
Lesson: Pythagorean Theorem (Part 1 - Exponents)
Presentation
•
Mathematics
•
7th - 9th Grade
•
Practice Problem
•
Medium
+2
Standards-aligned
Christopher Gassler
Used 19+ times
FREE Resource
8 Slides • 9 Questions
1
Categorize
2
Pythagorean Theorem Introduction
Objective: Find the missing side in right triangles using the Pythagorean Theorem.
3
Multiple Choice
35 means....?
3 × 3 × 3 × 3 × 3
5 × 5 × 5
3 × 5
4
REVIEW Understanding Exponents
12 (means 1×1) = 1
22 (means 2×2)= 4
32 (means 3×3)= 9
42 (means 4×4)= 16
52 (means 5×5)= 25
62 (means 6×6)= 36
72 (means 7×7)= 49
82 (means 8×8)= 64
92 (means 9×9)= 81
5
Math Response
33 = ?
6
Numbers in blue are PERFECT SQUARES
12 = 1
22 = 4
32 = 9
42 = 16
52 = 25
62 = 36
72 = 49
82 = 64
92 = 81
7
PERFECT SQUARES are numbers that when you take the square root the answer is a number (not a decimal)
√4 = 2
√9 = 3
√16 = 4
√25 = 5
√36 = 6
√49 = 7
...and so on
8
Math Response
81=??
9
NON-PERFECT SQUARES are numbers that when you take the square root the answer is a decimal
√10 = 3.16227766....(this keeps going forever)
√34 = 5.820951895...
In this situation, we are going to round to the nearest tenth.
(next slide)
10
ROUNDING to the nearest tenth
√10 = 3.16227766....
(look at the number to the right)
√10 = 3.16227766....
(below 5 - number stays the same)
(5 or above - number goes up one)
6 is above 5 - the 1 becomes a 2
√10 ≈ 3.2
11
ROUNDING to the nearest tenth
√34 = 5.820951895...
(look at the number to the right)
√34 = 5.820951895...
(below 5 - number stays the same)
(5 or above - number goes up one)
2 is below 5 - the 8 stay an 8
√34 ≈ 5.8
12
Math Response
Round √166 to the nearest tenth
13
Solving Equations with Square Roots
Solve: x2 = 25
Solve: x2 = 26
14
Math Response
Solve: x2 = 121 (if necessary round the answer to the nearest tenth)
15
Math Response
Solve: x2 = 39 (if necessary round the answer to the nearest tenth)
16
Math Response
Solve: x2 = 98 (if necessary round the answer to the nearest tenth)
17
Open Ended
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