
Motion_Graphs
Presentation
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Physics, Science
•
9th Grade
•
Hard
POCHANA RAJKUMAR
Used 13+ times
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18 Slides • 0 Questions
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Motion_Graphs
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1. Distance – Time Graph
It represents a change in position of the object with respect to time.
The graph in case the object is stationary (means the distance is constant at all time intervals) – Straight line graph parallel to x = axis
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The graph in case of uniform motion – Straight line graph
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The graph in case of non-uniform motion – Graph has different shapes
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2. Velocity – Time Graphs
Constant velocity – Straight line graph, velocity is always parallel to the x-axis
Uniform Velocity / Uniform Acceleration – Straight line graph
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Non-Uniform Velocity / Non-Uniform Acceleration – Graph can have different shapes
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Calculating Displacement from a Velocity-time Graph
The area under the graph gives the distance traveled between a certain interval of time. Hence, if we want to find out the distance traveled between time interval t1 and t2, we need to calculate the area enclosed by the rectangle ABCD where area (ABCD) = AB * AC.
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Similarly, to calculate distance traveled in a time interval in case of uniform acceleration, we need to find out the area under the graph, as shown in the figure below.
To calculate the distance between time intervals t1 and t2 we need to find out area represented by ABED.
Area of ABED = Area of the rectangle ABCD + Area of the triangle ADE = AB × BC + 1/ 2 * (AD × DE)
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Equations of Motion
The equations of motion represent the relationship between an object's acceleration, velocity and distance covered if and only if,
--> The object is moving on a straight path
--> The object has a uniform acceleration
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Three Equations of Motion
1. The Equation for Velocity – Time Relation
v = u + at
2. The Equation for Position – Time Relation
s = ut + 1/2 at2
3. The Equation for the Position – Velocity Relation
2a s = v2 – u2
Where,
u: initial velocity
a: uniform acceleration
t: time
v: final velocity
s: distance traveled in time t
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Deriving the Equations of Motion Graphically
The line segment PN shows the relation between velocity and time.
Initial velocity, u can be derived from velocity at point P or by the line segment OP
Final velocity, v can be derived from velocity at point N or by the line segment NR
Also, NQ = NR – PO = v – u
Time interval, t is represented by OR, where OR = PQ = MN
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1. Deriving the Equation for Velocity – Time Relation
Acceleration = Change in velocity / time taken
Acceleration = (final velocity – initial velocity) / time
a = (v – u)/t
so, at = v – u
v = u + at
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2. Deriving Equation for Position – Time Relation
We know that, distance travelled by an object = Area under the graph
So, Distance travelled = Area of OPNR = Area of rectangle OPQR + Area of triangle PQN
s = (OP * OR) + (PQ * QN) / 2
s = (u * t) + (t * (v – u) / 2)
s = ut + 1/2 at2 [because at = v – u]
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3. Deriving the Equation for Position – Velocity Relation
We know that, distance travelled by an object = area under the graph
So, s = Area of OPNR = (Sum of parallel sides * height) / 2
s = ((PO + NR)* PQ)/ 2
s = ( (v+u) * t)/ 2
2s / (v+u) = t [equation 1]
Also, we know that, (v – u)/ a = t [equation 2]
On equating equations 1 and 2, we get,
2s / (v + u) = (v – u)/ a
2as = (v + u) (v – u)
2 a s = v2 – u2
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Uniform Circular Motion
If an object moves in a constant velocity along a circular path, the change in velocity occurs due to the change in direction. Therefore, this is an accelerated motion. Consider the figure given below and observe how directions of an object vary at different locations on a circular path.
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Uniform Circular Motion :
When an object travels in a circular path at a uniform speed the object is said to have a uniform circular motion.
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Non-Uniform Circular Motion :
When an object travels in a circular path at a non-uniform speed the object is said to have a non-uniform circular motion
Examples of uniform circular motion:
-> The motion of a satellite in its orbit
-> The motion of planets around the sun
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Velocity of Uniform Circular Motion
Velocity = Distance/ Time
Velocity = Circumference of circle / Time
v = 2πr/ t
where,
v: velocity of the object
r: radius of the circular path
t: time taken by the object
Motion_Graphs
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