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Area of Shapes

Area of Shapes

Assessment

Presentation

Mathematics

6th - 7th Grade

Practice Problem

Hard

CCSS
6.G.A.1, 3.MD.C.7B, 7.G.B.6

+1

Standards-aligned

Created by

Dakota Farmer

Used 47+ times

FREE Resource

18 Slides • 10 Questions

1

Area of Shapes

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2

What is Area?

  • Area is the size of the flat surface

  • It is measure in units squared, or units2

3

4

Rectangles

5

Area of a Rectangle

  • Use the formula: A=bh

  • b = length of the base

  • h = height of the rectangle

6

7

Example 1: Find the area

  •  A = bhA\ =\ bh  

  • b = 8.6

  • h = 3

  •  A = 8.6(3)A\ =\ 8.6\left(3\right)  

  •  A = 25.8 cm2A\ =\ 25.8\ cm^2  

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8

Example 2: Find Area

  • A = bh

  •  b = 2 14b\ =\ 2\ \frac{1}{4}  

  •  h = 1 12h\ =\ 1\ \frac{1}{2}  

  •  A = 2 14 (1 12)A\ =\ 2\ \frac{1}{4}\ \left(1\ \frac{1}{2}\right)  

  •  A = 3 38 ft2A\ =\ 3\ \frac{3}{8}\ ft^2  

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9

Fill in the Blank

Two walls of a room are being painted. Each wall measures 16 ft by 8 1/2 ft.


How many square feet will be painted?

10

Writing Formulas

  • Formulas can be manipulated to solve for missing information.

  • EX: A = bh can be manipulated

  • Divide the h to the other side:  b = Ahb\ =\ \frac{A}{h} 

  • Divide the b to the other side:  h = Abh\ =\ \frac{A}{b} 

11

Example 3: The area of the rectangle is 162 m2

  • We know A and H, but not B.

  • Use:  b = Ahb\ =\ \frac{A}{h}  

  •  b = 16218b\ =\ \frac{162}{18}  

  •  b=9mb=9m  

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12

Multiple Select

Check all of the formulas below that could be used to find the height of a rectangle with a base of 11 in and an area of 120 in2

1

120 = 11(11)120\ =\ 11\left(11\right)

2

120 = 11(h)120\ =\ 11\left(h\right)

3

11 = 120(h)11\ =\ 120\left(h\right)

4

h = 12011h\ =\ \frac{120}{11}

5

h = 11120h\ =\ \frac{11}{120}

13

Fill in the Blank

A rectangular canvas covers 225 in2 on a wall. If the canvas has a height of 18 in, then what is the base?

A = b*h

14

Area of Parallelograms

  • The dimensions of a parallelogram are also referred to as the base and height.

  • Use the formula A=bh.

  • B is the length of the base.

  • H is the height of the parallelogram, which makes a 90-degree angle with the base.

  • H is the perpendicular height.

15

Example 4: Find area

  •  A=bhA=bh  

  • b = 12.2cm

  • h = 8cm, as it is perpendicular to the base.

  •  A = 12.2(8)A\ =\ 12.2\left(8\right)  

  •  A=97.6cm2A=97.6cm^2  

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16

Fill in the Blank

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Find the area of the following rectangle.

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Open Ended

Describe how the area of a rectangle and the area of a parallelogram with the same dimensions are related.

Think on the formulas.

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Triangles

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Area of Triangles

  • Two triangles are formed when a parallelogram is cut in half

  • Therefore, the formula for the area of a triangle is:  A = bh2A\ =\ \frac{bh}{2}  

  • The height of the triangle will form a right angle with the base. It is the perpendicular height.

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21

Multiple Select

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Check all statements that are correct.

1

b=14

2

h=14

3

b=16

4

h=16

5

A=112 in2

22

Fill in the Blank

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Find the area.


 A = bh2A\ =\ \frac{bh}{2}  

23

Fill in the Blank

What is the area of a right triangle with a height of 8.9cm and a base of 14.3 cm?

24

Trapezoids

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Area of Trapezoids

  • A trapezoid is one or two triangles and a rectangle combined.

  • Use the formula:  A=b1 + b22  hA=\frac{b_1\ +\ b_2}{2}\ \cdot\ h  

  • b1 is the length of the 1st base

  • b2 is the length of the 2nd base

  • h is the perpendicular height of the trapezoid.

26

Example 5: Find area

  • Formula:  A = b1+b22  hA\ =\ \frac{b_1+b_2}{2}\ \cdot\ h  

  • b1=12 ; b2=7 ; h=4

  •  A=12+724A=\frac{12+7}{2}\cdot4  

  •  A=1924A=\frac{19}{2}\cdot4  

  •  A=762A=\frac{76}{2}  

  •  A=38in2A=38in^2  

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27

Multiple Choice

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Find the area of the regular trapezoid.

1

108 in2

2

60 in2

3

27 in2

4

54 in2

28

Fill in the Blank

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Find the area of the trapezoid by breaking it into a rectangle and a triangle.
All information needed is provided.
Area Rectangle: A=bh ; Area of Triangle:  A = bh2A\ =\ \frac{bh}{2}  

Area of Shapes

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