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Logarithm Functions

Logarithm Functions

Assessment

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•

Mathematics

•

10th - 12th Grade

•

Medium

Created by

Bronwyn Long

Used 12+ times

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11 Slides • 7 Questions

1

Logarithm Functions

Unit 1 Methods

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2

Warm-ups

What do we know?

3

Multiple Choice

Simplify: a2b(2ab2)3÷ab16a0\frac{a^2b}{\left(2ab^2\right)^3}\div\frac{ab}{16a^0}  

1

 2a2b6\frac{2}{a^2b^6}  

2

 2a2b6\frac{2a^2}{b^6}  

3

 2a2b62a^2b^6  

4

 1128ab5\frac{1}{128ab^5}  

4

Multiple Choice

The function f: R→R, f(x)=3×2x−1f:\ R\rightarrow R,\ f\left(x\right)=3\times2^x-1  has the range:

1

 RR  

2

 RR  \ {1}\left\{1\right\}  

3

 (−1, ∞)\left(-1,\ \infty\right)  

4

 (1, ∞)\left(1,\ \infty\right)  

5

[ 1,∞1,\infty  )

5

Multiple Choice

Which of the following graphs could be the graph of the function f(x)=2ax+bf\left(x\right)=2^{ax}+b  


1
2
3
4
5

6

Multiple Choice

Express  log⁡104+2log⁡103−log⁡106\log_{10}4+2\log_{10}3-\log_{10}6  as a single logarithm

1

 log⁡104\log_{10}4  

2

 log⁡105\log_{10}5  

3

 log⁡10−6\log_{10}-6  

4

 log⁡106\log_{10}6  

7

Multiple Choice

 ax=ba^x=b  and  log⁡ab=x\log_ab=x  are equivalent

1

True

2

False

8

13G Graphs of Logarithm Functions

Unit 1 Methods

9

Graph of y=log⁡axy=\log_ax  when a>1

What do you notice about the graph of  y=2xy=2x  and  y=log⁡2xy=\log_2x  ?

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10

The graph of y=log⁡2xy=\log_2x  is the reflection of the graph  y=2xy=2^x   in the line  y=xy=x  

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11

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12

Multiple Choice

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What is the domain and range of the following:

1

R, R

2

R+, R

3

R-, R

13

Multiple Choice

What is the inverse of the following  f(x)=2xf\left(x\right)=2^x ?

1

 g(x)=log⁡2xg\left(x\right)=\log_2x  

2

 g(x)=log⁡2yg\left(x\right)=\log_2y  

14

We know that a graph with a negative exponent (or a base 0<a<1) is a decay.

Logarithms for these functions are also a decay reflected over the y=x.

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15

13F Using logarithms to solve equations

16

Consider the equation  2x=112^x=11  

We could rewrite this as:
 log⁡102x=log⁡1011\log_{10}2^x=\log_{10}11  
so:
 x=log⁡1011log⁡102x=\frac{\log_{10}11}{\log_{10}2}  
but from the original equation  2x=112^x=11  , so
 log⁡211=log⁡1011log⁡102\log_211=\frac{\log_{10}11}{\log_{10}2}  

17

 log⁡bc=log⁡aclog⁡ab\log_bc=\frac{\log_ac}{\log_ab}  

18

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Logarithm Functions

Unit 1 Methods

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