipse and a hyperbola.

4

Open Ended

Give me your best guess about how you can tell an equation is a parabola.

5

Telling Conic Equations apart

  • Circles have both x2 and y2 and their coefficients are the same when equation is set = 0

  • Ellipses have both x2 and y2 and their coefficients are different, but have the same sign when equation is set = 0

  • Hyperbolas have both x2 and y2 and their coefficients have opposite signs when equation is set = 0

  • Parabolas have only one variable being squared

6

Multiple Choice

Which type of conic is:

137 + 6y = -3y2 - 3x2 + 24x

1

Circle

2

Ellipse

3

Hyperbola

4

Parabola

7

Multiple Choice

Which type of conic is:

137 + 6y = 3y2 - 3x2 + 24x

1

Circle

2

Ellipse

3

Hyperbola

4

Parabola

8

Multiple Choice

BE CAREFUL

Which type of conic is:

137 + 6y - 3y2 = - 3x2 + 24x

1

Circle

2

Ellipse

3

Hyperbola

4

Parabola

9

Multiple Choice

Which type of conic is:

137 + 6y = 3y2 + 6x2 + 24x

1

Circle

2

Ellipse

3

Hyperbola

4

Parabola

10

Multiple Choice

Which type of conic is:

137 + 6y = 3y2 + 24x

1

Circle

2

Ellipse

3

Hyperbola

4

Parabola

11

Multiple Choice

Question image

Which type of conic is:

1

Circle

2

Ellipse

3

Hyperbola

4

Parabola

12

How do we go from standard form to center form?

  • Put ALL the variables on 1 side and the constant on the other

  • Group like terms together

  • Factor any coefficients of the square terms forward

  • Do what we did with circles

13

Multiple Choice

Put

x2 + y2 - 6x + 8y - 11 = 0 into center form.

1

(x - 3)2 + (y + 4)2 = 11

2

(x - 3)2 + (y + 4)2 = -14

3

(x - 3)2 + (y + 4)2 = 36

4

(x - 3)2 + (y + 4)2 = 18

14

How'd you do it?

x2 + y2 - 6x + 8y - 11 = 0











15

Now we will do it with something a little different:

3x2 + y2 - 6x + 8y - 11 = 0

16

Now we will do it with something a little different:

y2 - 3x2 - 6x + 8y - 11 = 0

17

Now we will do it with something a little different:

3y2 - x + 12y - 11 = 0

18

Poll

Can you tell the difference between the equations?

Yes

No

Kinda

19

Poll

1 - Not at all

5 - Definitely got it

How's putting the equations into center form coming along? Be honest, we will do more!

1

2

3

4

5

Standard form for conics

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