
Sketching Higher Order Polynomials
Presentation
•
Mathematics
•
10th - 11th Grade
•
Medium
Standards-aligned
Jennifer Rodriguez
Used 86+ times
FREE Resource
11 Slides • 28 Questions
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Think Quadratics
Concave up vs. Concave down
Think Linear
Positive slope vs. Negative slope
Summary of End Behaviors
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Multiple Choice
Does the graph show an EVEN or ODD degree polynomial?
EVEN degree
ODD degree
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Multiple Choice
Does the graph have a POSITIVE or NEGATIVE leading coefficient?
POSITIVE
NEGATIVE
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Multiple Choice
Does the graph show an EVEN or ODD degree polynomial?
EVEN degree
ODD degree
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Multiple Choice
Does the graph have a POSITIVE or NEGATIVE leading coefficient?
POSITIVE
NEGATIVE
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Multiple Choice
Does the graph show an EVEN or ODD degree polynomial?
EVEN degree
ODD degree
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Multiple Choice
Does the graph have a POSITIVE or NEGATIVE leading coefficient?
POSITIVE
NEGATIVE
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Multiple Select
Which functions' graph would have a decreasing left end behavior and increasing right end behavior?
NOTE: There may be more than one correct answer.
f(x)=2x3+4x2+6x+3
g(x)=−8x3+2x2+4x
h(x)=−4x2+6x3+x+2
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Multiple Choice
Which of the function's graph would have a INCREASING left end behavior and INCREASING right end behavior?
f(x)=−4x2+6x+3
g(x)=8x3+2x2+4x
h(x)=2x4+6x3+x+2
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Multiple Choice
Which graphs would have a NEGATIVE leading coefficient?
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Open Ended
What do you notice/wonder about the cubic functions and their graphs? How are they similar? How are they different?
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Multiplicity
A zero has MULTIPLICITY.
Multiplicity is the number of times the zero's associated factor appears in the polynomials.
You can determine if the graph will bounce or cross the x-axis from the multiplicity
If the multiplicity is odd, the graph will cross at that zero
If the multiplicity is even, the graph will bounce at that zero
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Theorem: Turning Points
If f is a polynomial function of degree n, then the graph of f has at most n-1 turning points.
If the graph of a polynomial function f has n-1 turning points, the the degree of f is a least n.
The graph on the right has 3 turning points so that means the degree of the function is at least 4.
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Multiple Select
Select all the zeros (with multiplicities) of
f(x)=(x+2)(x−1)2
x= -2 multiplicity 2
x= 2 multiplicity 1
x= -2 multiplicity 1
x= -1 multiplicity 2
x= 1 multiplicity 2
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Multiple Select
f(x)=(x+2)(x−1)2
From the last question, we know that f(x) has zeros at
x= -2 multiplicity 1 and x= 1 multiplicity 2.
Select whether the graph of f(x) will cross or bounce at each of the zeros.
cross at x= -2
bounce at x= -2
cross at x=1
bounce at x=1
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Multiple Choice
Which of the following is the graph of
f(x)=(x+2)(x−1)2 ?
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Multiple Select
Select all the zeros (with multiplicities) of
g(x)=−2x2(x+4)2
x= -4 multiplicity 2
x= 4 multiplicity 2
x= 0 multiplicity 2
x= 2 multiplicity 2
x= -2 multiplicity 2
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Multiple Select
g(x)=−2x2(x+4)2
From the last question, we know that g(x) has zeros at
x= 0 multiplicity 2 and x= -4 multiplicity 2.
Select whether the graph of g(x) will cross or bounce at each of the zeros.
cross at x= 0
bounce at x= 0
cross at x= -4
bounce at x= -4
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Multiple Choice
Which of the following is the graph of
g(x)=−2x2(x+4)2 ?
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Multiple Select
x=0 multiplicity of 1 is a zero of h(x).
Select all other zeros (with multiplicities) of
h(x)=x(x−7)2(x+5)2
x= -7 multiplicity 2
x= 7 multiplicity 2
x= -5 multiplicity 2
x= 5 multiplicity 2
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Multiple Choice
h(x)=x(x−7)2(x+5)2
From the last question, we know that h(x) has zeros at
x= 0 multiplicity 1, x= 7 multiplicity 2, and x= -5 multiplicity 2
Select the graph of h(x).
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Multiple Select
Select all other zeros (with multiplicities) of
k(x)=−(x+1)2(x+4)
x= 0 multiplicity 1
x= -1 multiplicity 2
x= 1 multiplicity 2
x= -4 multiplicity 1
x=4 multiplicity 1
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Multiple Choice
k(x)=−(x+1)2(x+4)
From the last question, we know that k(x) has zeros at
x= -1 multiplicity 2, and x= -4 multiplicity 1
Select the graph of h(x).
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Multiple Select
Select ALL the possible factors in the equation of the graph.
(x−2)
(x+1)
(x−1)2
(x+1)2
(x+2)
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Writing Polynomial Functions
Use smallest degree possible
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Open Ended
Which of these doesn't belong? Explain your choice.
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