Day 2 of Solutions

Day 2 of Solutions

I can explain how to prepare a solution of known concentration.

Multiple Choice

The ___ is the thing being dissolved

• solute
• solvent

Multiple Choice

Molarity is measured in

• moles per kg

• mols per L

• moles per kJ

• moles per mL

Multiple Choice

Which sweet tea would you expect to taste the sweetest?

• 1M
• 3M
• 3.1M
• 2.5M

Multiple Choice

What is the molarity of 4 g of NaCl (MM=58.45) in 3,800 mL of solution?

• 0.018 M
• 0.0011 M
• 1.052 M
• 0.062 M

Multiple Choice

How many liters would you need to make a 1 M solution if you have 6 mol of Sodium Hydroxide? 

• 2
• 3
• 4
• 6 

Multiple Choice

How many moles are needed to make 2.5 L of a 3.8 M solution? 

• 9.5 mol
• 0.66 mol
• 1.5 mol
• 15 mol

Multiple Choice

When you make a dilution, which of these values remains constant?

• The molarity (M)

• The total moles of solute

• The volume (V)

• The concentration

Multiple Choice

As we dilute a solution.....

• The volume increases and the molarity (M) increases

• The volume increases and the molarity (M) decreases

• The volume decreases and the molarity (M) increases

• The volume decreases and the molarity (M) decreases

Multiple Choice

How many mL of stock solution of 2M NaCl do you need to prepare 100 mL of 0.150M NaCl?

• 7.5 mL

• 15 mL

• 1333 mL

• 200 mL

Multiple Choice

If I have 340 mL of a 0.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it?

• .188 M

• 3.78 M

• .389 M

• 1.76 M

Multiple Choice

How do we compute for percentage by volume?

• volume of solute divided by volume of solution then multiply by one hundred percent

• volume of solution divided by volume of solute then multiply by one hundred percent

• add volume of solute and solvent then multiply by one hundred percent

• multiply volume of solute and solvent then divide by one hundred percent

Fill in the Blanks

What is the percent by volume of a solution formed by added 8 L of acetone to 8 L of water?

Multiple Choice

How do we compute for percent by mass?

Multiple Choice

What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

Based on the given problem what is the amount of solute?

• 5g iron(II) sulfate

• 75g water

• 80g solution

• 6.25%

Multiple Choice

What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

Based on the given problem what is the amount of solution?

• 5g iron(II) sulfate

• 75g water

• 80g solution

• 6.25%