

Chain rules, tangent, and Normal
Presentation
•
Mathematics
•
10th - 12th Grade
•
Medium
ujang irpan
Used 4+ times
FREE Resource
6 Slides • 13 Questions
1
Chain rules, tangent, and Normal
Mr. U_Ir

2
Open Ended
Full name
3
Remember how to differentiate
Ready to the action?
4
Multiple Choice
Find the derivative of 3x7−x3+3x−1
3x7−x3+3x−1
21x6−3x2+3x−1
21x6−3x2+3
21x7−3x3+3x−1
5
Multiple Choice
Find the derivative of x71
−7x61
7x61
−x87
x87
6
Multiple Choice
Find the derivative of x4
x2
−x32
x32
−x2
7
Chain rules
Prepare your note
8
Multiple Choice
Find the derivative of y=(2x2−1)5
y′=5(2x2−1)4
y′=5(4x−1)4
y′=20x(2x2−1)4
y′=20x(4x−1)4
9
Multiple Choice
Find the gradient of tangent to curve y=(3x2−2)51 at the point where x=1
−5
−6
1
−30
10
Tangent line
The gradient of tangent is the derivative of the curve
11
Multiple Choice
Find the point of tangency of tangent line to curve y=(3x2−2)51 at the point where x=1
(1,1)
(1,−1)
(−1,1)
(−1,−1)
12
Multiple Choice
Find the equation of tangent line to curve y=(3x2−2)51 at the point where x=1
y−1=−60(x−1)
y−1=60(x−1)
y+1=−60(x−1)
y+1=60(x−1)
13
Multiple Choice
Find the equation of tangent to the curve y=2x2+x28−9 at the point where x = 2.
y=6x−11
y=6x+11
y=−6x−11
y=−6x+11
14
Normal line
The line which perpendicular to the tangent line
15
Multiple Choice
Find the gradient of normal to curve y=(3x2−2)51 at the point where x=1
301
30
−301
−30
16
Multiple Choice
Find the equation of normal line to curve y=(3x2−2)51 at the point where x=1
y−1=−601(x−1)
y−1=601(x−1)
y+1=−601(x−1)
y+1=601(x−1)
17
Multiple Choice
Find the equation of normal to the curve y=2x2+x28−9 at the point where x = 2.
x+6y=−8
x+6y=8
6x+y=−8
6x+y=8
18
Poll
Is this lesson method helpful for you?
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19
Mr. U_Ir
Chain rules, tangent, and Normal
Mr. U_Ir

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