

Bepaalde integralen: toepassingen
Presentation
•
Mathematics
•
1st - 3rd Grade
•
Practice Problem
•
Hard
Eva Meskens
Used 2+ times
FREE Resource
2 Slides • 12 Questions
1
Bepaalde integralen: toepassingen

2
Multiple Choice
Wat is een primitieve van de gegeven functie f: f(x) =0
F(x) = 1
F(x) = x
F(x)=x1
F(x)=x
3
Multiple Choice
Wat is een primitieve van de gegeven functie f: f(x)=x1
F(x)=ln a1ax
F(x) = ex
F(x)=ln x
F(x)=ln ∣x∣
4
Multiple Choice
2.1. Op ontdekking:
∫01 (f(x)−g(x))dx =∫01(x2−x)dx
∫10(x−x2)dx
∫01(x−x2)dx
5
Multiple Choice
Op ontdekking:
∫01(x−x2)dx =(31x3−21x2)01
(31x2−21x3)01
(21x2−31x3)10
(21x2−31x3)01
6
Multiple Choice
Bewijs p. 28: Groene opp. - rode opp. = ∫abf(x)dx − ∫abg(x)dx wegens
Integratieregel lineariteit (regel 2)
Integratieregel additiviteit/optelbaarheid (regel 1)
Hoofdstelling 2
Meetkundige betekenis van de bepaalde integraal
7
Multiple Choice
Modelvoorbeeld p. 29:
Opp. I =
∫ab(g(x)−f(x))dx
∫ab(h(x)−f(x))dx
∫ab(f(x)−h(x))dx
∫ab(h(x)−g(x))dx
8
Multiple Choice
Modelvoorbeeld p. 29:
Opp. II =
∫ab(g(x)−f(x))dx
∫ab(h(x)−f(x))dx
∫ab(f(x)−h(x))dx
∫ab(h(x)−g(x))dx
9
Multiple Choice
Modelvoorbeeld p. 28:
Wat is a?
4
3
2
1
10
Multiple Choice
De oppervlakte ingesloten door de functies f, g en h =
13/6
13/9
7/6
19/6
11
Multiple Choice
Modelvoorbeeld 2 p. 30: Opp =
∫12(l(y)−k(y))dx
∫12(l(y)−k(y))dy
∫21(l(y)−k(y))dy
∫12(k(y)−l(y))dy
12
Multiple Choice
Modelvoorbeeld 2 p. 30: Opp = ∫12(l(y)−k(y))dy =
∫12(6 −y −y2)dy
∫12(6 −y −y2)dx
∫12(6 −y +y2)dy
∫21(6 −y −y2)dy
13
Multiple Choice
De oppervlakte ingesloten door de functies l en k =
13/6
13/9
7/6
19/6
14
Oefeningen
nr. 1 p. 42: a, b, c
nr. 2 p. 43: a, b, c (Tip: teken de grafieken in geogebra)
Extra: nr. 3 p. 43
Bepaalde integralen: toepassingen

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