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Fundamental Theorem of Algebra

Fundamental Theorem of Algebra

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
HSN.CN.C.9, HSF-IF.C.7C, HSA.APR.B.2

+1

Standards-aligned

Created by

Toyin Olaye

Used 22+ times

FREE Resource

22 Slides • 19 Questions

1

Fundamental Theorem of Algebra

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8

Multiple Choice

The degree of the polynomial determines the number of roots.
1
True
2
False

9

Multiple Choice

How many solutions does the polynomial f(x)=3x4 + 5x2 - 6x have?
1
4
2
2
3
3
4
5

10

Multiple Choice

What is the total number of roots for the following equation?
y = 4x6 - 12x5 - x4 + 2x3 - 6x2 - 5x + 10
1
4
2
5
3
6
4
7

11

Multiple Choice

Question image
Use the Fundamental Theorem of Algebra to state the number of zeros/solutions/roots of the polynomial. 
1
A
2
B
3
C
4
D

12

Multiple Choice

Question image
Use the Fundamental Theorem of Algebra to state the number of zeros/solutions/roots of the polynomial. 
1
A
2
B
3
C
4
D

13

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16

Multiple Choice

All imaginary roots comes in pairs.
1
True
2
False

17

Multiple Choice

We Do:

A Polynomial of Degree 6 CAN have the following number of imaginary roots:

1

1

2

4

3

3

4

8

18

Multiple Choice

We Do:

A Polynomial of Degree 6 has 4 real roots, how many roots are imaginary roots?

1

2

2

4

3

3

4

8

19

Multiple Choice

You Do:

A Polynomial of Degree 9 CAN have the following number of imaginary roots:

1

1

2

10

3

3

4

8

20

Multiple Choice

You Do:

A Polynomial of Degree 9 has 5 real roots, how many roots are imaginary roots?

1

2

2

4

3

3

4

8

21

Multiple Choice

You Do: (Trick Question)

A Polynomial of Degree 3 has 2 real roots, how many roots are imaginary roots?

1

2

2

3

3

1

4

Not possible

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28

Multiple Choice

We Do:

Write x = -3 in its factored form

1

(x - 3)

2

(x + 3)

3

(3x + 1)

4

(3x - 1)

29

Multiple Choice

We Do:
 x=12x=\frac{1}{2} in factored form: 

1

(2x + 1)

2

(1x + 2)

3

(2x - 1)

4

(2x - 2)

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36

Multiple Choice

We Do:

Below are four possible zeros for this polynomial.

Figure out which one "works"

f(x) = x3 + 2x2 - 11x - 12

1

-3

2

-4

3

1

4

6

37

Multiple Choice

You Do:

Below are four possible zeros for this polynomial.

Figure out which one "works"

f(x) = x3 + 2x2 - 11x - 12

1

-3

2

-4

3

1

4

6

38

Multiple Choice

We Do:

What are the three factors for

(x3 +7x2 +7x -15) ÷ (x -1)?

1

(x-1) (x+5) (x-3)

2

(x-1) (x+5) (x + 3)

3

(x+1) (x+5) (x-3)

4

(x+1) (x-5) (x-3)

39

Multiple Choice

You Do:

What are the three factors for

(x3 -3x2 -4x +12) ÷ (x + 2)?

1

(x-2) (x+2) (x+3)

2

(x-2) (x-2) (x+3)

3

(x+2) (x+2) (x+3)

4

(x-2) (x+2) (x-3)

40

Multiple Choice

We Do:

What are the zeros of the polynomial?

g(x) = 2x4 + 23x3 +19x2 - 116x - 60

1

2,-3,-10,1/2

2

2, 3,-10,-1/2

3

2,-3,-10,-1/2

4

-2,-3,10,-1/2

41

Multiple Choice

You Do:

What are the zeros of the polynomial?

h(x) = x4 + 3x3 - 55x2 - 99x +630

1

-5,6,-3,7

2

5 6, 3, -7

3

-5, 6, 3, -7

4

6, 3, -7

Fundamental Theorem of Algebra

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